Problem 21
Question
Find the inverse of the given function by using the "undoing process," and then verify that \(\left(f \circ f^{-1}\right)(x)=x\) and \(\left(f^{-1} \circ f\right)(x)=x\). (Objective 4) $$f(x)=5 x-4$$
Step-by-Step Solution
Verified Answer
The inverse function is \( f^{-1}(x) = \frac{x + 4}{5} \). Verification shows \( f(f^{-1}(x)) = x \) and \( f^{-1}(f(x)) = x \).
1Step 1: Write the function equation
Start with the given function equation: \[ y = 5x - 4 \] This represents the function \( f(x) = 5x - 4 \).
2Step 2: Swap x and y
To find the inverse function, interchange \(x\) and \(y\): \[ x = 5y - 4 \].
3Step 3: Solve for y
Focus on isolating \(y\) by solving the equation: \[ x + 4 = 5y \] Then, divide by 5 to obtain: \[ y = \frac{x + 4}{5} \].
4Step 4: Write the inverse function
The inverse function of \( f(x) = 5x - 4 \) is: \[ f^{-1}(x) = \frac{x + 4}{5} \].
5Step 5: Verify \( \left(f \circ f^{-1}\right)(x) = x \)
Substitute \( f^{-1}(x) \) into \( f(x) \): \[ f(f^{-1}(x)) = 5\left(\frac{x + 4}{5}\right) - 4 \] Simplify:\[ = x + 4 - 4 \] \[ = x \].
6Step 6: Verify \( \left(f^{-1} \circ f\right)(x) = x \)
Substitute \( f(x) \) into \( f^{-1}(x) \): \[ f^{-1}(f(x)) = \frac{5x - 4 + 4}{5} \] Simplify:\[ = \frac{5x}{5} \] \[ = x \].
Key Concepts
Undoing ProcessFunction CompositionInterchange Variables
Undoing Process
The concept of the "undoing process" is essentially about reversing the steps of a function to find its inverse. Think of a function as a series of actions that transform an input to an output. The inverse function undoes these actions to return to the original input. For the function given as \( f(x) = 5x - 4 \), finding the inverse involves reversing these operations.
Here is a simple breakdown:
Here is a simple breakdown:
- The original operation is to multiply by 5 and then subtract 4.
- To "undo" this, you start by adding 4 (opposite of subtracting 4), which brings us one step back.
- Next, you divide by 5, which reverses the multiplication by 5.
- Thus, the "undoing process" effectively is: add 4, then divide by 5.
Function Composition
Function composition is a way of combining two functions wherein the output of one function becomes the input of another. When verifying inverse functions, function composition allows us to check if one function truly undoes the other.
In mathematical terms, if \( g(x) \) is the inverse of \( f(x) \), then composing \( f \) with \( g \) and vice versa will return \( x \), our original input:
In mathematical terms, if \( g(x) \) is the inverse of \( f(x) \), then composing \( f \) with \( g \) and vice versa will return \( x \), our original input:
- \( (f \circ f^{-1})(x) = x \)
- \( (f^{-1} \circ f)(x) = x \)
Interchange Variables
Finding an inverse function often involves swapping variables, a concept known as interchanging variables. This step is crucial because to reverse the output-to-input relationship, we assign the roles of inputs and outputs to each other.
To illustrate:
To illustrate:
- Start with the function \( y = 5x - 4 \), where \( y \) is the output and \( x \) is the input.
- Interchange them: Let \( x \) become the output and \( y \) the new input, resulting in: \( x = 5y - 4 \).
- After interchanging, solve for \( y \) to express the inverse: \( y = \frac{x + 4}{5} \).
Other exercises in this chapter
Problem 20
Specify the domain for each of the functions. $$f(x)=\frac{7}{x^{2}-8 x-20}$$
View solution Problem 21
Find the constant of variation for each of the stated conditions. \(y\) varies directly as \(x\) and inversely as \(z\), and \(y=45\) when \(x=18\) and \(z=2\).
View solution Problem 21
Show that \((f \circ g)(x)=x\) and \((g \circ f)\) \((x)=x\) for each pair of functions. \(f(x)=4 x+2\) and \(g(x)=\frac{x-2}{4}\)
View solution Problem 21
Graph each of the functions. $$f(x)=2 x^{2}$$
View solution