Problem 21
Question
Find the following limits without using a graphing calculator or making tables. $$ \lim _{h \rightarrow 0}\left(5 x^{3}+2 x^{2} h-x h^{2}\right) $$
Step-by-Step Solution
Verified Answer
The limit is \(5x^3\).
1Step 1: Understanding the Limit
We need to find the limit of the expression \(5x^3 + 2x^2 h - xh^2\) as \(h\) approaches 0. This involves evaluating the behavior of the expression as \(h\) becomes very small.
2Step 2: Separate Terms of the Expression
Consider the expression \(5x^3 + 2x^2 h - xh^2\). Notice that it is a polynomial and therefore, the limit can be determined by replacing \(h\) with 0 in the expression since polynomial functions are continuous.
3Step 3: Evaluating Each Term Individually
Evaluate each term in the polynomial as \(h \rightarrow 0\).- The term \(5x^3\) is independent of \(h\), so it remains \(5x^3\).- The term \(2x^2h\) becomes \(2x^2 \cdot 0 = 0\) as \(h\) approaches 0.- The term \(xh^2\) becomes \(x \cdot 0^2 = 0\) as \(h\) approaches 0.
4Step 4: Combine Results of Evaluated Terms
By evaluating the limits of each term and combining the results, the expression simplifies to: \[ 5x^3 + 0 + 0 = 5x^3 \]Thus, the limit of the original expression as \(h\) approaches 0 is \(5x^3\).
Key Concepts
Limit EvaluationContinuity of PolynomialsBehavior as Variable Approaches Zero
Limit Evaluation
When we are evaluating the limit of a polynomial expression as a variable approaches a specific value, we are interested in what the expression looks like if we zoom in infinitely close to the point in question. In simple terms, this means observing the behavior of the function as a certain variable, in this case, \( h \), gets very close to zero.
- The goal is to pinpoint the expression's behavior and simplify it to deduce the ultimate value.
- For our expression \( 5x^3 + 2x^2 h - xh^2 \), this means breaking down each component to understand how they change as \( h \) approaches zero.
Continuity of Polynomials
Polynomials are a class of functions in mathematics that have a very nice property called continuity. This means that they are smooth and unbroken; you can draw them without lifting your pen from the paper.
- Polynomials are continuous everywhere, meaning at every point and at every limit like \( h = 0 \) in our example.
- This allows us to substitute values directly into these expressions when finding limits, thereby simplifying the overall process.
Behavior as Variable Approaches Zero
The behavior of terms in an expression as a variable approaches zero determines how the whole expression behaves.
- Terms that are independent of this variable remain unaffected.
- Each term that includes the variable \( h \), such as \( 2x^2h \) and \( xh^2 \), diminishes or disappears completely.
Other exercises in this chapter
Problem 21
Evaluate each expression. $$ \left.\frac{d^{2}}{d x^{2}} x^{10}\right|_{x=-1} $$
View solution Problem 21
Find the derivative of each function. $$ f(x)=\frac{1}{6} x^{3}+\frac{1}{2} x^{2}+x+1 $$
View solution Problem 21
Find the derivative of each function by using the Product Rule. Simplify your answers. $$ f(t)=6 t^{4 / 3}\left(3 t^{2 / 3}+1\right) $$
View solution Problem 22
Use the Generalized Power Rule to find the derivative of each function. $$ y=(1-x)^{50} $$
View solution