Problem 21
Question
$$ \begin{aligned} &\text { If } \mathbf{A}=\left(\begin{array}{r} 4 \\ 8 \\ -10 \end{array}\right) \text { and } \mathbf{B}=\left(\begin{array}{lll} 2 & 4 & 5 \end{array}\right), \text { find }(\mathbf{a}) \mathbf{A}^{T} \mathbf{A},(\mathbf{b}) \mathbf{B}^{T} \mathbf{B} \text { , }\\\ &\text { (c) } \mathbf{A}+\mathbf{B}^{T} \end{aligned} $$
Step-by-Step Solution
Verified Answer
\( \mathbf{A}^T \mathbf{A} = 180, \mathbf{B}^T \mathbf{B} = \begin{pmatrix} 4 & 8 & 10 \\ 8 & 16 & 20 \\ 10 & 20 & 25 \end{pmatrix}, \mathbf{A} + \mathbf{B}^T = \begin{pmatrix} 6 \\ 12 \\ -5 \end{pmatrix} \).
1Step 1: Calculate \( \mathbf{A}^T \mathbf{A} \)
To find \( \mathbf{A}^T \mathbf{A} \), first transpose \( \mathbf{A} \) to get \( \mathbf{A}^T = \begin{pmatrix} 4 & 8 & -10 \end{pmatrix} \). Then, multiply \( \mathbf{A}^T \) with \( \mathbf{A} \): \[ \mathbf{A}^T \mathbf{A} = \begin{pmatrix} 4 & 8 & -10 \end{pmatrix} \begin{pmatrix} 4 \ 8 \ -10 \end{pmatrix} \].Perform the multiplication: \[ 4 \times 4 + 8 \times 8 + (-10) \times (-10) = 16 + 64 + 100 = 180 \].Thus, \( \mathbf{A}^T \mathbf{A} = 180 \).
2Step 2: Calculate \( \mathbf{B}^T \mathbf{B} \)
Transpose \( \mathbf{B} \) to get \( \mathbf{B}^T = \begin{pmatrix} 2 \ 4 \ 5 \end{pmatrix} \) and multiply by \( \mathbf{B} \): \[ \mathbf{B}^T \mathbf{B} = \begin{pmatrix} 2 \ 4 \ 5 \end{pmatrix} \begin{pmatrix} 2 & 4 & 5 \end{pmatrix} \].Perform the matrix multiplication: \[ \begin{pmatrix} 2 \times 2 & 2 \times 4 & 2 \times 5 \ 4 \times 2 & 4 \times 4 & 4 \times 5 \ 5 \times 2 & 5 \times 4 & 5 \times 5 \end{pmatrix} = \begin{pmatrix} 4 & 8 & 10 \ 8 & 16 & 20 \ 10 & 20 & 25 \end{pmatrix} \].Thus, \( \mathbf{B}^T \mathbf{B} = \begin{pmatrix} 4 & 8 & 10 \ 8 & 16 & 20 \ 10 & 20 & 25 \end{pmatrix} \).
3Step 3: Calculate \( \mathbf{A} + \mathbf{B}^T \)
Make sure \( \mathbf{A} \) and \( \mathbf{B}^T \) can be added by verifying they are the same dimensions. Both \( \mathbf{A} = \begin{pmatrix} 4 \ 8 \ -10 \end{pmatrix} \) and \( \mathbf{B}^T = \begin{pmatrix} 2 \ 4 \ 5 \end{pmatrix} \) are column vectors with 3 entries, so they can be added.Add corresponding elements:\[ \mathbf{A} + \mathbf{B}^T = \begin{pmatrix} 4 + 2 \ 8 + 4 \ -10 + 5 \end{pmatrix} = \begin{pmatrix} 6 \ 12 \ -5 \end{pmatrix} \].Therefore, \( \mathbf{A} + \mathbf{B}^T = \begin{pmatrix} 6 \ 12 \ -5 \end{pmatrix} \).
Key Concepts
Matrix TranspositionMatrix Multiplication3D Vectors
Matrix Transposition
Matrix transposition is a simple, yet vital operation in linear algebra. It involves flipping a matrix over its diagonal, effectively swapping its row and column indices. Consider matrix \( \mathbf{A} \), represented as \( \begin{pmatrix} 4 \ 8 \ -10 \end{pmatrix} \). The transpose of \( \mathbf{A} \), denoted as \( \mathbf{A}^T \), converts the column matrix into a row matrix, resulting in \( \mathbf{A}^T = \begin{pmatrix} 4 & 8 & -10 \end{pmatrix} \).
- Each element \( a_{ij} \) in the original becomes \( a_{ji} \) in the transposed.
- In reality, this operation is necessary for operations like matrix multiplication, where the alignment of rows and columns matters.
Matrix Multiplication
Matrix multiplication is an operation where two matrices, or a matrix and a vector, combine to form another matrix. In our exercise, we dealt with \( \mathbf{A}^T \mathbf{A} \) and \( \mathbf{B}^T \mathbf{B} \).
For \( \mathbf{A}^T \mathbf{A} \), after transposing \( \mathbf{A} \):
For \( \mathbf{A}^T \mathbf{A} \), after transposing \( \mathbf{A} \):
- The resulting multiplication is \( \mathbf{A}^T \mathbf{A} = \begin{pmatrix} 4 & 8 & -10 \end{pmatrix} \begin{pmatrix} 4 \ 8 \ -10 \end{pmatrix} \).
- This involves summing the products of corresponding elements: \( 4 \times 4 + 8 \times 8 + (-10) \times (-10) = 180 \).
- The transpose and multiplication resulted in a 3x3 matrix, each entry obtained by multiplying rows by columns and summing.
3D Vectors
3D vectors are a cornerstone of mathematics and physics, representing points or directions in three-dimensional space. In the exercise, vectors \( \mathbf{A} \) and \( \mathbf{B} \) were involved. Each vector accounts for entities in a 3D coordinate system. For example, \( \mathbf{A} = \begin{pmatrix} 4 \ 8 \ -10 \end{pmatrix} \) represents a point or position in 3D space with x, y, and z coordinates.
When performing operations such as addition, like in \( \mathbf{A} + \mathbf{B}^T \), piecewise addition occurs:
When performing operations such as addition, like in \( \mathbf{A} + \mathbf{B}^T \), piecewise addition occurs:
- The x-components add together, y-components with y, z-components with z.
- Result: \( \begin{pmatrix} 4 + 2 \ 8 + 4 \ -10 + 5 \end{pmatrix} = \begin{pmatrix} 6 \ 12 \ -5 \end{pmatrix} \).
Other exercises in this chapter
Problem 21
In Problems, find the eigenvalues and eigenvectors of the given matrix. Using Theorem \(8.8 .2\) or (6), state whether the matrix is singular or nonsingular. $$
View solution Problem 21
Find the inverse of the given matrix or show that no inverse exists. $$ \left(\begin{array}{rrr} 4 & 2 & 3 \\ 2 & 1 & 0 \\ -1 & -2 & 0 \end{array}\right) $$
View solution Problem 21
Evaluate the determinant of the given matrix by cofactor expansion. $$ \left(\begin{array}{rrr} -2 & -1 & 4 \\ -3 & 6 & 1 \\ -3 & 4 & 8 \end{array}\right) $$
View solution Problem 21
Use a calculator to solve the given system. \(\begin{aligned} x_{1}+x_{2}+x_{3} &=4.280 \\ 0.2 x_{1}-0.1 x_{2}-0.5 x_{3} &=-1.978 \\ 4.1 x_{1}+0.3 x_{2}+0.12 x_
View solution