Problem 20
Question
Use the distributive property to rewrite each of the following quantities. $$1(x+y)$$
Step-by-Step Solution
Verified Answer
Question: Rewrite the given expression $$1(x+y)$$ using the distributive property.
Answer: The rewritten expression using the distributive property is $$x+y$$.
1Step 1: Identify the numbers and variables in the expression
In the given expression $$1(x+y)$$, we have the numbers and variables: a=1, b=x, and c=y.
2Step 2: Apply the distributive property
We now apply the distributive property by multiplying the value of 'a' with both 'b' and 'c' and then adding the results:
$$1(x+y) = 1\cdot x + 1\cdot y$$
3Step 3: Simplify the expression
Let's simplify the expression to get our final answer by multiplying 1 by both x and y:
$$1 \cdot x + 1 \cdot y = x+y$$
The rewritten expression using the distributive property is $$x+y$$.
Key Concepts
AlgebraExpression SimplificationVariables
Algebra
Algebra is the branch of mathematics dealing with symbols and the rules for manipulating these symbols. It allows us to express mathematical relationships without needing specific numbers. In algebra, variables take the place of numbers so we can solve general problems, rather than specific numerical ones.
- The concept of an equation in algebra is like a balance scale. What is on one side should equal what is on the other.
- Algebra involves operations such as addition, subtraction, multiplication, and division, but it also includes working with expressions, equations, and inequalities.
Expression Simplification
Expression simplification involves reducing an expression into its simplest form. This process makes complex problems more manageable, allowing us to solve them more efficiently.
When simplifying, you rely on various algebraic properties, the distributive property being one of them. It helps rewrite expressions so they're easier to work with.
When simplifying, you rely on various algebraic properties, the distributive property being one of them. It helps rewrite expressions so they're easier to work with.
- A simplified expression should have all like terms combined. For example, in the expression \(1 \cdot x + 1 \cdot y\), the terms with the multiplier 1 can be simplified to \(x + y\).
- Reducing an expression doesn't change its value but helps in easily seeing what the expression represents or finding solutions faster.
Variables
Variables in algebra function as placeholders for values that can change. They are typically represented by letters such as \(x\), \(y\), or \(z\). Understanding variables is critical because they allow us to represent general expressions and solve equations.
- Variables let us represent unknown quantities and model real-world situations. For instance, \(x\) and \(y\) in the expression \(1(x+y)\) are variables representing unknown values.
- When working with variables, you can think of them as containers that hold different values at different times, making algebra flexible and powerful.
Other exercises in this chapter
Problem 20
Make use of the power rule for quotients, the power rule for products, the power rule for powers, or a combination of these rules to simplify each expression. $
View solution Problem 20
For the following problems, write each of the quantities using exponential notation. \((21-x)\) cubed plus \((x+5)\) to the seventh
View solution Problem 20
For the following problems, use the order of operations to find each value. $$\frac{8(6+20)}{8}+\frac{3(6+16)}{22}$$
View solution Problem 21
Find each value. Assume the base is not zero. $$ \frac{26 x^{2} y^{5}}{4 x y^{2}} $$
View solution