Problem 21
Question
a. On the same set of axes, sketch the graphs of \(y=2 \sin x\) and \(y=\cos x\) in the interval \(0 \leq x \leq 2 \pi\) b. How many points do the graphs of \(y=2 \sin x\) and \(y=\cos x\) have in common in the interval \(0 \leq x \leq 2 \pi ?\)
Step-by-Step Solution
Verified Answer
The graphs intersect at 2 points in the interval \(0 \leq x \leq 2\pi\).
1Step 1: Understand the Functions
The first function is \( y = 2 \sin x \), which means the sine wave will have an amplitude of 2 rather than 1, and it will oscillate between -2 and 2.The second function is \( y = \cos x \), which will oscillate between -1 and 1 due to its amplitude of 1.Both functions are periodic with a period of \( 2\pi \), the same as the interval given.
2Step 2: Plotting Key Points for y=2sin(x)
Identify key points for one period of \( y = 2 \sin x \):- At \( x = 0 \), \( y = 2 \sin 0 = 0 \)- At \( x = \pi/2 \), \( y = 2 \sin(\pi/2) = 2 \)- At \( x = \pi \), \( y = 2 \sin \pi = 0 \)- At \( x = 3\pi/2 \), \( y = 2 \sin(3\pi/2) = -2 \)- At \( x = 2\pi \), \( y = 2 \sin 2\pi = 0 \)Plot these points, and sketch the sine curve with a peak at 2 and a trough at -2 over the interval \( 0 \leq x \leq 2\pi \).
3Step 3: Plotting Key Points for y=cos(x)
Identify key points for one period of \( y = \cos x \):- At \( x = 0 \), \( y = \cos 0 = 1 \)- At \( x = \pi/2 \), \( y = \cos(\pi/2) = 0 \)- At \( x = \pi \), \( y = \cos \pi = -1 \)- At \( x = 3\pi/2 \), \( y = \cos(3\pi/2) = 0 \)- At \( x = 2\pi \), \( y = \cos 2\pi = 1 \)Plot these points, and sketch the cosine curve oscillating between -1 and 1.
4Step 4: Finding Intersection Points
The graphs intersect where \( 2\sin x = \cos x \). Using the identity \( \tan x = \frac{\sin x}{\cos x} \), solve: \[2 \sin x = \cos x \Rightarrow 2 \tan x = 1\]This simplifies to \( \tan x = \frac{1}{2} \).Find solutions of \( x \) in \( 0 \leq x \leq 2\pi \):- The principal solutions are \( x = \tan^{-1}(\frac{1}{2}) \).- Adding the period of tangent, \( \pi \), find the second point by calculating \( x = \pi + \tan^{-1}(\frac{1}{2}) \).These points provide the values of \( x \) where the graphs intersect in the given interval.
Key Concepts
Graphing Sine and CosineAmplitude and PeriodTrigonometric Identities
Graphing Sine and Cosine
Understanding how to graph the sine and cosine functions is an essential skill in mathematics. These functions represent periodic behaviors that repeat their patterns over specific intervals.
For the sine function, such as the graph of \( y = 2 \sin x \), the curve displays oscillations with peaks and troughs. To properly sketch this graph, identify key points for one full cycle from \( 0 \) to \( 2\pi \):
For the sine function, such as the graph of \( y = 2 \sin x \), the curve displays oscillations with peaks and troughs. To properly sketch this graph, identify key points for one full cycle from \( 0 \) to \( 2\pi \):
- At \( x = 0 \), \( y = 0 \)
- At \( x = \pi/2 \), \( y = 2 \)
- At \( x = \pi \), \( y = 0 \)
- At \( x = 3\pi/2 \), \( y = -2 \)
- At \( x = 2\pi \), \( y = 0 \)
- At \( x = 0 \), \( y = 1 \)
- At \( x = \pi/2 \), \( y = 0 \)
- At \( x = \pi \), \( y = -1 \)
- At \( x = 3\pi/2 \), \( y = 0 \)
- At \( x = 2\pi \), \( y = 1 \)
Amplitude and Period
The amplitude and period are fundamental properties of trigonometric functions that define how these functions look when plotted.The **amplitude** of a function like sine or cosine describes the height from the center to the peak or from the center to the trough. For instance, in \( y = 2 \sin x \), the amplitude is 2:
- This indicates the graph will oscillate between +2 and -2 because it stretches twice as far from the midline compared to a standard sine wave, which has an amplitude of 1.
- So you see that the sine curve's highest point is at y = 2, and lowest is at y = -2.
- This means it oscillates between +1 and -1, which is typical for standard cosine functions.
Trigonometric Identities
Trigonometric identities are mathematical tools that simplify the manipulation and solving of trigonometric functions. In the problem, finding the intersection points of \( y = 2 \sin x \) and \( y = \cos x \) involves utilizing these identities.The equation \( 2 \sin x = \cos x \) can be transformed using the tangent identity:
For any angle \( x \), we know that \( \tan x = \frac{\sin x}{\cos x} \). This gives us:\[2 \sin x = \cos x \Rightarrow \frac{2 \sin x}{\cos x} = 1 \Rightarrow 2 \tan x = 1 \]This further simplifies to \( \tan x = \frac{1}{2} \). Finding the solutions for \( x \) within the interval \( 0 \leq x \leq 2\pi \) involves solving:
For any angle \( x \), we know that \( \tan x = \frac{\sin x}{\cos x} \). This gives us:\[2 \sin x = \cos x \Rightarrow \frac{2 \sin x}{\cos x} = 1 \Rightarrow 2 \tan x = 1 \]This further simplifies to \( \tan x = \frac{1}{2} \). Finding the solutions for \( x \) within the interval \( 0 \leq x \leq 2\pi \) involves solving:
- The principal solution, \( x = \tan^{-1}(\frac{1}{2}) \).
- Since the tangent function has a period of \( \pi \), the next solution is \( x = \pi + \tan^{-1}(\frac{1}{2}) \).
Other exercises in this chapter
Problem 20
Using the graphs of each function, determine whether each function is even, odd, or neither. a. \(y=\tan x\) b. \(y=\csc x\) c. \(y=\sec x\) d. \(y=\cot x\)
View solution Problem 20
Find the phase shift of each function. \(y=\cos \left(x-\frac{\pi}{2}\right)\)
View solution Problem 21
Find the phase shift of each function. \(y=\sin \left(x+\frac{\pi}{3}\right)\)
View solution Problem 22
a. On the same set of axes, sketch the graphs of \(y=\tan x\) and \(y=\cos \left(x+\frac{\pi}{2}\right)\) in the interval \(-\frac{\pi}{2} \leq x \leq \frac{3 \
View solution