Problem 21
Question
(a) Use the discriminant to determine whether the graph of the equation is a parabola, an ellipse, or a hyperbola. (b) Use a rotation of axes to eliminate the \(xy\)-term. (c) Sketch the graph. $$\sqrt{3} x^{2}+3 x y=3$$
Step-by-Step Solution
Verified Answer
The graph is a hyperbola. After rotating the axes, sketch the hyperbola centered at the origin.
1Step 1: Identify coefficients
For the given equation \( \sqrt{3}x^2 + 3xy = 3 \), identify the coefficients: \( A = \sqrt{3} \), \( B = 3 \), \( C = 0 \). These will be used to determine the type of conic section.
2Step 2: Calculate the Discriminant
The discriminant of a conic section is given by: \( B^2 - 4AC \). Substitute the coefficients into the formula: \( Discriminant = 3^2 - 4 \times \sqrt{3} \times 0 = 9 \).
3Step 3: Determine the Type of Conic
Since the discriminant \( B^2 - 4AC = 9 > 0 \), the conic section is a hyperbola.
4Step 4: Rotation of Axes Formula
To eliminate the \(xy\)-term, use the rotation of axes formula: \( \tan(2\theta) = \frac{B}{A-C} \). Plug the values into the formula: \( \tan(2\theta) = \frac{3}{\sqrt{3} - 0} = \sqrt{3} \).
5Step 5: Find the Rotation Angle
Since \( \tan(2\theta) = \sqrt{3} \), \( 2\theta = 60^\circ \) (since \( \tan(60^\circ) = \sqrt{3} \)). So, \( \theta = 30^\circ \).
6Step 6: Transform the Equation
Apply the rotation of axes: \( x = x' \cos(30^\circ) - y' \sin(30^\circ) \) and \( y = x' \sin(30^\circ) + y' \cos(30^\circ) \). Substitute into the original equation and simplify to get: \( \frac{3}{2} (x')^2 - (y')^2 = 3 \).
7Step 7: Sketch the Graph
The transformed equation \( \frac{3}{2} (x')^2 - (y')^2 = 3 \) represents a hyperbola. Center the graph at the origin and sketch the hyperbola, noting the axes' orientation which has been changed by the rotation.
Key Concepts
Discriminant in Conic SectionsRotation of AxesUnderstanding HyperbolasSketching Graphs
Discriminant in Conic Sections
The discriminant in conic sections is a handy tool that helps identify the type of conic section represented by a quadratic equation. For any quadratic equation of the form \( Ax^2 + Bxy + Cy^2 + Dx + Ey + F = 0 \), the discriminant is given by \( B^2 - 4AC \). This value plays a crucial role in determining whether you are dealing with a parabola, ellipse, or hyperbola.
Here's how it works:
Here's how it works:
- If \( B^2 - 4AC < 0 \), the equation represents an ellipse.
- If \( B^2 - 4AC = 0 \), the equation represents a parabola.
- If \( B^2 - 4AC > 0 \), the equation represents a hyperbola.
Rotation of Axes
Rotation of axes is a method used to eliminate the \(xy\)-term from a conic section's equation. It simplifies the graph and equation, making analysis easier. This technique is especially useful when dealing with equations where the conic section's orientation isn't along the traditional x or y axes.
Here's a step-by-step guide:
Here's a step-by-step guide:
- Start with the rotation formula: \( \tan(2\theta) = \frac{B}{A-C} \).
- Substitute the coefficients from your equation into the formula. In our example, it gives \( \tan(2\theta) = \sqrt{3} \).
- Find \( \theta \), which is half of the angle given by \( 2\theta \). In this case, \( 2\theta = 60^\circ \), so \( \theta = 30^\circ \).
Understanding Hyperbolas
Hyperbolas are fascinating conic sections characterized by two separate curves, called branches. Recognizing and understanding their properties are fundamental aspects of conic section studies.
Key characteristics include:
Key characteristics include:
- They are defined as the set of all points where the difference of distances to two fixed points (foci) is constant.
- Hyperbolas can be horizontal or vertical, depending on their orientation.
- They have asymptotes, which are lines the branches approach but never touch.
Sketching Graphs
Sketching graphs of conics, like hyperbolas, requires careful plotting and understanding of their general equation and properties. From the transformed equation, \( \frac{3}{2} (x')^2 - (y')^2 = 3 \), you can gather insights on orientation and scale.
Here are the steps to sketch a hyperbola:
Here are the steps to sketch a hyperbola:
- Identify the center, plotted at the origin if the equation is in standard form after rotation.
- Determine the vertices and foci parameters using the derived equation.
- Draw asymptotes based on coefficients, guiding the shape of the branches.
- Sketch the branches, ensuring the distance between them matches the constant difference in the hyperbola definition.
Other exercises in this chapter
Problem 20
Find the focus, directrix, and focal diameter of the parabola, and sketch its graph. $$x-7 y^{2}=0$$
View solution Problem 21
A polar equation of a conic is given. (a) Show that the conic is an ellipse, and sketch its graph. (b) Find the vertices and directrix, and indicate them on the
View solution Problem 21
Find the focus, directrix, and focal diameter of the parabola, and sketch its graph. $$5 x+3 y^{2}=0$$
View solution Problem 22
A polar equation of a conic is given. (a) Show that the conic is an ellipse, and sketch its graph. (b) Find the vertices and directrix, and indicate them on the
View solution