Problem 21
Question
Find an equation of the line that satisfies the given conditions. Through \((1,7) ;\) slope \(\frac{2}{3}\)
Step-by-Step Solution
Verified Answer
The equation of the line is \( y = \frac{2}{3}x + \frac{19}{3} \).
1Step 1: Understand the Point-Slope Form
The point-slope form of the equation of a line is given by \( y - y_1 = m(x - x_1) \), where \((x_1, y_1)\) is a point on the line and \(m\) is the slope of the line. In this problem, the point is \((1, 7)\) and the slope is \(\frac{2}{3}\).
2Step 2: Substitute Point and Slope into Point-Slope Form
Substitute \(x_1 = 1\), \(y_1 = 7\), and \(m = \frac{2}{3}\) into the point-slope formula. This gives:\[ y - 7 = \frac{2}{3}(x - 1) \]
3Step 3: Simplify the Equation
Distribute \(\frac{2}{3}\) on the right-hand side of the equation:\[ y - 7 = \frac{2}{3}x - \frac{2}{3} \]Then, solve for \(y\) by adding 7 to both sides to put the equation in slope-intercept form \(y = mx + b\):\[ y = \frac{2}{3}x - \frac{2}{3} + 7 \]
4Step 4: Simplify the Constant Term
Convert 7 into a fraction with denominator 3 to combine it with \(-\frac{2}{3}\):\[ 7 = \frac{21}{3} \]So the equation becomes:\[ y = \frac{2}{3}x + \left( -\frac{2}{3} + \frac{21}{3} \right) \]
5Step 5: Finalize the Equation
Add the constants:\[ -\frac{2}{3} + \frac{21}{3} = \frac{19}{3} \]Thus, the final equation of the line is:\[ y = \frac{2}{3}x + \frac{19}{3} \]
Key Concepts
Point-Slope FormSlope-Intercept FormSlopeCoordinate Geometry
Point-Slope Form
The point-slope form is a particularly useful way to write the equation of a line when you have one point and the slope. This formula shows the line's steepness (slope) and how it behaves around a specific point. The general equation is given by:
For instance, if we know a line goes through the point \( (1, 7) \) and has a slope of \frac{2}{3}\, we can substitute these values into the formula:
- \( y - y_1 = m(x - x_1) \)
For instance, if we know a line goes through the point \( (1, 7) \) and has a slope of \frac{2}{3}\, we can substitute these values into the formula:
- \( y - 7 = \frac{2}{3}(x - 1) \)
Slope-Intercept Form
The slope-intercept form is another common way of writing line equations, providing clear insight into both the slope and the y-intercept. This form is expressed as:
- \( y = mx + b \)
- \( y = \frac{2}{3}x + \frac{19}{3} \)
Slope
The slope of a line is a measure of its steepness, often described as "rise over run." It is denoted by the letter \( m \), and is computed by the change in y-coordinates divided by the change in x-coordinates between two points on the line. Mathematically, it is expressed as:
- \( m = \frac{y_2 - y_1}{x_2 - x_1} \)
Coordinate Geometry
Coordinate geometry, also known as analytic geometry, uses algebraic techniques to study geometry. It allows us to find different properties of geometric figures, like distance, midpoint, and the equation of lines. By assigning coordinates to points on a plane, problems in geometry become manageable with algebra.
In this context, the line's equation through \( (1, 7) \) with a slope of \frac{2}{3}\ is a prime example of how coordinates and algebra combine to describe geometric figures with precision.
Coordinate geometry is powerful because it provides a method to solve many geometry problems accurately, which would otherwise be complex using purely geometric methods. It offers a way to visualize equations and solve intersection, parallelism, and perpendicularity problems effectively.
In this context, the line's equation through \( (1, 7) \) with a slope of \frac{2}{3}\ is a prime example of how coordinates and algebra combine to describe geometric figures with precision.
Coordinate geometry is powerful because it provides a method to solve many geometry problems accurately, which would otherwise be complex using purely geometric methods. It offers a way to visualize equations and solve intersection, parallelism, and perpendicularity problems effectively.
Other exercises in this chapter
Problem 20
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