Problem 21
Question
19–44 ? Make a table of values and sketch the graph of the equation. Find the x- and y-intercepts and test for symmetry. $$ y=-x+4 $$
Step-by-Step Solution
Verified Answer
The x-intercept is (4, 0) and the y-intercept is (0, 4); there is no symmetry.
1Step 1: Create a Table of Values
To create a table of values, choose several x-values and calculate their corresponding y-values using the equation \( y = -x + 4 \). For example: \( x = -2, -1, 0, 1, 2 \).- If \( x = -2 \), then \( y = -(-2) + 4 = 6 \).- If \( x = -1 \), then \( y = -(-1) + 4 = 5 \).- If \( x = 0 \), then \( y = -(0) + 4 = 4 \).- If \( x = 1 \), then \( y = -(1) + 4 = 3 \).- If \( x = 2 \), then \( y = -(2) + 4 = 2 \). Record these in a table: \[\begin{array}{c|c}x & y \\hline-2 & 6 \-1 & 5 \0 & 4 \1 & 3 \2 & 2 \\end{array}\]
2Step 2: Sketch the Graph
Plot the points from the table \((-2, 6), (-1, 5), (0, 4), (1, 3), (2, 2)\) on a coordinate plane. Since this is a linear equation, draw a straight line through the points. The line will slope downwards as the equation has a negative slope (-1).
3Step 3: Find the x-intercept
To find the x-intercept, set \( y = 0 \) and solve for \( x \).\[0 = -x + 4 \x = 4\]So, the x-intercept is at \( (4, 0) \).
4Step 4: Find the y-intercept
To find the y-intercept, set \( x = 0 \) and solve for \( y \). From the equation: \( y = -(0) + 4 = 4 \). So, the y-intercept is at \( (0, 4) \).
5Step 5: Test for Symmetry
For symmetry, test the equation for even and odd functions.- To test for y-axis symmetry, substitute \( x = -x \) and see if the equation remains the same. \(-x + 4 eq x + 4\), hence it is not symmetrical about the y-axis.- To test for x-axis symmetry, substitute \( y = -y \): leads to \(-y = -x + 4\), which simplifies back to \( y eq x - 4 \) and is not symmetrical about the x-axis.- To test origin symmetry, substitute \( (x,y) \to (-x,-y) \): \(-y = x + 4 \) which does not simplify to the original equation, so it is not symmetrical about the origin.
Key Concepts
Graphing Linear EquationsIntercepts of GraphsSymmetry in Graphs
Graphing Linear Equations
Graphing linear equations is about visualizing a line on a coordinate grid. When you have an equation like \( y = -x + 4 \), it represents a straight line. To graph this equation, start by creating a table of values. Choose several points for \( x \) and compute the corresponding \( y \) values by plugging them into the equation. For instance:
Such plots are useful in many real-world applications, from economics to physics, where linear relationships often appear.
- If \( x = -2 \), \( y = (-(-2) + 4) = 6 \).
- If \( x = 0 \), \( y = (-(0) + 4) = 4 \).
- Continue with more values for accuracy.
Such plots are useful in many real-world applications, from economics to physics, where linear relationships often appear.
Intercepts of Graphs
Intercepts are specific points where the graph meets the axes. For linear equations, they help in sketching the graph accurately.
The **y-intercept** is where the graph intersects the y-axis. To find it, simply set \( x = 0 \) in the equation and solve for \( y \). In our case:
They are particularly helpful for understanding where phenomena start or stop, such as when a company breaks even (x-intercept) or the initial amount in a bank account (y-intercept).
The **y-intercept** is where the graph intersects the y-axis. To find it, simply set \( x = 0 \) in the equation and solve for \( y \). In our case:
- y-intercept: \( (0, 4) \).
- x-intercept: \( (4, 0) \).
They are particularly helpful for understanding where phenomena start or stop, such as when a company breaks even (x-intercept) or the initial amount in a bank account (y-intercept).
Symmetry in Graphs
Symmetry in graphs indicates whether, and how, the shape of the graph is mirrored over specific axes or points. Testing for symmetry can provide insights about the graph's behavior and properties. For symmetry:
- Check **y-axis symmetry** by replacing \( x \) with \( -x \). The line \(-x + 4 eq x + 4\) shows no y-axis symmetry.
- Check **x-axis symmetry** by replacing \( y \) with \( -y \). With \(-y = -x + 4 eq x - 4\), no x-axis symmetry exists.
- Check **origin symmetry** by substituting \( (x, y) \) with \( (-x, -y) \). The transformation \(-y = x + 4 eq y = -x + 4 \) results in no symmetry about the origin.
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