Problem 21
Question
A survey of grocery stores in the Southeast revealed 40 percent had a pharmacy, 50 percent had a floral shop, and 70 percent had a deli. Suppose 10 percent of the stores have all three departments, 30 percent have both a pharmacy and a deli, 25 percent have both \(a\) floral shop and deli, and 20 percent have both a pharmacy and floral shop. a. What is the probability of selecting a store at random and finding it has both a pharmacy and a floral shop? b. What is the probability of selecting a store at random and finding it has both a pharmacy and a deli? c. Are the events "select a store with a deli" and "select a store with a pharmacy" mutually exclusive? d. What is the name given to the event of "selecting a store with a pharmacy, a floral shop, and a deli?" e. What is the probability of selecting a store that does not have all three departments?
Step-by-Step Solution
VerifiedKey Concepts
Mutually Exclusive Events
This is what makes them mutually exclusive.
In our grocery store exercise, we need to determine if having a pharmacy and a deli in the same store are mutually exclusive.
Since it's possible for a store to have both departments, as shown by the given probabilities, we identify that these events are not mutually exclusive. This distinction is crucial for understanding how different probabilities relate to one another in scenarios where multiple conditions can overlap.
Intersection of Events
In the example of the grocery stores, several probabilities concerning intersections are given. For instance:
- The probability of a store having both a pharmacy and a floral shop is \( P(P \cap F) = 0.20 \).
- Another intersection, having both a pharmacy and a deli, is \( P(P \cap D) = 0.30 \).
Complement Rule
In our exercise, we applied the complement rule for a store not having all three departments (pharmacy, floral shop, and deli). Given that the probability of having all three is \( P(P \cap F \cap D) = 0.10 \), the complement rule helps us find the probability of not having all three:
- \( 1 - P(P \cap F \cap D) = 0.90 \)
Conditional Probability
The notation used is \( P(A \mid B) \), where you are calculating the probability of \( A \) happening, assuming \( B \) is true. Understanding conditional probabilities is crucial for dealing with dependent events in probability theory.
While our exercise did not need this calculation directly, being aware of conditional probabilities allows you to think critically about how one event impacts another. As you delve deeper into probability, you'll see more complex problems where this concept is essential.