Problem 21
Question
\(15-24=\) Find the quotient and remainder using long division. $$ \frac{6 x^{3}+2 x^{2}+22 x}{2 x^{2}+5} $$
Step-by-Step Solution
Verified Answer
Quotient: \(3x + 1\), Remainder: \(7x - 5\).
1Step 1: Set up the Division
We are asked to divide the polynomial \(6x^3 + 2x^2 + 22x\) by \(2x^2 + 5\) using long division. We'll set it up just like a numerical long division, placing \(6x^3 + 2x^2 + 22x\) inside the division bracket and \(2x^2 + 5\) outside.
2Step 2: Divide the Leading Terms
Look at the leading term of the dividend \(6x^3\) and the leading term of the divisor \(2x^2\). Divide these: \(\frac{6x^3}{2x^2} = 3x\). This will be the first term of our quotient.
3Step 3: Multiply and Subtract
Now multiply the entire divisor \(2x^2 + 5\) by the first term of our quotient \(3x\), which gives \((3x)(2x^2 + 5) = 6x^3 + 15x\). Subtract this from \(6x^3 + 2x^2 + 22x\), resulting in \((6x^3 + 2x^2 + 22x) - (6x^3 + 15x) = 2x^2 + 7x\).
4Step 4: Repeat the Process
Next, divide the leading term of the new polynomial \(2x^2\) by the leading term of the divisor \(2x^2\), which gives \(1\). This is the next term in our quotient. Multiply the entire divisor by \(1\), giving \(2x^2 + 5\). Subtract this from \(2x^2 + 7x\), resulting in \((2x^2 + 7x) - (2x^2 + 5) = 7x - 5\).
5Step 5: Final Division and Remainder
Try to divide the leading term \(7x\) by \(2x^2\). Since the degree of \(7x\) is less than that of \(2x^2\), no further division is possible. Thus, \(7x - 5\) is the remainder.
6Step 6: Write the Solution
The division gives us a quotient of \(3x + 1\) and a remainder of \(7x - 5\).
Key Concepts
Long DivisionQuotientRemainderLeading Term
Long Division
Polynomial long division is a method for dividing a polynomial by another polynomial, much like the long division of numbers that you may already be familiar with. In polynomial long division, we align terms based on descending powers of the variable.
Here's a quick rundown:
Here's a quick rundown:
- Set up the division with the larger polynomial (the dividend) inside the division symbol and the smaller polynomial (the divisor) outside.
- Divide the leading term of the dividend by the leading term of the divisor to find the first term of the quotient.
- Multiply the entire divisor by this first term of the quotient and subtract the result from the original dividend.
- Repeat the process with the new polynomial until the remainder becomes less than the degree of the divisor.
Quotient
The quotient in polynomial division is the resulting polynomial that you get when you divide the dividend by the divisor. In our example, after performing the long division on the given polynomials, we arrived at the quotient of the division: \(3x + 1\).
Here’s how the quotient is determined:
Here’s how the quotient is determined:
- Begin by dividing the leading term of the dividend by the leading term of the divisor. For instance, \(\frac{6x^3}{2x^2} = 3x\), which is the first term of our quotient.
- Multiply the entire divisor by this first quotient term and subtract it from the original polynomial.
- Repeat these steps with any remaining terms after subtraction.
Remainder
In polynomial division, the remainder is what is left over after performing the long division process when no more terms of the quotient can be obtained. In our case, after dividing, the remainder turned out to be \(7x - 5\).
Understanding the remainder involves:
Understanding the remainder involves:
- Attempting to divide the remaining polynomial by the divisor.
- If the degree of the remaining polynomial is less than that of the divisor, then no further division is possible—this leftover portion is the remainder.
Leading Term
The leading term is the term in a polynomial with the highest degree, which usually means it is the term with the largest exponent of the variable. Identifying the leading term is crucial in the division process because it determines how the division proceeds.
During polynomial long division:
During polynomial long division:
- We use the leading term of both the dividend and the divisor to calculate the first term of the quotient.
- This ensures that we are systematically eliminating the terms in the dividend from highest to lowest power.
- In our example, at first, we took the leading term \(6x^3\) from the dividend and divided by the leading term \(2x^2\) from the divisor.
Other exercises in this chapter
Problem 21
Find all rational zeros of the polynomial, and write the polynomial in factored form. $$ P(x)=x^{3}-4 x^{2}+x+6 $$
View solution Problem 21
Find all horizontal and vertical asymptotes (if any). $$ r(x)=\frac{5}{x-2} $$
View solution Problem 21
Factor the polynomial completely, and find all its zeros. State the multiplicity of each zero. \(P(x)=x^{3}+4 x\)
View solution Problem 21
\(15-26\) Sketch the graph of the polynomial function. Make sure your graph shows all intercepts and exhibits the proper end behavior. $$ P(x)=(x-1)^{2}(x-3) $$
View solution