Problem 21
Question
Find the general term, \(a_{m}\) for each geometric sequence. Then, find the indicated term. $$a_{1}=-\frac{1}{2}, r=-\frac{3}{2} ; a_{4}$$
Step-by-Step Solution
Verified Answer
The general term for the geometric sequence is \(a_{m} = -\frac{1}{2} \cdot \left(-\frac{3}{2}\right)^{m-1}\). Using this formula, the fourth term (\(a_4\)) is \(-\frac{27}{16}\).
1Step 1: Identify Given Values
From the problem, we have the initial values:
$$a_1 = -\frac{1}{2}$$
$$r = -\frac{3}{2}$$
We are tasked to find the fourth term (\(a_4\)) in the geometric sequence.
2Step 2: Use the Formula to Find the General Term
Use the general formula for any term in a geometric sequence:
$$a_{m} = a_{1} \cdot r^{m-1}$$
Plug in the given values for \(a_1\) and \(r\):
$$a_{m} = -\frac{1}{2} \cdot \left(-\frac{3}{2}\right)^{m-1}$$
Now we have our general term formula in terms of \(m\).
3Step 3: Find the Fourth Term
Use the formula found in step 2 to calculate the fourth term (\(a_4\)) by substituting \(m = 4\):
$$a_{4} = -\frac{1}{2} \cdot \left(-\frac{3}{2}\right)^{4-1}$$
Simplify and calculate the result:
$$a_{4} = -\frac{1}{2} \cdot \left(-\frac{3}{2}\right)^{3}$$
$$a_{4} = -\frac{1}{2}\cdot\left(-\frac{27}{8}\right)$$
$$a_{4} = -\frac{27}{16}$$
So, the fourth term (\(a_4\)) in the given geometric sequence is \(\boxed{-\frac{27}{16}}\).
Key Concepts
General TermFourth TermGeometric Sequence Formula
General Term
The general term of a geometric sequence is like a magic formula that helps you determine any term within the sequence. It is incredibly useful because once you have it, you can find any term without having to manually calculate each preceding term. The formula for the general term is given by: \( a_{m} = a_{1} \cdot r^{m-1} \), where:
- \( a_{m} \) represents the m-th term you want to find.
- \( a_{1} \) is the first term of the sequence.
- \( r \) is the common ratio, which is the factor by which each term is multiplied to get the next term.
- \( m \) is the term position you are interested in.
Fourth Term
Finding the specific term you're interested in, such as the fourth term in this case, is straightforward once you know how to use the general term formula. Suppose you have already derived the general term formula for the sequence: \( a_{m} = -\frac{1}{2} \cdot \left(-\frac{3}{2}\right)^{m-1} \). To find the fourth term, \( a_4 \), you simply substitute 4 for \( m \).Plug the value into the formula:
- Calculate: \( a_{4} = -\frac{1}{2} \cdot \left(-\frac{3}{2}\right)^{4-1} \)
- Simplify the exponent: \( a_{4} = -\frac{1}{2} \cdot \left(-\frac{3}{2}\right)^3 \)
- Calculate the power: \( \left(-\frac{3}{2}\right)^3 = -\frac{27}{8} \)
- Finish the calculation: \( a_{4} = -\frac{1}{2} \cdot -\frac{27}{8} = -\frac{27}{16} \)
Geometric Sequence Formula
The geometric sequence formula is the backbone of finding terms within geometric sequences. It provides a structured way to calculate any term by focusing on the relationship between terms rather than listing them. The essential part of this formula is the common ratio \( r \), which measures how each term increases or decreases in the sequence based on multiplication.Here are key points about the formula:
- The formula is \( a_{m} = a_{1} \cdot r^{m-1} \).
- It applies to any geometric sequence and helps find terms quickly.
- Knowing just two pieces of information—the first term \( a_{1} \) and the common ratio \( r \)—allows you to explore the entire sequence.
Other exercises in this chapter
Problem 20
Given the general term of each sequence, find each of the following. \(a_{n}=4 n^{2}-9\) a) the first term of the sequence b) the fourth term c) the 13 th term
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Evaluate each binomial coefficient. $$\left(\begin{array}{l}9 \\\7\end{array}\right)$$
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Find a formula for the general term, \(a_{n},\) of each sequence. $$2,4,6,8, \dots$$
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Given the arithmetic sequence \(4,7,10,13,16, \dots\) a) Find \(a_{1}\) and \(d\) b) Find a formula for the general term of the sequence, \(a_{n}\) c) Find the
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