Problem 20
Question
What is the mass in grams of each of the following? \begin{equation}\begin{array}{l}{\text { a. } 6.02 \times 10^{24} \text { atoms Bi }} \\ {\text { b. } 1.00 \times 10^{24} \text { atoms Mn }} \\\ {\text { c. } 3.40 \times 10^{22} \text { atoms He }} \\ {\text { d. } 1.50 \times 10^{15} \text { atoms } \mathrm{N}} \\ {\text { e. } 1.50 \times 10^{15} \text { atoms } U}\end{array}\end{equation}
Step-by-Step Solution
Verified Answer
(a) 2090 g Bi, (b) 91.18 g Mn, (c) 0.226 g He, (d) \(3.49 \times 10^{-8}\) g N, (e) \(5.92 \times 10^{-7}\) g U.
1Step 1: Calculate Moles
To find the mass, we first need to calculate the number of moles for each element by using Avogadro's number, which is approximately \( 6.022 \times 10^{23} \) atoms/mol. For example, to find moles of Bi, use the formula \( \text{moles} = \frac{\text{number of atoms}}{6.022 \times 10^{23}} \). Repeat for each element.
2Step 2: Bi - Moles and Mass
Number of atoms of Bi = \( 6.02 \times 10^{24} \). Moles of Bi = \( \frac{6.02 \times 10^{24}}{6.022 \times 10^{23}} \approx 10 \) mol. Molar mass of Bi (Bismuth) is 209.0 g/mol. Mass = moles \( \times \) molar mass = \( 10 \times 209.0 = 2090 \) g.
3Step 3: Mn - Moles and Mass
Number of atoms of Mn = \( 1.00 \times 10^{24} \). Moles of Mn = \( \frac{1.00 \times 10^{24}}{6.022 \times 10^{23}} \approx 1.66 \) mol. Molar mass of Mn (Manganese) is 54.94 g/mol. Mass = moles \( \times \) molar mass = \( 1.66 \times 54.94 \approx 91.18 \) g.
4Step 4: He - Moles and Mass
Number of atoms of He = \( 3.40 \times 10^{22} \). Moles of He = \( \frac{3.40 \times 10^{22}}{6.022 \times 10^{23}} \approx 0.0564 \) mol. Molar mass of He (Helium) is 4.00 g/mol. Mass = moles \( \times \) molar mass = \( 0.0564 \times 4.00 \approx 0.226 \) g.
5Step 5: N - Moles and Mass
Number of atoms of N = \( 1.50 \times 10^{15} \). Moles of N = \( \frac{1.50 \times 10^{15}}{6.022 \times 10^{23}} \approx 2.49 \times 10^{-9} \) mol. Molar mass of N (Nitrogen) is 14.01 g/mol. Mass = moles \( \times \) molar mass = \( 2.49 \times 10^{-9} \times 14.01 \approx 3.49 \times 10^{-8} \) g.
6Step 6: U - Moles and Mass
Number of atoms of U = \( 1.50 \times 10^{15} \). Moles of U = \( \frac{1.50 \times 10^{15}}{6.022 \times 10^{23}} \approx 2.49 \times 10^{-9} \) mol. Molar mass of U (Uranium) is 238.03 g/mol. Mass = moles \( \times \) molar mass = \( 2.49 \times 10^{-9} \times 238.03 \approx 5.92 \times 10^{-7} \) g.
Key Concepts
Avogadro's NumberMolar MassMass in GramsChemical Elements
Avogadro's Number
Let's dive into the concept of Avogadro's number, a cornerstone in chemistry that links atoms to grams. This number is often denoted as \( 6.022 \, \times \, 10^{23} \) atoms/mol. Think of it as a bridge connecting the atomic world—tiny, invisible particles—to amounts we can see and measure. For instance, when we say a mole of any element, it means it contains \( 6.022 \, \times \, 10^{23} \) atoms of that element. Here’s how it helps you:
- Converting atoms to moles: Divide the number of atoms by Avogadro's number to find how many moles you have.
- Understanding scale: Although elements vary in size, each mole contains exactly the same number of atoms.
Molar Mass
Molar mass is a term you'll encounter frequently in chemistry. It refers to the mass of one mole of a substance, usually expressed in grams per mole (g/mol). Each element has a unique molar mass based on the mass of its atoms.
To calculate the molar mass:
To calculate the molar mass:
- Check the periodic table: Each element’s atomic weight equals its molar mass.
- Units: It's always in g/mol, allowing you to easily convert from moles to grams.
Mass in Grams
Converting moles to mass in grams is a straightforward step using the molar mass. Once you know the number of moles you have, just multiply it by the molar mass of the element to get its mass in grams.
For example, if you have \( 1.66 \) moles of Manganese (Mn) with a molar mass of \( 54.94 \, \text{g/mol} \):
For example, if you have \( 1.66 \) moles of Manganese (Mn) with a molar mass of \( 54.94 \, \text{g/mol} \):
- Calculate mass: \( \text{mass} = \text{moles} \times \text{molar mass} = 1.66 \, \times \, 54.94 \approx 91.18 \, \text{g} \).
Chemical Elements
Chemical elements are the building blocks of matter, classified in the periodic table. Each element has its unique properties and atomic arrangement, which define its chemical behavior.
There are several things to remember about elements:
There are several things to remember about elements:
- Unique identity: Every element has a specific number of protons defining its identity (atomic number).
- Variety of states: Elements can exist in various states—solid, liquid, or gas—depending on environmental conditions.
- Role in chemistry: Understanding elements is crucial for predicting how substances react and combine.
Other exercises in this chapter
Problem 14
Arrange these three samples from smallest to largest in terms of number of representative particles: \(1.25 \times 10^{25}\) atoms of zinc (Zn), 3.56 mol of iro
View solution Problem 15
Determine the mass in grams of each of the following a. 3.57 mol Al b. 42.6 mol Si
View solution Problem 24
Explain how molar mass relates the mass of an atom to the mass of a mole of atoms.
View solution Problem 26
Arrange these quantities from smallest to largest in terms of mass: 1.0 mol of \(\mathrm{Ar}, 3.0 \times 10^{24}\) atoms of \(\mathrm{Ne},\) and 20 \(\mathrm{g}
View solution