Problem 20
Question
Use the Law of Sines to solve the triangle. $$ \alpha=75^{\circ}, \gamma=45^{\circ}, b=8 $$
Step-by-Step Solution
Verified Answer
\(a\approx8.92\), \(c\approx6.54\), \(\beta=60^{\circ}\).
1Step 1: Recognize Known Elements
We are given two angles, \( \alpha = 75^{\circ} \) and \( \gamma = 45^{\circ} \), and one side, \( b = 8 \). We need to find the third angle \( \beta \), and the sides \( a \) and \( c \).
2Step 2: Calculate the Third Angle
Use the property that the sum of the angles in a triangle is \( 180^{\circ} \). Calculate \( \beta \) as follows: \[ \beta = 180^{\circ} - \alpha - \gamma = 180^{\circ} - 75^{\circ} - 45^{\circ} = 60^{\circ}. \]
3Step 3: Apply the Law of Sines
The Law of Sines states: \[ \frac{a}{\sin(\alpha)} = \frac{b}{\sin(\beta)} = \frac{c}{\sin(\gamma)}. \] Now plug in the known values to measure the unknown sides.
4Step 4: Solve for Side 'a'
Using the \[ \frac{a}{\sin(\alpha)} = \frac{b}{\sin(\beta)} \] relationship, plug in the known values: \[ \frac{a}{\sin(75^{\circ})} = \frac{8}{\sin(60^{\circ})}. \] This translates to \[ a = \frac{8 \sin(75^{\circ})}{\sin(60^{\circ})}. \] Calculate this value using a calculator: \[ a \approx \frac{8 \times 0.9659}{0.8660} \approx 8.92. \]
5Step 5: Solve for Side 'c'
Using the \[ \frac{c}{\sin(\gamma)} = \frac{b}{\sin(\beta)} \] relationship, plug in the known values: \[ \frac{c}{\sin(45^{\circ})} = \frac{8}{\sin(60^{\circ})}. \] Solve for \( c \): \[ c = \frac{8 \sin(45^{\circ})}{\sin(60^{\circ})}. \] Calculate this value using a calculator: \[ c \approx \frac{8 \times 0.7071}{0.8660} \approx 6.54. \]
Key Concepts
TrigonometrySolving TrianglesTriangle Angles
Trigonometry
Trigonometry is the branch of mathematics that explores the relationships between the sides and angles of triangles. This field of study is crucial because it provides the tools needed to solve complex problems involving right and non-right triangles. Trigonometry uses functions such as sine, cosine, and tangent to relate angles to side lengths. These functions can help calculate unknown side lengths or angles, provide insights into angles of elevation or depression, and are foundational in fields ranging from engineering to physics. Understanding trigonometry empowers students to translate geometric relationships into algebraic equations, forming a bridge between geometry and algebra.
Solving Triangles
Solving triangles is about finding the unknown sides and angles when certain elements of a triangle are known. This often involves using one or more of the trigonometric laws, such as the Law of Sines or the Law of Cosines.
- The Law of Sines is particularly handy when you have two angles and one side (AAS or ASA conditions) or two sides and a non-included angle (SSA condition).
- The Law of Cosines is used for cases where two sides and the included angle are known (SAS) or when all three sides are known (SSS).
Triangle Angles
Triangle angles are essential components for solving triangles, and they follow the rule that their sum must be 180°. This rule helps in finding an unknown angle when the other two angles are provided. For example, if two angles are 75° and 45°, the third angle would be 60°, as you simply subtract the sum of the known angles from 180°: 180° - 75° - 45° = 60°.
When working with triangle angle measures:
- Remember that acute angles are less than 90°.
- A right angle is exactly 90°, which forms the basis for right triangles.
- Obtuse angles are those greater than 90°, perhaps seen in obtuse triangles.
Other exercises in this chapter
Problem 20
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Sketch the vectors \(\mathbf{u}+\mathbf{v}\) and \(\mathbf{u}\) - \(\mathbf{v}\). $$ \mathbf{u}=2 \mathbf{i}+3 \mathbf{j}, \mathbf{v}=-\mathbf{i}+2 \mathbf{j} $
View solution Problem 22
Sketch the vectors \(\mathbf{u}+\mathbf{v}\) and \(\mathbf{u}\) - \(\mathbf{v}\). $$ \mathbf{u}=-4 \mathbf{i}+\mathbf{j}, \mathbf{v}=2 \mathbf{i}+2 \mathbf{j} $
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