Problem 20
Question
Write down a formula for the population size, \(N_{t}\), as a function of time, \(t\). Find the exponential growth equation for a population that triples in size every unit of time and that has 72 individuals at time 0 .
Step-by-Step Solution
Verified Answer
The formula is \(N_t = 72 \cdot 3^t\).
1Step 1: Understand the Problem
We need to find a formula of population size \(N_t\) as a function of time \(t\). The population triples every unit time and starts with 72 individuals at \(t = 0\).
2Step 2: Exponential Growth Formula
The general formula for exponential growth is \(N_t = N_0 \cdot a^t\), where \(N_0\) is the initial population, \(a\) is the growth factor, and \(t\) is time.
3Step 3: Determine Growth Factor
Since the population triples every unit of time, the growth factor \(a = 3\). Therefore, the proper growth factor in our formula is \(3\).
4Step 4: Write the Specific Formula
Substitute the initial population \(N_0 = 72\) and the growth factor \(a = 3\) into the formula from Step 2: \[N_t = 72 \cdot 3^t\].
5Step 5: Verify the Formula
Check that \(N_0 = 72\) at \(t = 0\). When \(t = 0\), \(N_t = 72 \cdot 3^0 = 72 \cdot 1 = 72\), confirming the initial population is correct.
Key Concepts
Population Size FormulaGrowth FactorInitial Population
Population Size Formula
When dealing with exponential growth scenarios, the population size formula is fundamental. This formula helps us model how populations change over time. It goes like this: the population at time \( t \), noted as \( N_t \), is equal to the initial population \( N_0 \) multiplied by the growth factor \( a \), raised to the power of the time \( t \). It is written as:\[N_t = N_0 \cdot a^t\]
- \( N_0 \): the initial population size, which is where it all begins, at time \( t = 0 \).
- \( a \): the growth factor that influences how much the population increases every time interval.
- \( t \): the time that has passed since the beginning of the observation.
Growth Factor
The growth factor is crucial to understanding exponential growth. It represents how many times the population multiplies over a single time unit. In our problem, we've learned that the population triples every unit of time. This means if you have 72 individuals to start, one time unit later you will have three times that amount.In formula terms, the growth factor \( a \) is 3. This means at each time step:
- The population isn't just increasing by the same number each time; it's multiplying.
- Because the growth is exponential, each passing time unit sees the population grow based on its current size, multiplying by 3.
Initial Population
The initial population \( N_0 \) is the starting size of the population we're examining. It's the number of individuals you have before any time has passed, specifically at \( t = 0 \). This value serves as the baseline in our exponential growth formula.In the given exercise, we're informed that the initial population is 72 individuals. This number is pivotal because it gives us a starting point to apply the exponential growth process.
- Without knowing \( N_0 \), we couldn't calculate the future population sizes accurately.
- Each subsequent population size is a reflection of not only the growth factor but also this initial figure.
Other exercises in this chapter
Problem 20
Assume that the population growth is described by the Beverton-Holt recruitment curve with parameters \(R_{0}\) and a. Find the population sizes for \(t=1,2, \l
View solution Problem 20
Find the next four values of the sequence \(\left\\{a_{n}\right\\}\) on the basis of the values of \(a_{0}, a_{1}, a_{2}, a_{3}, a_{4}\). $$ -1, \frac{1}{4},-\f
View solution Problem 21
Assume that the population growth is described by the Beverton-Holt recruitment curve with parameters \(R_{0}\) and a. Find the population sizes for \(t=1,2, \l
View solution Problem 21
Find the next four values of the sequence \(\left\\{a_{n}\right\\}\) on the basis of the values of \(a_{0}, a_{1}, a_{2}, a_{3}, a_{4}\). $$ \frac{1}{2}, \frac{
View solution