Problem 20
Question
Which one of the following ionic species will impart colour to an aqueous solution? (a) \(\mathrm{Cr}^{3+}\) (b) \(\mathrm{Cu}^{+}\) (c) \(\mathrm{Ti}^{4+}\) (d) \(\mathrm{Zn}^{2+}\)
Step-by-Step Solution
Verified Answer
\( \mathrm{Cr}^{3+} \) will impart color to the solution.
1Step 1: Understand Color Formation in Ionic Species
Ions impart color to a solution if they have unpaired d-electrons. Transition metal ions are typically colorful due to d-d electron transitions.
2Step 2: Analyze Each Option's Electron Configuration
- \( \mathrm{Cr}^{3+} \) has a 3d\(^{3}\) configuration with unpaired electrons.- \( \mathrm{Cu}^{+} \) has a 3d\(^{10}\) configuration without unpaired electrons.- \( \mathrm{Ti}^{4+} \) has no 3d electrons as it loses all its d-electrons.- \( \mathrm{Zn}^{2+} \) has a 3d\(^{10}\) configuration without unpaired electrons.
3Step 3: Determine the Ion with Unpaired Electrons
Identify that \( \mathrm{Cr}^{3+} \) is the only ion with unpaired d-electrons (3d\(^{3}\)) which can undergo electron transitions and impart color to the solution.
Key Concepts
Color of Ionic SpeciesElectron Configurationd-d Electron Transitions
Color of Ionic Species
The vibrant color of many ionic species, especially those involving transition metals, is a fascinating phenomenon associated with their electronic structure. Ions that impart color to solutions are often found in compounds involving transition metals. This color arises due to specific interactions at the atomic level.
For an ion to display color, it typically must possess unpaired electrons in its d-orbitals. These unpaired electrons allow for transitions from one d-orbital to another. When light interacts with these ions, it can cause electron transitions within the d-orbital, which absorb specific wavelengths of light.
The remaining light that is transmitted or reflected gives the ion its characteristic color. The presence or absence of unpaired d-electrons is, therefore, crucial. Without them, such transitions (and colors) are usually not possible.
For an ion to display color, it typically must possess unpaired electrons in its d-orbitals. These unpaired electrons allow for transitions from one d-orbital to another. When light interacts with these ions, it can cause electron transitions within the d-orbital, which absorb specific wavelengths of light.
The remaining light that is transmitted or reflected gives the ion its characteristic color. The presence or absence of unpaired d-electrons is, therefore, crucial. Without them, such transitions (and colors) are usually not possible.
Electron Configuration
Electron configuration is a fundamental concept that helps us understand where electrons are located around an atom. It is essential in determining the chemical properties of an element, including coloration in transition metal ions.
Transition metal ions are unique because they have partially filled d-orbitals. These d-orbitals can hold a maximum of 10 electrons, allowing for several unique configurations:
Transition metal ions are unique because they have partially filled d-orbitals. These d-orbitals can hold a maximum of 10 electrons, allowing for several unique configurations:
- For example, a \(\mathrm{Cr}^{3+}\) ion has a 3d\(^{3}\) electron configuration with three unpaired electrons, which makes it potentially colorful.
- On the other hand, ions like \(\mathrm{Cu}^{+}\) and \(\mathrm{Zn}^{2+}\) feature a 3d\(^{10}\) configuration, lacking unpaired electrons, and thus typically do not show color.
d-d Electron Transitions
One of the main reasons why transition metal ions are colorful is due to d-d electron transitions. But what exactly does this mean? When an electron in a d-orbital absorbs energy, it can move to a higher energy d-orbital. This jump between levels is what is known as a d-d transition.
The energy required for these transitions falls in the visible spectrum of light. When electrons absorb specific wavelengths of light to transition to another d-level, the ion reflects the complementary color of the absorbed light.
For instance, in \(\mathrm{Cr}^{3+}\), the presence of unpaired d-electrons allows these transitions to occur, giving rise to its distinct color. Meanwhile, if all d-orbitals are fully occupied or empty, like in \(\mathrm{Cu}^{+}\) or \(\mathrm{Zn}^{2+}\) respectively, no such transitions are possible, and the ions remain colorless.
Hence, identifying the d-electron configuration tells us a lot about the possible colors an ion might exhibit and highlights the amazing interplay between light and matter in transition metals.
The energy required for these transitions falls in the visible spectrum of light. When electrons absorb specific wavelengths of light to transition to another d-level, the ion reflects the complementary color of the absorbed light.
For instance, in \(\mathrm{Cr}^{3+}\), the presence of unpaired d-electrons allows these transitions to occur, giving rise to its distinct color. Meanwhile, if all d-orbitals are fully occupied or empty, like in \(\mathrm{Cu}^{+}\) or \(\mathrm{Zn}^{2+}\) respectively, no such transitions are possible, and the ions remain colorless.
Hence, identifying the d-electron configuration tells us a lot about the possible colors an ion might exhibit and highlights the amazing interplay between light and matter in transition metals.
Other exercises in this chapter
Problem 18
Action of caustic soda on \(\mathrm{Al}(\mathrm{OH})_{3}\) gives a compound having formula (a) \(\mathrm{Al}_{2}(\mathrm{OH})_{4}\) (b) \(\mathrm{Na}_{3} \mathr
View solution Problem 19
A one litre flask is full of brown bromine vapours. The intensity of brown colour of vapour will not decrease appreciably on adding to the flask some (a) carbon
View solution Problem 21
A chloride dissolves appreciably in cold water. When placed on platinum wire in Bunsen flame no distinctive colour in noticed, the cation would be (a) \(\mathrm
View solution Problem 22
By passing \(\mathrm{H}_{2} \mathrm{~S}\) gas in acidified \(\mathrm{KMnO}_{4}\) we get (a) \(\mathrm{S}\) (b) \(\mathrm{MnO}_{2}\) (c) \(\mathrm{K}_{2} \mathrm
View solution