Problem 21
Question
Find the distance between the two points. Round your solution to the nearest hundredth if necessary. $$ (2,1),(-4,16) $$
Step-by-Step Solution
Verified Answer
The distance between the points (2,1) and (-4,16) is approximately 16.15.
1Step 1 Identify the points
Identify the points given as \((2,1)\) and \((-4,16)\). Here, (2,1) corresponds to \(x_1 = 2\) and \(y_1 = 1\), and (-4,16) corresponds to \(x_2 = -4\) and \(y_2 = 16\).
2Step 2 Substitute in the distance formula
Substitute these values into the distance formula \(\sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2}\). The calculation becomes \(\sqrt{((-4 - 2)^2 + (16 - 1)^2)}\).
3Step 3 Simplify the squares
Simplify the squares in the formula: \(\sqrt{(-6)^2 + (15)^2} = \sqrt{36 + 225}\).
4Step 4 Calculate the distance
Calculate the sum under the square root and then take the square root: \(\sqrt{261} ≈ 16.15\).
Key Concepts
Understanding Coordinate GeometryThe Role of the Square RootImportance of Squared Differences
Understanding Coordinate Geometry
Coordinate geometry, also known as analytic geometry, is a branch of mathematics that combines algebra and geometry to study points, lines, and shapes in a coordinate plane. Each point in this plane is represented by an ordered pair of numbers, often written as \((x, y)\). This is essential for understanding distances between points.
In the distance formula problem, we have been given two points \((2,1)\) and \((-4,16)\). Here’s a quick breakdown of coordinate geometry concepts involved:
In the distance formula problem, we have been given two points \((2,1)\) and \((-4,16)\). Here’s a quick breakdown of coordinate geometry concepts involved:
- Coordinates: Each point is given as \((x, y)\), where \(x\) is the horizontal position and \(y\) is the vertical position.
- Origin: The center of the coordinate plane is \((0, 0)\), where the x-axis and y-axis intersect.
- Distance: Finding the distance between two points involves calculating the straight line that connects them directly within this plane.
The Role of the Square Root
A square root is a fundamental concept in mathematics, representing a value that, when multiplied by itself, gives the original number. In the context of the distance formula, the square root is used to find the actual distance between two points.
When calculating the distance, you reach the step where you sum the squares of differences in both x and y coordinates. This will look like:
When calculating the distance, you reach the step where you sum the squares of differences in both x and y coordinates. This will look like:
- First, for our points, we have \((-4 - 2)^2 + (16 - 1)^2\).
- This simplifies to \(36 + 225 = 261\).
- The square root of 261 is approximately \(16.15\).
Importance of Squared Differences
The concept of squared differences is crucial in the distance formula as it ensures all distance contributions from each axis are positive.
When finding the distance, the formula squares the difference between x-coordinates and y-coordinates:
When finding the distance, the formula squares the difference between x-coordinates and y-coordinates:
- For x–coordinates: \((x_2 - x_1)^2\), or specifically for our problem \((-4 - 2)^2\) becomes \((-6)^2 = 36\).
- For y-coordinates: \((y_2 - y_1)^2\), or for our problem \((16 - 1)^2 = 15^2 = 225\).
- Positive Values: Squaring ensures that even if the coordinates result in a negative difference, the squared value is positive.
- Consistent Measurement: It maintains a consistent method by treating increases and decreases equally.
Other exercises in this chapter
Problem 20
Evaluate the function for the given value of x. $$y=2 \sqrt{x} ; 9$$
View solution Problem 21
Use an indirect proof to prove that the conclusion is true. If \(a c>b c\) and \(c>0,\) then \(a>b\)
View solution Problem 21
USING THE PYTHAGOREAN THEOREM Find the missing length of the right triangle if \(a\) and \(b\) are the lengths of the legs and \(c\) is the length of the hypote
View solution Problem 21
Find the midpoint of the line segment connecting the given points. \((-1,1),(-4,-4)\)
View solution