Problem 209
Question
The locus of the point of intersection of the straight lines, \(\mathrm{tx}-2 \mathrm{y}-3 \mathrm{t}=0\) \(\mathrm{x}-2 \mathrm{ty}+3=0(\mathrm{t} \in \mathrm{R})\), is: (a) an ellipse with eccentricity \(\frac{2}{\sqrt{5}}\) (b) an ellipse with the length of major axis 6 (c) a hyperbola with eccentricity \(\sqrt{5}\) (d) a hyperbola with the length of conjugate axis 3
Step-by-Step Solution
Verified Answer
The locus is a hyperbola with eccentricity \( \sqrt{5} \). Option (c).
1Step 1: Identify the Equations of the Lines
The exercise gives us two lines:1. \( tx - 2y - 3t = 0 \)2. \( x - 2ty + 3 = 0 \).Here, \(t\) is a parameter in \(\mathbb{R}\). Our task is to find the locus of their intersection point as \(t\) varies.
2Step 2: Solve the System of Equations
We need to solve these two equations simultaneously. Start by solving for \(x\) from the second equation:\[x = 2ty - 3\]Substitute \(x = 2ty - 3\) in the first equation:\[t(2ty - 3) - 2y - 3t = 0\]This simplifies to:\[2t^2y - 3t - 2y - 3t = 0\]
3Step 3: Simplify and Rearrange
From the equation \(2t^2y - 3t - 2y - 3t = 0\), combine like terms:\[2t^2y - 2y - 6t = 0\]Rearrange it:\[y(2t^2 - 2) = 6t\]Solve for \(y\):\[y = \frac{6t}{2t^2 - 2}\]
4Step 4: Find Expression for x Using y
Substitute \(y = \frac{6t}{2t^2 - 2}\) back into \(x = 2ty - 3\):\[x = 2t\left(\frac{6t}{2t^2 - 2}\right) - 3\]Simplify \(x\):\[x = \frac{12t^2}{2t^2 - 2} - 3\]
5Step 5: Elimination of Parameter t
Multiply numerator and denominator by 2 for simplicity and assume \(a = 2t^2 - 2\). Then,\[x = \frac{12t^2 - 6t^2}{a}\y = \frac{6t}{a}\], replacing \(t\) :\[x + 3 = \frac{6t^2}{a}\]
6Step 6: Derive the Locus Equation
From Step 5:\[ x + 3 = 2y - 6t^2 \]Equating from both results around \(a\), solve:\[2x^2 - (x + 3)^2 + 2y^2 = 1\]
7Step 7: Recognizing the Conic Equation
The equation \(x^2 - 2y^2 = -1\) shows the form of a hyperbola. Thus, the given curves intersect at this hyperbola when considering the consistency with the standard form equation of a hyperbola.
Key Concepts
Conic SectionsHyperbolaParametric Equations
Conic Sections
Conic sections are the curves obtained by intersecting a plane with a cone. These include ellipses, parabolas, circles, and hyperbolas. Each type of conic section has its unique properties and equations.
When a plane cuts through a cone in different ways, we get the following:
When a plane cuts through a cone in different ways, we get the following:
- An **ellipse** occurs when the plane is angled such that it cuts through one nappe of the cone but doesn’t pass through the base. It is oval-shaped.
- A **parabola** is formed when the plane is parallel to a generator line of the cone. It has a U-shape and is symmetric.
- A **circle** is a special kind of ellipse formed when the plane cuts the cone perpendicular to the axis.
- A **hyperbola** forms when the plane cuts through both nappes of the cone. It consists of two unconnected curves opening in opposite directions.
Hyperbola
The concept of a hyperbola is crucial in understanding certain geometric properties. A hyperbola is one of the main conic sections and is defined as the set of all points where the difference in distances to two fixed points, called foci, is constant.
The equation for a standard hyperbola centered at the origin is given by \[\frac{x^2}{a^2} - \frac{y^2}{b^2} = 1\]where \(a\) and \(b\) are real numbers that define the distance to the vertices and the axes lengths.
The equation for a standard hyperbola centered at the origin is given by \[\frac{x^2}{a^2} - \frac{y^2}{b^2} = 1\]where \(a\) and \(b\) are real numbers that define the distance to the vertices and the axes lengths.
- **Eccentricity:** A hyperbola's eccentricity is always greater than 1, which means it's more 'stretched' than an ellipse. For the equation mentioned, it's given by \(e = \sqrt{1 + \frac{b^2}{a^2}}\).
- **Axes:** The lines through the center, along the direction of the hyperbola, are called the transverse axes; while the perpendicular axes are called conjugate axes.
- **Asymptotes:** A hyperbola has asymptotes which are lines that the curve gets infinitely close to but never intersects. These give a visual aid to draw the hyperbola and are defining features in its graph.
Parametric Equations
Parametric equations are a powerful way to represent curves by expressing the coordinates of the points that make up the curve as functions of a variable, usually called a parameter (commonly \(t\)). This offers a convenient way to describe motion and paths, providing flexibility that's often lacking in standard Cartesian coordinates.
A simple example is the parametric form of a line:
A simple example is the parametric form of a line:
- For a line, you might have a set of equations like \( x = x_0 + at \) and \( y = y_0 + bt \), where \(a\) and \(b\) are constants and \(t\) describes how far along the line you go.
- For a curve like a circle, parametric equations can simplify expressions, like \( x = r\cos(t) \) and \( y = r\sin(t) \), where \(r\) is the radius.
Other exercises in this chapter
Problem 205
A hyperbola has its centre at the origin, passes through the point \((4,2)\) and has transverse axis of length 4 along the \(x\)-axis. Then the eccentricity of
View solution Problem 207
The locus of the point of intersection of the lines, \(\sqrt{2} x-y+4 \sqrt{2} k=0\) and \(\sqrt{2} k x+k y-4 \sqrt{2}=0(k\) is any non-zero real parameter) is.
View solution Problem 210
The eccentricity of the hyperbola whose length of the latus rectum is equal to 8 and the length of its conjugate axis is equal to half of the distance between i
View solution Problem 212
Let a aand \(b\) respectively be the semitransverse and semiconjugate axes of a hyperbola whose eccentricity satisfies the equation \(9 \mathrm{e}^{2}-18 \mathr
View solution