Problem 207
Question
Suppose you have six quarters, nine dimes, and four pennies. Explain how you find the total value of all the coins.
Step-by-Step Solution
Verified Answer
The total value of the coins is 244 cents.
1Step 1: Convert Quarters to Cents
Each quarter is worth 25 cents. Multiply the number of quarters (6) by 25.\[\text{Value of quarters} = 6 \times 25 = 150 \text{ cents}\]
2Step 2: Convert Dimes to Cents
Each dime is worth 10 cents. Multiply the number of dimes (9) by 10.\[\text{Value of dimes} = 9 \times 10 = 90 \text{ cents}\]
3Step 3: Convert Pennies to Cents
Each penny is worth 1 cent. Multiply the number of pennies (4) by 1.\[\text{Value of pennies} = 4 \times 1 = 4 \text{ cents}\]
4Step 4: Sum the Total Value
Add the values of quarters, dimes, and pennies to find the total value.\[\text{Total value} = 150 + 90 + 4 = 244 \text{ cents}\]
Key Concepts
Basic ArithmeticConversion of UnitsSum CalculationElementary Algebra
Basic Arithmetic
In this exercise, basic arithmetic plays a crucial role. To find out the value of each type of coin, we use multiplication and addition. Multiplication helps us determine the total value of a group of coins. Add up these values to get the final sum.
For example, multiplying the number of quarters (6) by 25 gives us 150 cents. Next, multiplying the number of dimes (9) by 10 gives us 90 cents. And multiplying the number of pennies (4) by 1 gives us 4 cents.
Once these values are calculated, we use addition to find the total value. Adding 150, 90, and 4 together gives us 244 cents.
For example, multiplying the number of quarters (6) by 25 gives us 150 cents. Next, multiplying the number of dimes (9) by 10 gives us 90 cents. And multiplying the number of pennies (4) by 1 gives us 4 cents.
Once these values are calculated, we use addition to find the total value. Adding 150, 90, and 4 together gives us 244 cents.
Conversion of Units
Understanding the value of different coins requires converting each type of coin into the same unit, which is cents in this exercise.
For dimes, each worth 10 cents, nine dimes are 9 times 10, which is 90 cents.
Pennies remain as they are, with four pennies giving 4 times 1 cent, resulting in 4 cents.
By converting all values to the same unit (cents), we can simplify the final calculation of their total value.
- Quarters need to be converted into cents.
- Dimes also need to be converted into cents.
- Pennies are already in cents.
For dimes, each worth 10 cents, nine dimes are 9 times 10, which is 90 cents.
Pennies remain as they are, with four pennies giving 4 times 1 cent, resulting in 4 cents.
By converting all values to the same unit (cents), we can simplify the final calculation of their total value.
Sum Calculation
To find the total value of the coins, we need to sum up the results from our conversions:
\[150 + 90 + 4 = 244 \text{ cents} \] Breaking down the process like this ensures that we don't miss any steps and that our calculations are accurate. It's also a good practice to double-check your additions, especially in more complex problems.
- Value of quarters: 150 cents
- Value of dimes: 90 cents
- Value of pennies: 4 cents
\[150 + 90 + 4 = 244 \text{ cents} \] Breaking down the process like this ensures that we don't miss any steps and that our calculations are accurate. It's also a good practice to double-check your additions, especially in more complex problems.
Elementary Algebra
Algebra helps to generalize and solve problems like these efficiently. Let's represent the number of quarters, dimes, and pennies as variables:
\[ \text{Value of quarters} = q \times 25 = 6 \times 25 = 150 \text{ cents} \] \[ \text{Value of dimes} = d \times 10 = 9 \times 10 = 90 \text{ cents} \] \[ \text{Value of pennies} = p \times 1 = 4 \times 1 = 4 \text{ cents} \] Substituting these back, we can set up our total value calculation:
\[ \text{Total value} = 150 + 90 + 4 = 244 \text{ cents} \] Using algebra in this way streamlines the problem-solving process, making it easier to see relationships and patterns.
- Let \( q = 6 \) (number of quarters)
- Let \( d = 9 \) (number of dimes)
- Let \( p = 4 \) (number of pennies)
\[ \text{Value of quarters} = q \times 25 = 6 \times 25 = 150 \text{ cents} \] \[ \text{Value of dimes} = d \times 10 = 9 \times 10 = 90 \text{ cents} \] \[ \text{Value of pennies} = p \times 1 = 4 \times 1 = 4 \text{ cents} \] Substituting these back, we can set up our total value calculation:
\[ \text{Total value} = 150 + 90 + 4 = 244 \text{ cents} \] Using algebra in this way streamlines the problem-solving process, making it easier to see relationships and patterns.
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