Problem 21
Question
Add the polynomials. $$\left(2 x^{2}-x+7\right)+\left(-2 x^{2}+4 x-9\right)$$
Step-by-Step Solution
Verified Answer
3x - 2
1Step 1: Identify Like Terms
In the polynomials, identify terms with the same power of \(x\). The first polynomial is \(2x^2 - x + 7\), and the second polynomial is \(-2x^2 + 4x - 9\). The like terms are those with \(x^2\), \(x\), and constant (without \(x\)).
2Step 2: Combine Like Terms with \(x^2\)
Combine the \(x^2\) terms from both polynomials. This gives us \(2x^2 - 2x^2 = 0\).
3Step 3: Combine Like Terms with \(x\)
Combine the \(x\) terms: \(-x + 4x = 3x\).
4Step 4: Combine Constant Terms
Combine the constant terms: \(7 - 9 = -2\).
5Step 5: Write the Resulting Polynomial
Combine all the results: Since the \(x^2\) terms cancel each other, the resulting polynomial is \(3x - 2\).
Key Concepts
Like TermsCombining Algebraic ExpressionsConstant Terms
Like Terms
In algebra, when dealing with polynomials, recognizing "like terms" is a crucial skill. Like terms are terms that contain the same variable raised to the same power. For example, in the polynomial expressions, the terms with \(x^2\) are like terms, and so are the terms with \(x\), and the constant numbers without any variable.
Understanding like terms is essential because it allows us to simplify complex algebraic expressions by adding or subtracting them. Let's break it down further:
Understanding like terms is essential because it allows us to simplify complex algebraic expressions by adding or subtracting them. Let's break it down further:
- Terms with \(x^2\): These terms have the variable \(x\) raised to the power of 2.
- Terms with \(x\): These are simply linear terms found in our expression.
- Constant Terms: These are standalone numbers without any accompanying variables.
Combining Algebraic Expressions
Once like terms are identified, combining algebraic expressions becomes straightforward. The process involves adding or subtracting coefficients of the like terms to simplify the polynomial further.
Here's a step-by-step breakdown:
Here's a step-by-step breakdown:
- Combine Terms with \(x^2\): Start by adding or subtracting the coefficients of \(x^2\). In our example, \(2x^2\) and \(-2x^2\) cancel each other out because their sum is zero.
- Combine Terms with \(x\): Similarly, sum up the coefficients of the linear terms. In the expression, \(-x + 4x\) results in \(3x\).
- Combine Constant Terms: Lastly, add the constant numbers: \(7\) and \(-9\), which give \(-2\).
Constant Terms
Constant terms in a polynomial are those that do not contain any variables. They are just numbers that stand alone in the expression.
For example, in the given polynomials, the constants are \(7\) and \(-9\). Constant terms are directly added or subtracted just like regular numbers:
Understanding the role of constant terms helps in accurately evaluating and simplifying algebraic expressions.
For example, in the given polynomials, the constants are \(7\) and \(-9\). Constant terms are directly added or subtracted just like regular numbers:
- Add or Subtract Normally: Since they have no variables, treat them like simple arithmetic addition or subtraction: \(7 - 9\) results in \(-2\).
Understanding the role of constant terms helps in accurately evaluating and simplifying algebraic expressions.
Other exercises in this chapter
Problem 20
Simplify. $$ \frac{5}{12} \div \frac{10}{9} $$
View solution Problem 20
Find the area of the triangle with base \(b\) and height \(h .\) \(b=y+1, h=2 y\)
View solution Problem 21
Exercises \(17-34:\) Evaluate the expression by hand. Check your result with a calculator. $$ 5^{0} $$
View solution Problem 21
Simplify the expression. Assume that all variables are positive. $$ \sqrt[3]{\frac{x^{3}}{8}} $$
View solution