Problem 21
Question
For the following problems, perform the divisions. $$ \frac{20 x^{2}+10 x}{5 x} $$
Step-by-Step Solution
Verified Answer
Answer: The simplified form of the expression is $$2(2x + 1)$$.
1Step 1: Factor out common terms
In this step, we will factor out any common terms in the numerator and denominator of the given expression.
$$
\frac{20x^2 + 10x}{5x} = \frac{10x(2x + 1)}{5x}
$$
2Step 2: Cancel common factors
Next, we will cancel any common factors in the numerator and the denominator to simplify the expression.
$$
\frac{10x(2x+1)}{5x} = \frac{2(2x+1)}{1}
$$
The simplified expression is:
$$
2(2x + 1)
$$
Key Concepts
Factoring PolynomialsCanceling Common FactorsAlgebraic Division
Factoring Polynomials
Factoring polynomials is like breaking down a number into its prime factors, except here we break down expressions into simpler, multiplicative components. It's a critical step in simplifying algebraic expressions because it reveals common factors that might be present. To factor, you look for the greatest common factor (GCF) which is the largest expression that divides all terms in the polynomial.
For the expression \(20x^2 + 10x\), the GCF is \(10x\). When we factor \(10x\) out of each term, we get \(10x(2x + 1)\). This makes it easier to see the similarities between the numerator and the denominator, setting us up for the next step of simplification by canceling common factors.
For the expression \(20x^2 + 10x\), the GCF is \(10x\). When we factor \(10x\) out of each term, we get \(10x(2x + 1)\). This makes it easier to see the similarities between the numerator and the denominator, setting us up for the next step of simplification by canceling common factors.
Canceling Common Factors
Canceling common factors between the numerator and denominator is a crucial simplification tactic in algebra. It's like reducing a fraction to its lowest terms. After factoring polynomials, we often find the same term on top and bottom of a fraction, and these can be divided out.
In our example, after factoring out the GCF, the resulting fraction is \(\frac{10x(2x+1)}{5x}\). Here, the common factor \(5x\) can be canceled out from the numerator and the denominator, as if we are dividing both by \(5x\), leaving us with \(2(2x + 1)\), which is the simplified form of the original expression. This step is crucial because it simplifies the expression to a form that's easier to work with in subsequent calculations.
In our example, after factoring out the GCF, the resulting fraction is \(\frac{10x(2x+1)}{5x}\). Here, the common factor \(5x\) can be canceled out from the numerator and the denominator, as if we are dividing both by \(5x\), leaving us with \(2(2x + 1)\), which is the simplified form of the original expression. This step is crucial because it simplifies the expression to a form that's easier to work with in subsequent calculations.
Algebraic Division
Algebraic division is the process we use to simplify expressions or solve equations that involve dividing polynomials. It operates on the same basic principles as arithmetic division: if you divide something by itself, you get one, and if a term is present in both the numerator and denominator, it can potentially be divided out.
When we applied algebraic division to our example, after canceling the common factor \(10x\), we're left with \(\frac{10x(2x+1)}{5x} = \frac{2(2x+1)}{1}\) simply because whatever you divide by itself equals one. This simplification could also be seen as dividing each term in the numerator by the denominator, which is another way to undertake algebraic division. The end result is a simpler expression that no longer has the denominator term, making it ready for further analysis or simply presenting the final simplified version of the original problem.
When we applied algebraic division to our example, after canceling the common factor \(10x\), we're left with \(\frac{10x(2x+1)}{5x} = \frac{2(2x+1)}{1}\) simply because whatever you divide by itself equals one. This simplification could also be seen as dividing each term in the numerator by the denominator, which is another way to undertake algebraic division. The end result is a simpler expression that no longer has the denominator term, making it ready for further analysis or simply presenting the final simplified version of the original problem.
Other exercises in this chapter
Problem 20
For the following problems, reduce each rational expression to lowest terms. $$ \frac{(a+6)(a-5)}{(a-5)(a+2)} $$
View solution Problem 21
The width of a rectangle is 1 foot longer than one half the length. Find the dimensions (lengh and width) of the rectangle if the perimeter is 44 feet.
View solution Problem 21
An inlet pipe can fill a tank in 5 hours. An outlet pipe can empty the tank in 4 hours. If both pipes are open, can the tank be filled? Explain.
View solution Problem 21
Simplify each complex rational expression. $$ \frac{4-\frac{1}{m^{2}}}{2+\frac{1}{m}} $$
View solution