Problem 21
Question
Find the Jacobian for the transformation from rectangular coordinates to spherical coordinates.
Step-by-Step Solution
Verified Answer
The Jacobian for the transformation is \(\rho^2 \sin \phi\).
1Step 1: Understand the Relationship between Coordinate Systems
In rectangular coordinates (Cartesian), a point in space is given by \((x, y, z)\). In spherical coordinates, the same point is given by \((\rho, \theta, \phi)\), where \(\rho\) is the radial distance from the origin, \(\theta\) is the azimuthal angle in the \(xy\)-plane from the positive \(x\)-axis, and \(\phi\) is the polar angle from the positive \(z\)-axis. The transformation equations are:\[ x = \rho \sin \phi \cos \theta \] \[ y = \rho \sin \phi \sin \theta \] \[ z = \rho \cos \phi \].
2Step 2: Set Up the Jacobian Matrix
The Jacobian matrix for a transformation from rectangular to spherical coordinates is constructed using the partial derivatives of the transformations. Specifically, it is a \(3 \times 3\) matrix where each element \(J_{ij}\) is given by the partial derivative of the Cartesian coordinate \(x_i\) with respect to the spherical coordinate \(q_j\) (\(x, y, z\) with respect to \(\rho, \theta, \phi\)). So, the matrix \(J\) is:\[ J = \begin{bmatrix} \frac{\partial x}{\partial \rho} & \frac{\partial x}{\partial \theta} & \frac{\partial x}{\partial \phi} \ \frac{\partial y}{\partial \rho} & \frac{\partial y}{\partial \theta} & \frac{\partial y}{\partial \phi} \ \frac{\partial z}{\partial \rho} & \frac{\partial z}{\partial \theta} & \frac{\partial z}{\partial \phi} \end{bmatrix} \].
3Step 3: Compute Partial Derivatives
Calculate each element of the Jacobian matrix:\[ \frac{\partial x}{\partial \rho} = \sin \phi \cos \theta \] \[ \frac{\partial x}{\partial \theta} = -\rho \sin \phi \sin \theta \] \[ \frac{\partial x}{\partial \phi} = \rho \cos \phi \cos \theta \]\[ \frac{\partial y}{\partial \rho} = \sin \phi \sin \theta \] \[ \frac{\partial y}{\partial \theta} = \rho \sin \phi \cos \theta \] \[ \frac{\partial y}{\partial \phi} = \rho \cos \phi \sin \theta \] \[ \frac{\partial z}{\partial \rho} = \cos \phi \] \[ \frac{\partial z}{\partial \theta} = 0 \] \[ \frac{\partial z}{\partial \phi} = -\rho \sin \phi \].
4Step 4: Assemble the Jacobian Matrix
Now, substitute the computed partial derivatives into the Jacobian matrix:\[ J = \begin{bmatrix} \sin \phi \cos \theta & -\rho \sin \phi \sin \theta & \rho \cos \phi \cos \theta \ \sin \phi \sin \theta & \rho \sin \phi \cos \theta & \rho \cos \phi \sin \theta \ \cos \phi & 0 & -\rho \sin \phi \end{bmatrix} \].
5Step 5: Calculate the Determinant of the Jacobian Matrix
The Jacobian determinant, also known as the Jacobian, is obtained by calculating the determinant of the assembled matrix. The determinant for this \(3 \times 3\) matrix is found using the standard formula for determinants. After expanding the determinant, we find:\[ \text{Det}(J) = \rho^2 \sin \phi \].
6Step 6: Interpret the Jacobian
The Jacobian \(\rho^2 \sin \phi\) represents the factor by which volumes transform under the change of coordinates from rectangular to spherical. This factor shows how a small region in Cartesian coordinates changes when expressed in spherical coordinates.
Key Concepts
Rectangular to Spherical TransformationCoordinate SystemsPartial DerivativesJacobian Determinant
Rectangular to Spherical Transformation
The conversion from rectangular (Cartesian) to spherical coordinates addresses how we describe the position of points in space using different systems. In rectangular coordinates, a point is represented by
- \(x\): the horizontal distance from the origin along the x-axis.
- \(y\): the horizontal distance along the y-axis.
- \(z\): the vertical distance from the origin.
- \(\rho\): the radial distance from the origin.
- \(\theta\): the azimuthal (horizontal) angle from the positive x-axis.
- \(\phi\): the polar (vertical) angle from the positive z-axis.
- x is converted using \(x = \rho \sin \phi \cos \theta\), representing the horizontal projection.
- y is given by \(y = \rho \sin \phi \sin \theta\), another projection onto the plane.
- z uses \(z = \rho \cos \phi\), indicating the vertical axis alignment.
Coordinate Systems
A coordinate system is a powerful tool in mathematics and physics that allows us to describe a point's position in space. Whether dealing with one-dimensional cases like a line, or more complex three-dimensional spaces, coordinate systems are fundamental.
There are several types of coordinate systems, but the two primarily discussed here are:
There are several types of coordinate systems, but the two primarily discussed here are:
- **Rectangular (Cartesian) Coordinates**: Use ordered pairs or triplets, such as \((x, y)\) in two dimensions or \((x, y, z)\) in three dimensions, to locate a point based on perpendicular axes.
- **Spherical Coordinates**: Ideal for spherical or radial symmetry problems, particularly useful in three-dimensional space, characterized by a radial distance (\(\rho\)), a polar angle (\(\phi\)), and an azimuthal angle (\(\theta\)).
Partial Derivatives
Partial derivatives are the building blocks of multivariable calculus. These derivatives are indispensable when dealing with functions of multiple variables as they allow us to examine how changes in one variable affect the function while keeping the others constant.
- For example, if we have a function \(f(x, y)\), the partial derivative \(\frac{\partial f}{\partial x}\) measures how \(f\) changes as \(x\) changes, keeping \(y\) constant.
- Similarly, \(\frac{\partial f}{\partial y}\) reveals how \(f\) changes with respect to \(y\).
Jacobian Determinant
The Jacobian determinant is an essential concept in multivariable calculus, particularly when transforming coordinates. It provides a measure of how much a transformation distorts, scales, or warps space.
For a transformation from rectangular
For a transformation from rectangular
- to spherical coordinates, the Jacobian determinant is derived by taking the determinant of the Jacobian matrix (whose elements are the partial derivatives of the transformation functions.)
- In our scenario, this gives us \(\text{Det}(J) = \rho^2 \sin \phi\).
Other exercises in this chapter
Problem 20
Sketch the solid whose volume is given by the following double integrals over the rectangle \(R=\\{(x, y)\) : \(0 \leq x \leq 2,0 \leq y \leq 3\\}\) $$ \iint_{R
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Use spherical coordinates to find the indicated quantity. Volume of the smaller wedge cut from the unit sphere by two planes that meet at a diameter at an angle
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Use triple iterated integrals to find the indicated quantities. Volume of the solid in the first octant bounded by \(y=2 x^{2}\) and \(y+4 z=8\)
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In Problems 21-32, sketch the indicated solid. Then find its volume by an iterated integration. Tetrahedron bounded by the coordinate planes and the plane \(z=6
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