Problem 21
Question
Graph each rational function. $$ f(x)=\frac{x}{x-3} $$
Step-by-Step Solution
Verified Answer
The graph of \( f(x) = \frac{x}{x-3} \) has a vertical asymptote at \( x = 3 \) and a horizontal asymptote at \( y = 1 \).
1Step 1: Identify the Function's Domain
To find the domain of the function \( f(x) = \frac{x}{x-3} \), we need to identify any values of \( x \) that make the denominator zero, as division by zero is undefined. Setting the denominator equal to zero, we have \( x - 3 = 0 \). Solving this, we find \( x = 3 \). Thus, the domain of the function is all real numbers except \( x = 3 \).
2Step 2: Locate Vertical Asymptotes
Vertical asymptotes occur where the denominator of the rational function becomes zero and the numerator does not cancel it out. For \( f(x) = \frac{x}{x-3} \), the vertical asymptote is at \( x = 3 \), as this is where the denominator becomes zero.
3Step 3: Determine Horizontal Asymptotes
To find the horizontal asymptote, compare the degrees of the numerator and the denominator. Since both the numerator \( x \) and the denominator \( x-3 \) are of degree 1, the horizontal asymptote is found by dividing the leading coefficients: \( \frac{1}{1} = 1 \). Thus, the horizontal asymptote is \( y = 1 \).
4Step 4: Sketch the Function
Begin by plotting the vertical asymptote (a dashed line) at \( x = 3 \) and the horizontal asymptote \( y = 1 \). Choose sample points, such as \( x = 0 \), \( x = 1 \), and \( x = 4 \), to calculate \( f(x) \) and get corresponding points. \( f(0) = 0 \), \( f(1) = \frac{1}{-2} \), and \( f(4) = 4 \). Connect these points, ensuring the curve approaches the asymptotes as it extends towards infinity.
Key Concepts
Vertical AsymptotesHorizontal AsymptotesFunction Domain
Vertical Asymptotes
A vertical asymptote of a rational function occurs at a value of \( x \) where the denominator is zero but the numerator is not. This results in the function approaching infinity, creating a line that the graph gets infinitely closer to but never actually touches. In the given function \( f(x) = \frac{x}{x-3} \), the vertical asymptote is located at \( x = 3 \).
This is because if we set the denominator \( x-3 = 0 \), we solve to get \( x = 3 \). It is important to note that this line is not part of the function's graph, it is rather a boundary where the function behavior changes dramatically.
This is because if we set the denominator \( x-3 = 0 \), we solve to get \( x = 3 \). It is important to note that this line is not part of the function's graph, it is rather a boundary where the function behavior changes dramatically.
- Remember, a vertical asymptote will never be crossed by the graph of a rational function.
- This is because the function is undefined at this point, causing a gap in the graph.
Horizontal Asymptotes
Horizontal asymptotes of a rational function give us an idea of the end behavior of the graph. These occur when the output value \( y \) approaches a specific number as \( x \) tends towards either positive or negative infinity. For \( f(x) = \frac{x}{x-3} \), we find the horizontal asymptote by comparing the degrees of the numerator and the denominator.
Both the numerator \( x \) and the denominator \( x-3 \) are degree 1 polynomials. Thus, we simply take the leading coefficients' ratio, yielding \( \frac{1}{1} = 1 \). This means the horizontal asymptote is \( y = 1 \).
Both the numerator \( x \) and the denominator \( x-3 \) are degree 1 polynomials. Thus, we simply take the leading coefficients' ratio, yielding \( \frac{1}{1} = 1 \). This means the horizontal asymptote is \( y = 1 \).
- It is possible for a graph to cross a horizontal asymptote.
- The asymptote merely dictates the direction the graph heads as it stretches into infinity.
Function Domain
The domain of a function is the set of all possible \( x \) values that can be input into the function without causing mathematical inconsistencies. For a rational function such as \( f(x) = \frac{x}{x-3} \), determining the domain involves identifying values of \( x \) that make the denominator equal zero, as this creates an undefined expression.
By setting \( x-3 = 0 \), we find that \( x = 3 \) would cause such an issue.
By setting \( x-3 = 0 \), we find that \( x = 3 \) would cause such an issue.
- Every value except \( x = 3 \) can be used in the function, which defines its domain as all real numbers except that value.
- Knowing the domain is essential in graphing as it tells us where the function is not applicable.
Other exercises in this chapter
Problem 21
State whether each equation represents a direct, joint, or inverse variation. Then name the constant of variation. \(\frac{2.5}{t}=s\)
View solution Problem 21
Find the LCM of each set of polynomials. $$ x^{2}-y^{2}, x^{3}+x^{2} y $$
View solution Problem 21
Simplify each expression. \(\frac{9-t^{2}}{t^{2}+t-12}\)
View solution Problem 22
NUMBER THEORY The ratio of 16 more than a number to 12 less than that number is 1 to 3 . What is the number?
View solution