Problem 20
Question
Use graphing to determine the domain and range of \(y=f(x)\) and of \(y=|f(x)|\). $$f(x)=-|x+2|-2$$
Step-by-Step Solution
Verified Answer
Domain of both functions: \((-\infty, \infty)\). Range of \( f(x) \): \((-\infty, -2]\), Range of \(|f(x)|\): \([0, \infty)\).
1Step 1: Understand the Function
First, identify the function given: \( f(x) = -|x+2| - 2 \). This is an absolute value function that has been reflected vertically and shifted downwards. Absolute value functions have a V-shape. In this case, the negative sign in front of \(|x+2|\) indicates that the V-shape will open downward.
2Step 2: Determine the Domain of \( f(x) \)
The domain of an absolute value function, including transformations like shifts or reflections, is all real numbers. Therefore, the domain of \( f(x) = -|x+2|-2 \) is \( (-\infty, \infty) \).
3Step 3: Determine the Range of \( f(x) \)
The vertex of the downward-opening V-shape is the maximum point of the function. For \( f(x) = -|x+2|-2 \), the vertex occurs at \( x = -2 \). At this point, \( f(-2) = -0 - 2 = -2 \). Thus, the range of \( f(x) \) is \(( -\infty, -2] \).
4Step 4: Graph \( f(x) \)
Sketch the graph of \( f(x) = -|x+2|-2 \) using its basic properties: an opening downwards V-shape with a vertex at \(( -2, -2) \). This visual will aid in analyzing the transformation to \( y = |f(x)| \).
5Step 5: Analyze \( y = |f(x)| \)
For \( y = |f(x)| \), any negative output of \( f(x) \) becomes positive. This results in reflecting all parts of the graph of \( f(x) \) that lie below the x-axis, onto their corresponding parts above the x-axis.
6Step 6: Determine the Domain of \( y = |f(x)| \)
The domain remains unchanged when taking the absolute value of a function. Hence, the domain of \( y = |f(x)| \) is also \( (-\infty, \infty) \).
7Step 7: Determine the Range of \( y = |f(x)| \)
The smallest value of \( |f(x)| \) is 0, occurring at \( x = -2 \) when \( f(-2) = -2 \). Thus, the range of \( y = |f(x)| \) starts at 0 and includes all positive numbers: \( [0, \infty) \).
8Step 8: Finalize the Domain and Range
Combine the results: for \( f(x) = -|x+2|-2 \), the domain is \( (-\infty, \infty) \) and the range is \(( -\infty, -2] \). For \( y = |f(x)| \), the domain is also \( (-\infty, \infty) \), but the range is \( [0, \infty) \).
Key Concepts
Domain and RangeAbsolute Value FunctionsFunction TransformationsPrecalculus Concepts
Domain and Range
In mathematical terms, the domain of a function includes all the possible input values (x-values) that will result in a well-defined function output. For the function given, \( f(x) = -|x+2|-2 \), any real number can be plugged into the equation and will provide a result, which implies that the domain is all real numbers. We can express this in interval notation as \((-\infty, \infty)\).
- The domain of \( y = |f(x)| \) also remains \((-\infty, \infty)\) because the absolute value function, being a modification of our original function, does not restrict any x-values.
- Concerning \( y=|f(x)| \), since we are taking the absolute value of the outputs of the original function, the negative values below the x-axis flip to positive. Thus, the lowest value is now 0, resulting in a range of \([0, \infty)\).
Absolute Value Functions
Absolute value functions are mathematical functions expressed in the format \( y = |x| \). Their characteristic V-shape graph is due to their nature of returning non-negative output for any input value. In simpler terms, the absolute value of a number reflects its distance from zero on a number line, without considering its sign.
- For \( f(x) = -|x+2|-2 \), the absolute value expression \(|x+2|\) is shifted and reflected.
- The inclusion of a negative sign (-) before the absolute value flips the V-shape graph downwards, essentially a vertical reflection.
Function Transformations
Function transformations alter the basic graph of a function in various ways including shifts, reflections, stretches, and compressions. Let’s look at \( f(x) = -|x+2|-2 \):
- Horizontal Shift: The term \(x+2\) suggests that the entire graph shifts to the left by 2 units.
- Vertical Shift: The constant -2 results in a downward shift by 2 units on the y-axis.
- Reflection: The negative sign (-) reflects the graph across the x-axis, causing its typical upward V-shape to flip downwards.
- For \( y = |f(x)| \), the outcome of the function being an absolute value means, f(x) reflecting about the x-axis always results in non-negative y-values.
Precalculus Concepts
Precalculus serves as the foundation for higher-level math, involving exploration of functions, algebra, and trigonometry. Understanding precalculus is crucial as it preps you for studying calculus.
- Key skills include analyzing and graphing functions such as the absolute value function, recognizing transformations, and comprehending domains and ranges.
- By comprehending these transformations, one develops an insight into how functions behave in the wider world of mathematics and beyond.
- Graphing is a particularly vital skill, allowing you to visualize and predict the behavior of complex functions effectively.
Other exercises in this chapter
Problem 20
Let \(f(x)=x^{2}+3 x\) and \(g(x)=2 x-1 .\) Perform the composition or operation indicated. $$\left(\frac{f}{g}\right)\left(\frac{1}{2}\right)$$
View solution Problem 20
Graph each piece wise-defined function. Is \(f\) continuous on its entire domain? Do not use a calculator. $$f(x)=\left\\{\begin{array}{ll} -2 x & \text { if }-
View solution Problem 20
Use transformations of graphs to sketch the graphs of \(y_{1}, y_{2},\) and \(y_{3}\) by hand. Check by graphing in an appropriate viewing window of your calcul
View solution Problem 21
Let \(f(x)=x^{2}+3 x\) and \(g(x)=2 x-1 .\) Perform the composition or operation indicated. $$\left(\frac{g}{f}\right)(0)$$
View solution