Problem 20
Question
Use \(f(x)=3 \ln x-4\). Evaluate \(f(1)\).
Step-by-Step Solution
Verified Answer
The value of \(f(1)\) is -4.
1Step 1: Understand function notation
The function \(f(x) = 3 \ln x - 4\) is an expression involving the variable x. When we say \(f(1)\), we are replacing 'x' in the function with '1'.
2Step 2: Substitute the value of x in the expression
Replace 'x' with '1' in the expression. So, \(f(1) = 3 \ln 1 - 4\).
3Step 3: Evaluate the expression
\(\ln 1 = 0\), because any number raised to the power 0 equals 1 . So \(f(1) = 3 * 0 - 4 = -4\).
Key Concepts
Function EvaluationNatural LogarithmsAlgebraic Expressions
Function Evaluation
Understanding function evaluation is crucial when it comes to working with mathematical functions. At its core, function evaluation is the process of finding the output of a function for a specific input value. In simpler terms, whenever you see an expression like \( f(1) \), you need to substitute the given input (in this case, 1) into the function.
- Functions are like machines; you feed in a number (input), and they give you a new number (output).
- The given function in this exercise is \( f(x) = 3 \ln x - 4 \).
- To evaluate \( f(1) \), substitute 1 for \( x \) in the function's formula.
Natural Logarithms
Natural logarithms are a special type of logarithm with the base \( e \), where \( e \approx 2.71828 \). They are often denoted as \( \ln x \) in mathematics. Natural logarithms are a fundamental concept in calculus and appear in many fields like economics, physics, and engineering.
- The natural logarithm of a number is the power to which \( e \) must be raised to obtain that number.
- Importantly, \( \ln 1 = 0 \), because any number raised to the power of 0 equals 1.
- This property is frequently used to simplify expressions, as seen in our exercise: \( \ln 1 \) resulted in 0.
Algebraic Expressions
Algebraic expressions are combinations of numbers, variables, and operations (like addition or multiplication). They form the basis for equations and functions, letting us solve for unknown values. In our exercise \( f(x) = 3 \ln x - 4 \), this is an algebraic expression concerning the variable \( x \).
- The term \( 3 \ln x \) represents a multiplication of the logarithmic function \( \ln x \) with the coefficient 3.
- The expression ends with the constant term -4, which modifies the result of the logarithmic part by subtracting 4.
- By substituting \( x \) with a specific value, like we did with \( x = 1 \), you can simplify it to a single number.
Other exercises in this chapter
Problem 19
Sketch the graph of each function. $$g(x)=\left(\frac{1}{4}\right)^{x}$$
View solution Problem 20
Solve the exponential equation. Round to three decimal places, when needed. $$5^{x+5}=3^{-2 x+1}$$
View solution Problem 20
State cohether each function given by a table is one-to-one. Explain your reasoning. $$\begin{array}{cc}x & f(x) \\\\-3 & 4 \\\\-1 & 7 \\\0 & 4 \\\1 & 5 \\\3 &
View solution Problem 20
In Exercises \(15-20,\) use the properties of logarithms to simplify each expression by eliminating all exponents and radicals. Assume that \(x, y > 0\). $$\log
View solution