Problem 21
Question
explain what is wrong with the statement. A function \(f\) that is not differentiable at \(x=0\) has a graph with a sharp corner at \(x=0\)
Step-by-Step Solution
Verified Answer
The statement is incorrect; it assumes a corner is the only cause of non-differentiability.
1Step 1: Understanding Differentiability
For a function to be differentiable at a point, it must be smooth at that point. This means there is no sharp corner or cusp and the slope (or derivative) from the left and right of the point must agree. If the function has a sharp corner at a point, it cannot be differentiable there.
2Step 2: Evaluating the Statement
The statement claims that a function not differentiable at a specific point must have a sharp corner there. While a sharp corner is one reason for a function to not be differentiable, it is not the only reason. A point of non-differentiability could also occur where there is a vertical tangent, a discontinuity, or any other type of undefined derivative.
3Step 3: Identifying Other Causes
A vertical tangent line, where the slope becomes infinite, or a discontinuity, where the function jumps, are also reasons for non-differentiability. Therefore, these situations don't involve a corner but still result in a function not being differentiable at that point.
4Step 4: Conclusion on Statement Validity
The statement is incorrect because it incorrectly implies that the only reason for non-differentiability is a sharp corner. There are multiple other scenarios that can lead to the same conclusion.
Key Concepts
Sharp CornerVertical TangentDiscontinuity
Sharp Corner
When we talk about sharp corners in the context of differentiability, we refer to places on a graph where there is a sudden change in direction. Imagine drawing a graph line without lifting your pencil. A sharp corner implies that you'll abruptly change direction at some point, forming a jagged edge.
- Mathematically, a sharp corner occurs when the left-hand and right-hand derivatives at a point do not match.
- This discrepancy means there's no smooth transition through the point, breaking the continuous flow of the derivative.
- As a result, the function is not differentiable at that point.
Vertical Tangent
Vertical tangents are another fascinating scenario where differentiability fails. Imagine a graph where the line shoots almost straight up or down at some point. This happens when the slope or the rate of change becomes infinitely steep.
- In mathematical terms, this means the derivative at that point becomes infinite.
- A vertical tangent line at any point implies undefined behavior for the function’s derivative.
- Hence, the function is not differentiable wherever a vertical tangent exists.
Discontinuity
Discontinuities can be real sticking points in understanding differentiability. When a function has a gap, jump, or break at a certain point, this is described as a discontinuity.
- A function must be continuous at a point to possess a derivative there.
- If there is a break, the limits from the left and right of the discontinuity do not meet.
- Without continuous behavior, the derivative does not exist, leading to non-differentiability.
Other exercises in this chapter
Problem 20
Estimate the limit by substituting smaller and smaller values of \(h .\) For trigonometric functions, use radians. Give answers to one decimal place. $$\lim _{h
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$$\text { Let }\left.\frac{d V}{d r}\right|_{r=2}=16$$. (a) For small \(\Delta r,\) write an approximate equation relating \(\Delta V\) and \(\Delta r\) near \(
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Find a formula for the derivative using the power rule. Confirm it using difference quotients. $$l(x)=1 / x^{2}$$
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Let \(R=f(S)\) and \(f^{\prime}(10)=3.\) (a) For small \(\Delta S,\) write an approximate equation relating \(\Delta R\) and \(\Delta S\) near \(S=10.\) (b) Est
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