Problem 21
Question
(a) Use a graphing calculator to sketch the graph of $$f(x)=e^{a x} \sin x, \quad x \geq 0$$ for \(a=-0.1,-0.01,0,0.01\), and 0.1. (b) Which part of the function \(f(x)\) produces the oscillations that you see in the graphs sketched in (a)? (c) Describe in words the effect that the value of \(a\) has on the shape of the graph of \(f(x)\). (d) Graph \(f(x)=e^{a x} \sin x, g(x)=-e^{a x}\), and \(h(x)=e^{a x}\) together in one coordinate system for (i) \(a=0.1\) and (ii) \(a=-0.1\). [Make separate graphs for (i) and (ii).] Explain what you see in each case. Show that $$-e^{a x} \leq e^{a x} \sin x \leq e^{a x}$$ Use this pair of inequalities to determine the values of \(a\) for which \(\lim _{x \rightarrow \infty} f(x)\) exists, and find the limiting value.
Step-by-Step Solution
VerifiedKey Concepts
Exponential functions
- If \(a > 0\), the function describes exponential growth as \(x\) increases. The larger the value of \(a\), the faster the growth.
- If \(a < 0\), it represents exponential decay, meaning the function decreases as \(x\) increases.
- If \(a = 0\), the expression simplifies to a constant equal to 1.
Trigonometric functions
- It is oscillatory, with values ranging from -1 to 1, producing wave-like graphs.
- The period of \(\sin x\) is \(2\pi\), indicating how often the wave pattern repeats.
- The combination with exponential functions results in changes to the amplitude but not the frequency of oscillations.
Graphing calculator
- Input the function accurately, paying attention to operator placement and parentheses to ensure correct calculation.
- Adjust viewing windows to capture the essential parts of the graph, especially when dealing with exponential growth or decay that can quickly exceed common view limits.
- Look for features such as oscillations, intercepts, and bounding envelopes, which can reveal insights into function behavior.
- Observe the changes in the graph as you vary parameters like \(a\) to study their effects.
Limits
- For the function \(f(x) = e^{ax} \sin x\), the limit as \(x\) approaches infinity depends heavily on the value of \(a\).
- If \(a < 0\), the function’s exponential decay drives it towards zero, so \(\lim_{x \to \infty} f(x) = 0\).
- If \(a \geq 0\), \(e^{ax}\) causes the amplitude to grow unbounded, so the limit does not exist.