Problem 208
Question
Using MO theory predict which of the following species has the shortest bond length? [2009] (a) \(\mathrm{O}_{2}^{+}\) (b) \(\mathrm{O}_{2}^{-}\) (c) \(\mathrm{O}_{2}^{2}{\underline{\phantom{xx}}}^{2-}\) (d) \(\mathrm{O}_{2}^{2+}\)
Step-by-Step Solution
Verified Answer
\(\mathrm{O}_{2}^{2+}\) has the shortest bond length.
1Step 1: Understanding Bond Order
Bond order is directly related to bond length; the higher the bond order, the shorter the bond length. In Molecular Orbital (MO) theory, bond order is calculated using the formula: \(\text{Bond Order} = \frac{(\text{number of bonding electrons}) - (\text{number of antibonding electrons})}{2}\).
2Step 2: Electron Configurations for Given Species
Assign the total number of electrons for each species based on their charges:\- \(\mathrm{O}_2\) has 16 electrons. \- \(\mathrm{O}_{2}^{+}\) has 15 electrons. \- \(\mathrm{O}_{2}^{-}\) has 17 electrons. \- \(\mathrm{O}_{2}^{2-}\) has 18 electrons. \- \(\mathrm{O}_{2}^{2+}\) has 14 electrons.
3Step 3: Determine MO Electron Configuration
Write out the MO electron configurations: \- \(\mathrm{O}_{2}^{+}\) (15 electrons): \([\sigma(1s)^2][\sigma^*(1s)^2][\sigma(2s)^2][\sigma^*(2s)^2] [\sigma(2p_z)^2][\pi(2p_x)^2][\pi(2p_y)^2][\pi^*(2p_x)^2][\pi^*(2p_y)^1]\) \- \(\mathrm{O}_{2}^{-}\) (17 electrons): \([\sigma(1s)^2][\sigma^*(1s)^2][\sigma(2s)^2][\sigma^*(2s)^2] [\sigma(2p_z)^2][\pi(2p_x)^2][\pi(2p_y)^2][\pi^*(2p_x)^2][\pi^*(2p_y)^3]\) \- \(\mathrm{O}_{2}^{2-}\) (18 electrons): \([\sigma(1s)^2][\sigma^*(1s)^2][\sigma(2s)^2][\sigma^*(2s)^2] [\sigma(2p_z)^2][\pi(2p_x)^2][\pi(2p_y)^2][\pi^*(2p_x)^2][\pi^*(2p_y)^4]\) \- \(\mathrm{O}_{2}^{2+}\) (14 electrons): \([\sigma(1s)^2][\sigma^*(1s)^2][\sigma(2s)^2][\sigma^*(2s)^2] [\sigma(2p_z)^2][\pi(2p_x)^2][\pi(2p_y)^2]\) \Fill them into bonding \((\sigma, \pi)\) and antibonding \((\sigma^*, \pi^*)\) orbitals.
4Step 4: Calculation of Bond Order
Calculate the bond order for each species: \- \(\mathrm{O}_{2}^{+}\): Bond order = \((8 - 3)/2 = 2.5\) \- \(\mathrm{O}_{2}^{-}\): Bond order = \((8 - 5)/2 = 1.5\) \- \(\mathrm{O}_{2}^{2-}\): Bond order = \((8 - 6)/2 = 1.0\) \- \(\mathrm{O}_{2}^{2+}\): Bond order = \((8 - 2)/2 = 3.0\)
5Step 5: Conclusion Based on Bond Order
The species with the highest bond order will have the shortest bond length. Therefore, among the given species, \(\mathrm{O}_{2}^{2+}\) with a bond order of 3.0 has the shortest bond length.
Key Concepts
Bond OrderBond LengthElectron ConfigurationIonic SpeciesOxygen Species
Bond Order
Bond order is a fundamental concept in Molecular Orbital (MO) Theory. It indicates the stability and strength of a bond between atoms in a molecule.
To calculate bond order, use this formula:
\[ \text{Bond Order} = \frac{(\text{number of bonding electrons}) - (\text{number of antibonding electrons})}{2} \]The bond order tells us how many chemical bonds exist between a pair of atoms.
By contrast, \( \mathrm{O}_2^{2-} \) has a bond order of 1.0, indicating only a single bond.
This connection between bond order and bond strength is essential when predicting molecular characteristics like bond length.
To calculate bond order, use this formula:
\[ \text{Bond Order} = \frac{(\text{number of bonding electrons}) - (\text{number of antibonding electrons})}{2} \]The bond order tells us how many chemical bonds exist between a pair of atoms.
- A higher bond order suggests a stronger, more stable bond.
- A low bond order can suggest a weaker bond.
- If the bond order equals zero, the bond does not exist.
By contrast, \( \mathrm{O}_2^{2-} \) has a bond order of 1.0, indicating only a single bond.
This connection between bond order and bond strength is essential when predicting molecular characteristics like bond length.
Bond Length
Bond length is the distance between the nuclei of two bonded atoms. It changes with different bond orders.
A higher bond order generally means a shorter bond length.
Therefore, these distances are a useful factor in determining the strength and stability of a molecule.
A higher bond order generally means a shorter bond length.
- Shorter bonds are typically stronger and more stable.
- Longer bonds are weaker and less stable.
- \( \mathrm{O}_2^{2+} \) has a bond order of 3.0, resulting in a very short bond length.
- \( \mathrm{O}_2^{2-} \) has a bond order of 1.0, leading to a longer bond length.
Therefore, these distances are a useful factor in determining the strength and stability of a molecule.
Electron Configuration
In Molecular Orbital Theory, the electron configuration of molecules helps us understand which electrons are present in bonding and antibonding orbitals.
This configuration is crucial for predicting molecular properties, such as bond order and bond length.
For molecules like oxygen species, the sequence of filling orbitals goes as follows:
\([\sigma(1s)^2][\sigma^*(1s)^2][\sigma(2s)^2][\sigma^*(2s)^2][\sigma(2p_z)^2][\pi(2p_x)^2][\pi(2p_y)^2]\)
Meanwhile, \( \mathrm{O}_2^{2+} \), with empty \( \pi^* \) orbitals, has a higher bond order of 3.0.
Understanding these configurations aids in visualizing how molecules will behave and interact.
This configuration is crucial for predicting molecular properties, such as bond order and bond length.
For molecules like oxygen species, the sequence of filling orbitals goes as follows:
\([\sigma(1s)^2][\sigma^*(1s)^2][\sigma(2s)^2][\sigma^*(2s)^2][\sigma(2p_z)^2][\pi(2p_x)^2][\pi(2p_y)^2]\)
- Bonding orbitals (\( \sigma, \pi \)) increase molecule stability.
- Antibonding orbitals (\( \sigma^*, \pi^* \)) decrease stability.
Meanwhile, \( \mathrm{O}_2^{2+} \), with empty \( \pi^* \) orbitals, has a higher bond order of 3.0.
Understanding these configurations aids in visualizing how molecules will behave and interact.
Ionic Species
Ionic species have an unequal amount of protons and electrons, resulting in a net charge. In Molecular Orbital Theory, ionic species can affect bond characteristics.
For example, when analyzing oxygen species, changes in ionic charges alter electron counts and subsequently bond orders.
The neutral species \( \mathrm{O}_2 \) possesses 16 electrons, while its ionic counterparts differ.
Studying ionic species is crucial for a comprehensive understanding of molecular behavior as it helps explain variances in chemical and physical properties due to electron arrangement.
For example, when analyzing oxygen species, changes in ionic charges alter electron counts and subsequently bond orders.
- \( \mathrm{O}_2^{+} \): One electron removed, leading to 15 electrons.
- \( \mathrm{O}_2^{-} \): One electron added, leading to 17 electrons.
The neutral species \( \mathrm{O}_2 \) possesses 16 electrons, while its ionic counterparts differ.
Studying ionic species is crucial for a comprehensive understanding of molecular behavior as it helps explain variances in chemical and physical properties due to electron arrangement.
Oxygen Species
Oxygen species, especially in their molecular forms like \( \mathrm{O}_2 \) and its ionic counterparts, play a vital role in chemistries like respiration and combustion.
In chemistry, analyzing oxygen species through MO Theory provides insights into their reactivity and stability.
This impacts their chemical behavior and interactions. Molecular Orbital Theory enables us to predict these peculiarities accurately, aiding in experimental and theoretical chemistry.
In chemistry, analyzing oxygen species through MO Theory provides insights into their reactivity and stability.
- \( \mathrm{O}_2 \): A neutral molecule often exhibiting a double bond.
- \( \mathrm{O}_2^{+}, \mathrm{O}_2^{-}, \mathrm{O}_2^{2+}, \mathrm{and} \mathrm{O}_2^{2-} \): Variants with different charges and electron configurations.
This impacts their chemical behavior and interactions. Molecular Orbital Theory enables us to predict these peculiarities accurately, aiding in experimental and theoretical chemistry.
Other exercises in this chapter
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