Problem 20
Question
Write the rational expression in simplest form.\(\frac{24 y^{3}}{56 y^{7}}\)
Step-by-Step Solution
Verified Answer
The simplified form of \(\frac{24 y^{3}}{56 y^{7}}\) is \(\frac{3}{7y^{4}}\).
1Step 1: Factoring the Numerator and Denominator
Firstly, the numerator and denominator of the fraction need to be factored out. Thus, \(\frac{24 y^{3}}{56 y^{7}}\) can be factored out as \(\frac{2^3*3*y^{3}}{2^3*7*y^{7}}\).
2Step 2: Cancel Out the Common Terms
From here, we are able to cancel out the common terms. We are left with \(\frac{3}{7*y^{4}}\). The power difference between \(y^7\) in the denominator and \(y^3\) in the numerator becomes \(y^4\) in the simplified expression.
3Step 3: Final Simplified Form
After cancelling out the common terms, the simplified rational expression is \(\frac{3}{7y^{4}}\). This is the simplest form of the original rational expression.
Key Concepts
Factoring PolynomialsExponents and PowersFraction Simplification
Factoring Polynomials
When working with rational expressions, one of the first and most crucial steps is factoring polynomials found in both the numerator and the denominator. Factoring involves breaking down a number or expression into its constituent elements, known as factors. For instance, in the original expression \(\frac{24y^{3}}{56y^{7}}\), we start by recognizing that 24 and 56 can be divided into smaller factors.
- 24 can be factored into \(2^3 \times 3\).
- 56 can be factored into \(2^3 \times 7\).
- For the polynomial parts, \(y^3\) and \(y^7\) are the powers of \(y\).
Exponents and Powers
Exponents and powers are fundamental concepts in mathematics that help us express repeated multiplication concisely. In the expression \(\frac{24y^{3}}{56y^{7}}\), the exponents help track the number of times the base, \(y\), is multiplied by itself. For instance, \(y^{3}\) means \(y\times y\times y\).
When simplifying rational expressions with terms that have exponents, such as \(y^3\) and \(y^7\), we use the laws of exponents. One of the key rules is that when dividing like bases, you subtract the exponents: \(a^m/a^n = a^{m-n}\). Thus, \(y^7\) divided by \(y^3\) becomes \(y^{7-3} = y^4\).
This process shows how understanding the laws of exponents allows us to simplify expressions by reducing the powers and making calculations more manageable.
When simplifying rational expressions with terms that have exponents, such as \(y^3\) and \(y^7\), we use the laws of exponents. One of the key rules is that when dividing like bases, you subtract the exponents: \(a^m/a^n = a^{m-n}\). Thus, \(y^7\) divided by \(y^3\) becomes \(y^{7-3} = y^4\).
This process shows how understanding the laws of exponents allows us to simplify expressions by reducing the powers and making calculations more manageable.
Fraction Simplification
Simplifying fractions involves reducing them to their simplest form so that they are easier to understand and use. In the context of rational expressions like \(\frac{24y^{3}}{56y^{7}}\), simplification happens after factoring out common bases in both the numerator and the denominator.
- After factoring as \(\frac{2^3\times 3\times y^3}{2^3\times 7\times y^7}\), we can cancel out \(2^3\) and common powers of \(y\).
- This results in \(\frac{3}{7y^{4}}\), where neither the numerator nor the denominator can be reduced further.
Other exercises in this chapter
Problem 20
Evaluate the expression when \(x=3, y=-2\), and \(z=4$$z^{2}\) ? \(6 y-x\)
View solution Problem 20
Use a calculator to order the numbers from least to greatest.\(\frac{559}{500}, 1.12, \frac{\sqrt{5}}{2}, \frac{115}{99}, \frac{23}{20}\)
View solution Problem 20
Perform the indicated operation(s) and write the resulting polynomial in standard form.\(-\left(5 x^{2}-1\right)+\left(-3 x^{2}+5\right)\)
View solution Problem 21
Factor the sum or difference of cubes.\(y^{3}+125\)
View solution