Problem 207
Question
$$ \lim _{x \rightarrow 3} \frac{x-3}{|x-3|} \text { . }\\{\text { Ans. } 1,-1\\} $$
Step-by-Step Solution
Verified Answer
The limit of the function \(\frac{x - 3}{|x - 3|}\) as \(x\) approaches 3 does not exist.
1Step 1 - Consider the Function for \(x < 3\)
When \(x < 3\), \(x - 3 < 0\), therefore, \(|x - 3| = -(x - 3)\). So, the function becomes \(\frac{x - 3}{-(x - 3)} = -1\) for all \(x < 3\).
2Step 2 - Limit of the Function for \(x < 3\)
We calculate the left-hand limit as \(x\) approaches 3 from the left side. It's simply the constant value at all such \(x\) which implies \(\lim_{x \rightarrow 3^-} \frac{x - 3}{|x - 3|} = -1\).
3Step 3 - Consider the Function for \(x > 3\)
When \(x > 3\), \(x - 3 > 0\), therefore, \(|x - 3| = x - 3\). So, the function becomes \(\frac{x - 3}{x - 3} = 1\) for all \(x > 3\).
4Step 4 - Limit of the Function for \(x > 3\)
We calculate the right-hand limit as \(x\) approaches 3 from the right side. It's simply the constant value at all such \(x\) which implies \(\lim_{x \rightarrow 3^+} \frac{x - 3}{|x - 3|} = 1\).
5Step 5 - Comparing Left-Hand Limit and Right-Hand Limit
The left-hand limit does not match the right-hand limit. Therefore, the limit of the function at \(x = 3\) does not exist.
Key Concepts
ContinuityOne-sided limitsPiecewise functions
Continuity
Continuity is an essential concept when analyzing functions and their behavior at specific points. A function is said to be continuous at a point if its graph is unbroken at that point. In mathematical terms, a function \( f(x) \) is continuous at a point \( c \) if the following three conditions are satisfied:
- The function \( f(x) \) is defined at \( x = c \).
- The limit of \( f(x) \) as \( x \) approaches \( c \) exists.
- The limit of \( f(x) \) as \( x \) approaches \( c \) is equal to \( f(c) \).
One-sided limits
Understanding one-sided limits is crucial for analyzing the behavior of functions as they get closer to a particular point from one direction only. One-sided limits include the left-hand limit and the right-hand limit:
- The left-hand limit \( \lim_{x \to c^-} f(x) \) describes the behavior of \( f(x) \) as \( x \) approaches \( c \) from the left, or lower values.
- The right-hand limit \( \lim_{x \to c^+} f(x) \) describes the behavior of \( f(x) \) as \( x \) approaches \( c \) from the right, or greater values.
Piecewise functions
Piecewise functions are defined by different expressions over different intervals. These functions are particularly useful for representing situations where a rule or definition changes, offering flexibility in mathematical models. Each segment of the domain is handled by a specific piece of the function.
In our given problem, the function \( \frac{x - 3}{|x - 3|} \) behaves like a piecewise function around \( x = 3 \). The expression is split into two parts:
In our given problem, the function \( \frac{x - 3}{|x - 3|} \) behaves like a piecewise function around \( x = 3 \). The expression is split into two parts:
- For \( x < 3 \), the function is \( -1 \), as derived from the calculation \( \frac{x - 3}{-(x - 3)} \).
- For \( x > 3 \), the function evaluates to \( 1 \), as shown by \( \frac{x - 3}{x - 3} \).
Other exercises in this chapter
Problem 205
$$ \left.\lim _{x \rightarrow 0} \frac{\sin x}{\sqrt{x^{2}}} \text { . \\{Ans. } 1,-1\right\\} $$
View solution Problem 206
$$ \lim _{x \rightarrow 0}(1+a x)^{\frac{b}{x}} .\left\\{\text { Ans. } e^{a b}\right\\} $$
View solution Problem 208
$$ \left.\lim _{x \rightarrow 0}\left(\frac{1+\tan x}{1+\sin x}\right)^{\frac{1}{3 x}} \text { \\{Ans. } 1\right\\} $$
View solution Problem 209
$$ \lim _{x \rightarrow 1}(1+\sin \pi x)^{\cot \pi x}\left\\{\text { Ans. } \frac{1}{c}\right\\} $$
View solution