Problem 21
Question
For Problems \(13-26\), compute \(A B\) and \(B A\). $$ A=\left[\begin{array}{rr} 2 & -1 \\ -5 & 3 \end{array}\right], \quad B=\left[\begin{array}{ll} 3 & 1 \\ 5 & 2 \end{array}\right] $$
Step-by-Step Solution
Verified Answer
Both \(AB\) and \(BA\) equal the identity matrix \(\begin{bmatrix} 1 & 0 \\ 0 & 1 \end{bmatrix}\).
1Step 1: Understand Matrix Multiplication
Matrix multiplication involves taking the dot product of rows and columns. For matrices \(A\) and \(B\), the element in the first row and first column of the product matrix is the dot product of the first row of \(A\) and the first column of \(B\).
2Step 2: Compute \(A \times B\)
To multiply matrix \(A\) by matrix \(B\), perform the following calculations:1. First row, first column: \(2 \times 3 + (-1) \times 5 = 6 - 5 = 1\).2. First row, second column: \(2 \times 1 + (-1) \times 2 = 2 - 2 = 0\).3. Second row, first column: \((-5) \times 3 + 3 \times 5 = -15 + 15 = 0\).4. Second row, second column: \((-5) \times 1 + 3 \times 2 = -5 + 6 = 1\).So, \(A \times B = \begin{bmatrix} 1 & 0 \ 0 & 1 \end{bmatrix}\).
3Step 3: Compute \(B \times A\)
To multiply matrix \(B\) by matrix \(A\), perform the following calculations:1. First row, first column: \(3 \times 2 + 1 \times (-5) = 6 - 5 = 1\).2. First row, second column: \(3 \times (-1) + 1 \times 3 = -3 + 3 = 0\).3. Second row, first column: \(5 \times 2 + 2 \times (-5) = 10 - 10 = 0\).4. Second row, second column: \(5 \times (-1) + 2 \times 3 = -5 + 6 = 1\).So, \(B \times A = \begin{bmatrix} 1 & 0 \ 0 & 1 \end{bmatrix}\).
4Step 4: Verify Results
Both products \( A B \) and \( B A \) resulted in the identity matrix \( \begin{bmatrix} 1 & 0 \ 0 & 1 \end{bmatrix} \), confirming our calculations were performed correctly.
Key Concepts
Dot ProductIdentity MatrixMatrix Operations
Dot Product
In the realm of matrix multiplication, the "dot product" is an essential concept to grasp. To compute the dot product of two matrices, you focus on the rows of the first matrix and the columns of the second matrix. The calculation involves multiplying corresponding elements and then summing those products. For example, if you have the first row of matrix A and the first column of matrix B, the dot product involves:
- Multiplying each element in the row of A with the corresponding element in the column of B.
- Adding up all these results to get a single number.
Identity Matrix
The identity matrix can be thought of as the "1" in the world of matrices. It's a special matrix where all the elements on the main diagonal are 1, and all other elements are 0. Think of it like this: multiplying any matrix by the identity matrix leaves it unchanged, just like multiplying a number by 1.In our exercise, compute matrices \(AB\) and \(BA\), both results turn out to be the identity matrix \(\begin{bmatrix} 1 & 0 \ 0 & 1 \end{bmatrix}\). This surprising result is important because it confirms a unique relationship between the matrices A and B.
- Each diagonal element \(1\) ensures the existence of each row or column distinctly.
- Each off-diagonal element \(0\) means no interaction between other entries during multiplication.
Matrix Operations
Matrix operations, including multiplication, involve calculating new matrices by combining two old ones. In contrast to simple arithmetic multiplication, matrix multiplication considers the structure of matrices—rows and columns—leading to a new matrix size.Here are some key rules:
- Matricies A (size \(m \times n\)) and B (size \(p \times q\)) can only be multiplied if the number of columns in A equals the number of rows in B, i.e., \(n = p\).
- The resulting matrix will have dimensions \(m \times q\).
Other exercises in this chapter
Problem 20
For Problems \(1-24\), indicate the solution set for each system of inequalities by graphing the system and shading the appropriate region. $$ \left(\begin{arra
View solution Problem 21
For Problems \(19-26\), compute \(A B\). $$ A=\left[\begin{array}{rr} -3 & -4 \\ 2 & 1 \end{array}\right], \quad B=\left[\begin{array}{r} 4 \\ -3 \end{array}\ri
View solution Problem 21
For Problems \(1-24\), indicate the solution set for each system of inequalities by graphing the system and shading the appropriate region. $$ \left(\begin{arra
View solution Problem 22
For Problems 21-36, use the technique discussed in this section to find the multiplicative inverse (if one exists) of each matrix. $$ \left[\begin{array}{rr} 1
View solution