Problem 21
Question
For the following exercises, find the domain of each function using interval notation. \(\frac{2 x+1}{\sqrt{5-x}}\)
Step-by-Step Solution
Verified Answer
The domain of the function is \((-\infty, 5)\).
1Step 1: Identify Constraints
To find the domain of the function \( \frac{2x+1}{\sqrt{5-x}} \), we first find any restrictions on \( x \). Since the denominator involves a square root, the expression under the square root, \( 5-x \), must be greater than zero.
2Step 2: Solve Inequality
We solve the inequality \( 5 - x > 0 \). Rearranging this, we get \( x < 5 \). This tells us \( x \) must be less than 5 for the function to be defined.
3Step 3: Determine Domain Using Interval Notation
Since the only restriction is \( x < 5 \), the domain of the function in interval notation is \( (-\infty, 5) \).
Key Concepts
Interval NotationInequality SolvingRestrictions on Variables
Interval Notation
Interval notation is a concise way to express the set of all possible input values, or domain, for which a function is defined. It uses brackets and parentheses to describe the domain range. In the exercise, the domain is expressed as \((-\infty, 5)\).
Here, the round parenthesis \(()\) means that 5 is not included in the domain. This is because the function \(\frac{2x+1}{\sqrt{5-x}}\) cannot have 5 as a value for \(x\) due to its restriction. If you see a square bracket \([]\), it includes the endpoint in the domain.
Here's a quick guide for understanding interval notation:
Here, the round parenthesis \(()\) means that 5 is not included in the domain. This is because the function \(\frac{2x+1}{\sqrt{5-x}}\) cannot have 5 as a value for \(x\) due to its restriction. If you see a square bracket \([]\), it includes the endpoint in the domain.
Here's a quick guide for understanding interval notation:
- \((a, b)\): All numbers between \(a\) and \(b\), but not including \(a\) and \(b\).
- \([a, b]\): All numbers between \(a\) and \(b\), including \(a\) and \(b\).
- Use \(-\infty\) or \(\infty\) when the domain is unbounded in one direction.
- \((-\infty, a)\): All numbers less than \(a\).
- \([a, \infty)\): All numbers greater than or equal to \(a\).
Inequality Solving
Inequality solving is crucial in finding the domain of functions, especially where restrictions are due to square roots or fractions. Here, our focus is on solving the inequality from the given function \(\frac{2x+1}{\sqrt{5-x}}\).
Let's break down how to solve the inequality \(5-x > 0\):
Practicing inequality solving improves your ability to find these restrictions quickly and confidently. This process is foundational in determining the domain of many functions.
Let's break down how to solve the inequality \(5-x > 0\):
- First, move \(x\) to the other side: \(5 > x\).
- This can also be written as \(x < 5\).
- This inequality shows the values \(x\) can take before making the denominator zero or negative, which are not allowed since the square root is involved.
Practicing inequality solving improves your ability to find these restrictions quickly and confidently. This process is foundational in determining the domain of many functions.
Restrictions on Variables
Understanding restrictions on variables is crucial for correctly determining a function's domain. Such restrictions ensure the function operates correctly without running into undefined operations or errors.
For the function \(\frac{2x+1}{\sqrt{5-x}}\), the restrictions arise from the square root in the denominator. Consider these key restrictions:
Recognizing such constraints and their impacts is vital to maintain consistency within your computations, prevent errors, and allow for accurate function analysis.
For the function \(\frac{2x+1}{\sqrt{5-x}}\), the restrictions arise from the square root in the denominator. Consider these key restrictions:
- Values under the square root must always be greater than zero (for real numbers).
- This prevents \(x = 5\) because it causes \(5-x\) to become zero, leading to a division by zero.
- If \(x > 5\), the expression under the square root becomes negative, and the square root of a negative number is not real.
Recognizing such constraints and their impacts is vital to maintain consistency within your computations, prevent errors, and allow for accurate function analysis.
Other exercises in this chapter
Problem 21
For the following exercises, graph the given functions by hand. \(y=-|x|-2\)
View solution Problem 21
For the following exercises, determine the interval(s) on which the function is increasing and decreasing. \(g(x)=5(x+3)^{2}-2\)
View solution Problem 21
For the following exercises, determine whether the relation represents \(y\) as a function of \(x\). \(y=x^{3}\)
View solution Problem 22
For the following exercises, use a graphing utility to determine whether each function is one-to-one. \(f(x)=x^{3}-27\)
View solution