Problem 21
Question
17–24 ? Use a Factoring Formula to factor the expression. $$ 8 s^{3}-125 t^{3} $$
Step-by-Step Solution
Verified Answer
The expression factors to \((2s - 5t)(4s^2 + 10st + 25t^2)\).
1Step 1: Identify the Type of Expression
The given expression is \(8s^3 - 125t^3\), which is a difference of cubes. Cubes are expressions in the form \(a^3 - b^3\). Here, we need to rewrite \(8s^3\) and \(125t^3\) in terms of cubes.
2Step 2: Express Terms as Perfect Cubes
Rewrite \(8s^3\) and \(125t^3\) as cubes: \(8s^3 = (2s)^3\) and \(125t^3 = (5t)^3\). So, the expression becomes \((2s)^3 - (5t)^3\).
3Step 3: Apply the Difference of Cubes Formula
The difference of cubes formula is \(a^3 - b^3 = (a - b)(a^2 + ab + b^2)\). Identify \(a = 2s\) and \(b = 5t\).
4Step 4: Substitute into the Formula
Substitute \(a = 2s\) and \(b = 5t\) into the formula: \((2s - 5t)((2s)^2 + (2s)(5t) + (5t)^2)\).
5Step 5: Simplify the Expression
Calculate each part: \((2s)^2 = 4s^2\), \((2s)(5t) = 10st\), and \((5t)^2 = 25t^2\). So, \(a^2 + ab + b^2 = 4s^2 + 10st + 25t^2\).
6Step 6: Final Factored Expression
Combine all parts from previous steps: The expression \(8s^3 - 125t^3\) factors to \((2s - 5t)(4s^2 + 10st + 25t^2)\).
Key Concepts
Difference of CubesAlgebraic ExpressionsFactoring Formulas
Difference of Cubes
The difference of cubes is an important concept in algebra that refers to the subtraction of two cubed terms. When we talk about cubes, we mean an algebraic expression raised to the third power. For instance, if we have two terms, say \(a\) and \(b\), then their cubes are \(a^3\) and \(b^3\).
To factor a difference of cubes, which looks like \(a^3 - b^3\), we use a specific formula:
An example is the expression \(8s^3 - 125t^3\). We recognize it as a difference of cubes because \(8s^3 = (2s)^3\) and \(125t^3 = (5t)^3\). After identifying the cubes, we apply the difference of cubes formula to factor it.
To factor a difference of cubes, which looks like \(a^3 - b^3\), we use a specific formula:
- \(a^3 - b^3 = (a - b)(a^2 + ab + b^2)\)
An example is the expression \(8s^3 - 125t^3\). We recognize it as a difference of cubes because \(8s^3 = (2s)^3\) and \(125t^3 = (5t)^3\). After identifying the cubes, we apply the difference of cubes formula to factor it.
Algebraic Expressions
Algebraic expressions are combinations of variables, numbers, and operations that form a mathematical phrase. They can represent real-world quantities and are foundational in algebra. Expressions like \(8s^3\) or \(125t^3\) are polynomial expressions that are commonly found in algebra.
An expression like \(8s^3\) is made by multiplying the variable \(s\) by itself two more times and then by 8; similarly, \(125t^3\) involves the variable \(t\) raised to the third power and multiplied by 125. In any algebraic expression, understanding how to manipulate terms using operations like addition, subtraction, multiplication, and division is key.
Algebraic expressions form the basis for higher-level mathematical operations such as factoring, which allows us to simplify and solve equations effectively.
An expression like \(8s^3\) is made by multiplying the variable \(s\) by itself two more times and then by 8; similarly, \(125t^3\) involves the variable \(t\) raised to the third power and multiplied by 125. In any algebraic expression, understanding how to manipulate terms using operations like addition, subtraction, multiplication, and division is key.
Algebraic expressions form the basis for higher-level mathematical operations such as factoring, which allows us to simplify and solve equations effectively.
Factoring Formulas
Factoring is a crucial skill in algebra that involves breaking down expressions into their simplest components. Use factoring formulas to simplify or solve equations by finding expressions that multiply together to give the original expression. These formulas include special cases like:
Using the difference of cubes as an example, it's a tool that lets you break down an expression like \(8s^3 - 125t^3\) into \((2s - 5t)(4s^2 + 10st + 25t^2)\). By applying these formulas, complex expressions become manageable and much easier to work with.
- Difference of cubes: \(a^3 - b^3 = (a - b)(a^2 + ab + b^2)\)
- Sum of cubes: \(a^3 + b^3 = (a + b)(a^2 - ab + b^2)\)
Using the difference of cubes as an example, it's a tool that lets you break down an expression like \(8s^3 - 125t^3\) into \((2s - 5t)(4s^2 + 10st + 25t^2)\). By applying these formulas, complex expressions become manageable and much easier to work with.
Other exercises in this chapter
Problem 21
\(21-34\) . Perform the multiplication or division and simplify. $$ \frac{4 x}{x^{2}-4} \cdot \frac{x+2}{16 x} $$
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Perform the indicated operations and simplify. $$ 2(2-5 t)+t^{2}(t-1)-\left(t^{4}-1\right) $$
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Evaluate the expression using \(x=3, y=4,\) and \(z=-1\). \((9 x)^{2 / 3}+(2 y)^{2 / 3}+z^{2 / 3}\)
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Write an algebraic formula for the given quantity.. The time \(t\) it takes an airplane to travel \(d\) miles if its speed is \(r\) miles per hour
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