Problem 20
Question
Which one of the following statement is correct? (a) Bronsted-Lowry theory could not explain the acidic nature of \(\mathrm{BCl}_{3}\) (b) the \(\mathrm{pH}\) of \(0.01 \mathrm{M} \mathrm{NaOH}\) solution is 2 (c) the ionic product of water at \(25^{\circ} \mathrm{C}\) is \(10^{-10} \mathrm{~mol}^{2} \mathrm{~L}^{-2}\) (d) the \(\mathrm{pH}\) of a solution can be calculated using the equation \(\mathrm{pH}=\log \left[\mathrm{H}^{+}\right]\)
Step-by-Step Solution
Verified Answer
The correct statement is (a) Bronsted-Lowry theory could not explain the acidic nature of \( \mathrm{BCl}_3 \).
1Step 1: Analyzing Statement (a)
The Bronsted-Lowry theory defines acids as proton donors. \( \mathrm{BCl}_3 \) does not donate a proton; instead, it accepts an electron pair due to its electron deficiency. Therefore, Bronsted-Lowry theory cannot explain the acidity of \( \mathrm{BCl}_3 \). So statement (a) is correct.
2Step 2: Analyzing Statement (b)
The \( \mathrm{pH} \) of a \(0.01\, \mathrm{M}\) \( \mathrm{NaOH} \) solution can be calculated by first determining the \( \mathrm{pOH} \). \( \mathrm{pOH} = -\log[\mathrm{OH}^-] \), so \( \mathrm{pOH} = -\log(0.01) = 2 \). Since \( \mathrm{pH} + \mathrm{pOH} = 14 \), \( \mathrm{pH} = 14 - 2 = 12 \). Statement (b) is incorrect.
3Step 3: Analyzing Statement (c)
The ionic product of water \( \mathrm{K_w} \) at \(25^{\circ} \mathrm{C} \) is typically \(1.0 \times 10^{-14} \, \mathrm{mol}^2 \, \mathrm{L}^{-2}\). Therefore, \(10^{-10} \, \mathrm{mol}^2 \, \mathrm{L}^{-2}\) is incorrect for the ionic product of water. Statement (c) is incorrect.
4Step 4: Analyzing Statement (d)
The correct equation to find the \( \mathrm{pH} \) of a solution is \( \mathrm{pH} = -\log[\mathrm{H}^+] \). Therefore, statement (d) is incorrect.
Key Concepts
Bronsted-Lowry TheorypH CalculationIonic Product of WaterBoron Trichloride (BCl3)
Bronsted-Lowry Theory
The Bronsted-Lowry theory is a fundamental concept in acid-base chemistry. It defines acids and bases based on their ability to donate or accept a proton (H").
According to this theory:
This theory, however, does not address substances that are not involved in proton transfer, such as boron trichloride (BCl₃).
BCl₃ is known to be acidic because it accepts an electron pair, rather than donating a proton.
This is why the Bronsted-Lowry theory cannot fully describe the acidic nature of BCl₃, which is more accurately explained by the Lewis acid-base theory.
According to this theory:
- An acid is a proton donor - it donates an H".
- A base is a proton acceptor - it receives an H".
This theory, however, does not address substances that are not involved in proton transfer, such as boron trichloride (BCl₃).
BCl₃ is known to be acidic because it accepts an electron pair, rather than donating a proton.
This is why the Bronsted-Lowry theory cannot fully describe the acidic nature of BCl₃, which is more accurately explained by the Lewis acid-base theory.
pH Calculation
pH calculation is crucial for understanding the acidity or basicity of a solution. The pH scale ranges from 0 to 14, with pH 7 being neutral, values below 7 acidic, and above 7 basic.
The formula to calculate the pH of a solution is:
Since NaOH is a strong base, it dissociates completely, giving a hydroxide ion concentration [OH⁻] of 0.01 M.
The pOH is calculated as:
It's crucial to remember that negative logarithms can result in a bit of a mind-bender conceptually, which makes understanding the idea behind pH calculations vital.
The formula to calculate the pH of a solution is:
- \( \mathrm{pH} = -\log [\mathrm{H}^+] \)
Since NaOH is a strong base, it dissociates completely, giving a hydroxide ion concentration [OH⁻] of 0.01 M.
The pOH is calculated as:
- \( \mathrm{pOH} = -\log [\mathrm{OH}^-] \), which equals \( \mathrm{pOH} = 2 \)
It's crucial to remember that negative logarithms can result in a bit of a mind-bender conceptually, which makes understanding the idea behind pH calculations vital.
Ionic Product of Water
The ionic product of water, represented by \( K_w \), is a key concept in acid-base chemistry. It signifies the equilibrium constant for the ionization of water, describing the self-ionization property.
In pure water, at 25°C, the reaction is expressed as:
When calculating the pH or pOH of a solution, this value is a constant used to express the relationship between hydrogen ions \( [\mathrm{H}^+] \) and hydroxide ions \( [\mathrm{OH}^-] \).
Any significant deviation from this value at standard conditions indicates unique solute effects or temperature changes.
In pure water, at 25°C, the reaction is expressed as:
- \( 2 \text{H}_2\text{O} \rightleftharpoons \text{H}_3\text{O}^+ + \text{OH}^- \)
- \( K_w = [\mathrm{H}^+][\mathrm{OH}^-] \)
When calculating the pH or pOH of a solution, this value is a constant used to express the relationship between hydrogen ions \( [\mathrm{H}^+] \) and hydroxide ions \( [\mathrm{OH}^-] \).
Any significant deviation from this value at standard conditions indicates unique solute effects or temperature changes.
Boron Trichloride (BCl3)
Boron trifluoride, or \( BCl_3 \), is an intriguing compound in the study of acid-base chemistry. Its behavior does not conform to the classical Bronsted-Lowry definition, where an acid is defined as a proton donor.
\( BCl_3 \) acts as a Lewis acid, which is defined as an electron pair acceptor.
Lewis theory broadens the definition of acids and bases beyond proton transfer, accommodating compounds like \( BCl_3 \) and providing a more inclusive insight into chemical reactivity.
\( BCl_3 \) acts as a Lewis acid, which is defined as an electron pair acceptor.
- In \( BCl_3 \), the boron atom lacks a full octet, making it electron-deficient, which explains its ability to accept an electron pair from a donor molecule, such as water or ammonia.
- This electron-pair acceptance leads to reactions, forming adducts, that do not involve the transfer of protons, distinguishing it from typical Bronsted-Lowry reactions.
Lewis theory broadens the definition of acids and bases beyond proton transfer, accommodating compounds like \( BCl_3 \) and providing a more inclusive insight into chemical reactivity.
Other exercises in this chapter
Problem 18
At \(25^{\circ} \mathrm{C}\) the \(\mathrm{pH}\) value of a solution is 6 , the solution is (a) neutral (b) acidic (c) alkaline (d) basic
View solution Problem 19
The \(\mathrm{pH}\) of \(\mathrm{N} / 10 \mathrm{HCl}\) is (a) 3 (b) 4 (c) 2 (d) 1
View solution Problem 21
Which of the following can act like a buffer? (a) \(\mathrm{CH}_{3} \mathrm{COOH}+\mathrm{CH}_{3} \mathrm{COONa}\) (b) \(\mathrm{NH}_{4} \mathrm{ND}_{3}+\mathrm
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Which one of the following statements is not correct? (a) \(\mathrm{Cl}-\) is a lewis acid (b) the \(\mathrm{pH}\) of \(10^{-8} \mathrm{M} \mathrm{HCl}\) soluti
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