Problem 21
Question
Explain how the graph of \(f\) can be obtained from the graph of \(y=\frac{1}{x}\) or \(y=\frac{1}{x^{2}}\) Draw a sketch of the graph of \(f\) by hand. Then generate an accurate depiction of the graph with a graphing calculator. Finally, give the domain and range. $$f(x)=\frac{1}{x}+1$$
Step-by-Step Solution
Verified Answer
Shift the graph of \( y = \frac{1}{x} \) up by 1 unit. Domain: \( x \neq 0 \); Range: \( y \neq 1 \).
1Step 1: Start with Basic Graph
First, identify the basic graph that we will use as our starting point. The function given is \( f(x) = \frac{1}{x} + 1 \), which means we will start with the graph of \( y = \frac{1}{x} \). This is a hyperbolic curve that has two branches, one in the first quadrant (where \( x > 0 \)) and one in the third quadrant (where \( x < 0 \)). The graph has a vertical asymptote at \( x = 0 \) and a horizontal asymptote at \( y = 0 \).
2Step 2: Understand Transformation
The function \( f(x) = \frac{1}{x} + 1 \) involves a vertical shift of the graph of \( y = \frac{1}{x} \). The '+1' in the function indicates that each point on the graph of \( y = \frac{1}{x} \) is shifted up by 1 unit. This changes the position of the horizontal asymptote from \( y = 0 \) to \( y = 1 \). The vertical asymptote remains unchanged at \( x = 0 \).
3Step 3: Sketch the Transformed Graph
To draw the graph by hand, start with the vertical asymptote at \( x = 0 \) as a dashed line. Then, draw the two branches of the hyperbola that resemble the shape of \( y = \frac{1}{x} \), but shifted upward so that they approach the horizontal line \( y = 1 \) as the new asymptote. The first branch should be in the first quadrant approaching \( x = 0 \) from the right, and the second branch should be in the third quadrant approaching \( x = 0 \) from the left.
4Step 4: Graph Using a Calculator
Use a graphing calculator to plot the function \( f(x) = \frac{1}{x} + 1 \). Enter the function into the calculator, and observe the accurate depiction of the graph. Ensure your plot reflects the vertical shift and asymptotes described earlier.
5Step 5: Identify the Domain and Range
Determine the domain and range of the function. The domain of \( f(x) = \frac{1}{x} + 1 \) is all real numbers except \( x = 0 \), as the function is undefined there. The range, as shifted from \( y = \frac{1}{x} \), is all real numbers except \( y = 1 \). The function never actually reaches \( y = 1 \) due to the horizontal asymptote.
Key Concepts
Graphing FunctionsVertical ShiftDomain and Range
Graphing Functions
Graphing functions is a way to visualize mathematical relationships. It provides a picture of how a function behaves for different input values of the variable. In this context, we started with the graph of the basic function, which is hyperbola-shaped:
- The function curve is defined by the equation \(y = \frac{1}{x}\).
- Two branches of the hyperbola, one in the first quadrant and the other in the third quadrant, appear due to the positive and negative values of \(x\).
- A key feature is the vertical asymptote at \(x = 0\), where the graph approaches but never touches. This line indicates where the function is undefined.
- Another notable aspect is the horizontal asymptote at \(y = 0\), representing the value that \(y\) approaches as \(x\) becomes extremely large or small.
Vertical Shift
Vertical shifts in graphing a function involve moving the entire graph up or down without changing its shape. For the function \(f(x) = \frac{1}{x} + 1\):
- The \(+1\) signifies a shift upwards by 1 unit.
- This transformation affects the horizontal asymptote, moving it from \(y = 0\) to \(y = 1\).
- It means every point on the graph of \(y = \frac{1}{x}\) is elevated by one unit.
- Importantly, the vertical asymptote remains unchanged, as it is only influenced by horizontal movements.
Domain and Range
The domain and range are fundamental concepts when analyzing functions. **Domain** refers to the set of all possible input values (\(x\)-values) that a function can accept, while **range** is the set of all possible output values (\(y\)-values) the function can produce. In the case of \( f(x) = \frac{1}{x} + 1 \):
- **Domain:** All real numbers except \(x = 0\). The function is undefined at \(x = 0\), as dividing by zero is impossible.
- **Range:** All real numbers except \(y = 1\). Asymptotic behavior ensures that \(y = 1\) is never reached, due to the transformation bringing the entire graph 1 unit up.
Other exercises in this chapter
Problem 21
Find all complex solutions for each equation by hand. Do not use a calculator. $$\frac{x}{2-x}+\frac{2}{x}-5=0$$
View solution Problem 21
Solve each equation by hand. Do not use a calculator. $$x^{2 / 5}=4$$
View solution Problem 22
Use positive rational exponents to rewrite each expression. Assume variables represent positive numbers. $$\sqrt{x+1}$$
View solution Problem 22
Find all complex solutions for each equation by hand. Do not use a calculator. $$\frac{2 x}{x-3}+\frac{4}{x}-6=0$$
View solution