Problem 21
Question
For exercises \(5-48\), simplify. $$ \frac{w^{2}}{w+8}-\frac{64}{w+8} $$
Step-by-Step Solution
Verified Answer
The simplified form is \(w - 8\).
1Step 1: Identify the common denominator
Both terms in the expression have the same denominator, which is \(w + 8\).
2Step 2: Combine the numerators
Since the denominators are already the same, we can combine the numerators: \(w^2 - 64 \). This gives us: \[\frac{w^{2} - 64}{w + 8}\].
3Step 3: Factor the numerator
The numerator \(w^2 - 64\) is a difference of squares, which can be factored into \((w - 8)(w + 8)\). Therefore, we get: \[\frac{(w - 8)(w + 8)}{w + 8}\].
4Step 4: Cancel out the common factor
The factor \(w + 8\) in the numerator and denominator can be canceled out, leaving us with: \w - 8\. Thus, the simplified form is: \[w - 8\].
Key Concepts
Common DenominatorDifference of SquaresFactoringCanceling Common Factors
Common Denominator
A common denominator is a shared multiple of the denominators of two or more fractions. In our exercise, both terms have the same denominator, which is \(w + 8\). This makes it easier to simplify the expression. If the denominators were different, we would have to find a common denominator before combining the terms.
Difference of Squares
The difference of squares is a special algebraic pattern where two perfect squares are subtracted. This pattern is represented as \(a^2 - b^2 = (a - b)(a + b)\). In our problem, we identified the numerator \(w^2 - 64\) as a difference of squares. Here, \(w^2\) is \(a^2\) and \(64\) is \(b^2\). Therefore, we can factor \(w^2 - 64\) as \( (w - 8)(w + 8)\). This step is crucial for further simplification.
Factoring
Factoring is the process of breaking down an expression into simpler 'factors' that, when multiplied together, give the original expression. In the exercise, we factored the numerator \(w^2 - 64\) into \( (w - 8)(w + 8)\). This step helps to make the expression easier to work with and sets up the next steps in the simplification process.
Canceling Common Factors
Canceling common factors is a simplification step where we eliminate identical factors in the numerator and denominator. In our exercise, the factor \(w + 8\) appears in both the numerator and denominator. By canceling this common factor, we simplify the expression \(\frac{(w - 8)(w + 8)}{w + 8}\) to \(w - 8\). This leaves us with a much simpler expression, making it easier to understand and use in further calculations.
Other exercises in this chapter
Problem 21
For exercises \(9-24\), evaluate or simplify. $$ \frac{\frac{v^{2}-5 v+4}{v^{2}-6 v+8}}{\frac{v^{2}+2 v-3}{v^{2}+v-6}} $$
View solution Problem 21
For exercises 13-24, rewrite each expression as an equivalent expression with the given denominator. $$ \frac{2 p}{p^{2}-36} ;(p+6)(p-6)(p+1) $$
View solution Problem 21
For exercises 1-66, simplify. $$ \frac{5}{5 x^{2}+10 x} $$
View solution Problem 22
If the force acting on an object is constant, the relationship of the mass of the object, \(x\), and the acceleration of the object, \(y\), is an inverse variat
View solution