Problem 21
Question
Find the determinant of the matrix. Determine whether the matrix has an inverse, but don't calculate the inverse. $$\left[\begin{array}{rrr} 2 & 1 & 0 \\ 0 & -2 & 4 \\ 0 & 1 & -3 \end{array}\right]$$
Step-by-Step Solution
Verified Answer
The determinant is 4; the matrix is invertible.
1Step 1: Understanding the Determinant
A matrix has an inverse if its determinant is non-zero. For a 3x3 matrix \( A = \begin{bmatrix} a & b & c \ d & e & f \ g & h & i \end{bmatrix} \), the determinant is calculated as \( \text{det}(A) = a(ei - fh) - b(di - fg) + c(dh - eg) \).
2Step 2: Identifying Matrix Elements
The given matrix is \( \begin{bmatrix} 2 & 1 & 0 \ 0 & -2 & 4 \ 0 & 1 & -3 \end{bmatrix} \). Identify the elements: \( a=2, b=1, c=0 \), \( d=0, e=-2, f=4 \), \( g=0, h=1, i=-3 \).
3Step 3: Calculate the Cofactors
Calculate the cofactors needed:* \( ei - fh = (-2)(-3) - (4)(1) = 6 - 4 = 2 \)* \( di - fg = (0)(-3) - (4)(0) = 0 - 0 = 0 \)* \( dh - eg = (0)(1) - (-2)(0) = 0 - 0 = 0 \)
4Step 4: Compute the Determinant
The determinant of the matrix is given by:\[ \text{det}(A) = 2(2) - 1(0) + 0(0) = 4 \].
5Step 5: Determine Invertibility
Since the determinant \( \text{det}(A) = 4 \) is non-zero, the matrix is invertible.
Key Concepts
Matrix InverseCofactor ExpansionInvertibility of Matrices
Matrix Inverse
In mathematics, finding the inverse of a matrix is akin to solving a puzzle. An inverse matrix is significant because, when multiplied with the original matrix, it gives the identity matrix. This concept is especially useful in solving systems of linear equations. However, not all matrices have an inverse. A matrix can only be inverted when its determinant is non-zero.
For a matrix \( A \), if \( A^{-1} \) exists, it satisfies the equation:
For a matrix \( A \), if \( A^{-1} \) exists, it satisfies the equation:
- \( AA^{-1} = A^{-1}A = I \)
Cofactor Expansion
Understanding the concept of cofactor expansion is crucial in determining the determinant of a matrix. Cofactor expansion, also known as Laplace's expansion, allows you to expand a determinant along any row or column of the matrix, providing flexibility in computation.
Here's how it works:
Here's how it works:
- Select a row or column to expand along. Choose whichever has the most zeros for easier computation.
- For each element in this row or column, calculate its minor, which is the determinant of the submatrix that remains after removing the element's row and column.
- Then, determine the cofactor by applying a checkerboard pattern of signs to the minors, switching between positive and negative.
- Sum up the products of each element, its cofactor, and the matrix expands.
Invertibility of Matrices
The concept of matrix invertibility is fundamental in linear algebra. Matrix invertibility refers to whether a matrix has an inverse. A crucial criterion for this is the determinant of the matrix. If the determinant is zero, the matrix is singular and does not have an inverse.
Here's why the determinant being non-zero matters:
Here's why the determinant being non-zero matters:
- It is a test for linear independence of columns or rows: a zero determinant indicates linear dependence, which means no inverse exists.
- A non-zero determinant implies that row echelon form or reduced row echelon form will eventually yield an identity matrix during calculations, granting the matrix an inverse.
Other exercises in this chapter
Problem 21
Find all solutions of the system of equations. $$\left\\{\begin{array}{l} x-2 y=2 \\ y^{2}-x^{2}=2 x+4 \end{array}\right.$$
View solution Problem 21
Finding the Inverse of a Matrix Find the inverse of the matrix if it exists. $$\left[\begin{array}{rrr}1 & 2 & 3 \\\4 & 5 & -1 \\\1 & -1 & -10\end{array}\right]
View solution Problem 21
Solve the matrix equation for the unknown matrix \(X\), or explain why no solution exists. $$\begin{array}{c}A=\left[\begin{array}{ll}4 & 6 \\\1 & 3\end{array}\
View solution Problem 21
Solve the system, or show that it has no solution. If the system has infinitely many solutions, express them in the ordered-pair form given in Example 6. $$\lef
View solution