Problem 21
Question
For the following exercises, write an explicit formula for each sequence. $$ 4,7,12,19,28, \ldots $$
Step-by-Step Solution
Verified Answer
The explicit formula is \( a_n = n^2 + 3 \).
1Step 1: Identify the Pattern
Examine the differences between consecutive terms in the sequence: \( 7 - 4 = 3 \), \( 12 - 7 = 5 \), \( 19 - 12 = 7 \), and \( 28 - 19 = 9 \). Notice that the differences increase by 2 each time.
2Step 2: Recognize the Pattern Type
The pattern of increasing differences indicates a quadratic sequence, which can be expressed in the form \( a_n = an^2 + bn + c \).
3Step 3: Set Up Equations for Initial Terms
Use the first few terms to set up equations: \( a_1 = 4 \), \( a_2 = 7 \), \( a_3 = 12 \). Substitute these into the quadratic formula to form equations:1. \( a(1)^2 + b(1) + c = 4 \)2. \( a(2)^2 + b(2) + c = 7 \)3. \( a(3)^2 + b(3) + c = 12 \).
4Step 4: Solve the System of Equations
Simplify each equation:1. \( a + b + c = 4 \)2. \( 4a + 2b + c = 7 \)3. \( 9a + 3b + c = 12 \).Subtract equation (1) from (2) and (3) to find \( a \) and \( b \). Then solve for \( c \):- Subtract (1) from (2): \( 3a + b = 3 \)- Subtract (2) from (3): \( 5a + b = 5 \).Subtract these results to find \( a \):- \( 5a + b - (3a + b) = 5 - 3 \)- \( 2a = 2 \) which implies \( a = 1 \).Substitute \( a = 1 \) into \( 3a + b = 3 \):- \( 3(1) + b = 3\)- \( b = 0 \).Now solve for \( c \) using equation (1) again with known values for \( a \) and \( b \):- \( 1 + 0 + c = 4 \)- \( c = 3 \).
5Step 5: Write the Explicit Formula
With the values found, the explicit formula for the sequence is \( a_n = n^2 + 3 \).
Key Concepts
Explicit FormulaPattern RecognitionSystem of Equations
Explicit Formula
When exploring any sequence, one of the key objectives is to find a concise mathematical expression that captures the pattern of that sequence. This expression is known as the explicit formula. An explicit formula provides a direct method to calculate the nth term of the sequence, making it significantly easier than computing each term through recursive steps.
For quadratic sequences, which involve terms that fit a specific parabolic distribution, the pattern can be captured using a formula of the form:
Once you have determined the constants \( a \), \( b \), and \( c \), you can express any term in the sequence with a simple calculation. This is the beauty and utility of the explicit formula—it turns a complex and potentially endless sequence into something manageable and predictable.
For quadratic sequences, which involve terms that fit a specific parabolic distribution, the pattern can be captured using a formula of the form:
- \( a_n = an^2 + bn + c \)
Once you have determined the constants \( a \), \( b \), and \( c \), you can express any term in the sequence with a simple calculation. This is the beauty and utility of the explicit formula—it turns a complex and potentially endless sequence into something manageable and predictable.
Pattern Recognition
Recognizing the underlying structure or pattern is essential when working with sequences. In the case of quadratic sequences, the differences between consecutive terms don't remain constant but instead increase in a regular pattern.
Initially, you might calculate the first-level differences, which don't yield a steady sequence, indicating the sequence is not linear. Therefore, you’ll need to look at the second-level differences, revealing a uniform pattern.
For example:
This skill of pattern recognition is invaluable across many aspects of mathematics, enabling you to simplify and solve many types of problems, especially those involving complex sequences.
Initially, you might calculate the first-level differences, which don't yield a steady sequence, indicating the sequence is not linear. Therefore, you’ll need to look at the second-level differences, revealing a uniform pattern.
For example:
- The differences are calculated as \(3, 5, 7, 9 \)... with each value showing a consistent increase of +2.
This skill of pattern recognition is invaluable across many aspects of mathematics, enabling you to simplify and solve many types of problems, especially those involving complex sequences.
System of Equations
To find the explicit formula's constants in a quadratic sequence, after identifying the pattern, you need to solve a system of equations. This method involves using a few initial terms of the sequence and substituting them into the quadratic formula.
You start by equating these terms to the general formula \( a_n = an^2 + bn + c \), forming a series of equations:
You start by equating these terms to the general formula \( a_n = an^2 + bn + c \), forming a series of equations:
- \( a(1)^2 + b(1) + c = 4 \)
- \( a(2)^2 + b(2) + c = 7 \)
- \( a(3)^2 + b(3) + c = 12 \)
- Subtract equations to eliminate variables and simplify.
- Find each constant, enabling you to compile the final explicit formula.
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Problem 21
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