Problem 20
Question
Use a formula for negatives to find the exact value. $$\text { (a) } \cot \left(-225^{\circ}\right) \quad \text { (b) } \sec \left(-\frac{\pi}{4}\right) \quad \text { (c) } \csc \left(-45^{\circ}\right)$$
Step-by-Step Solution
Verified Answer
(a) -1, (b) \(\sqrt{2}\), (c) \(-\sqrt{2}\)
1Step 1: Recognize Trigonometric Function Parities
Identify whether the given trigonometric function is even or odd. Recall that cosine and secant are even functions while sine, tangent, cosecant, and cotangent are odd functions.
2Step 2: Apply Function Parity to Find \( \cot(-225^{\circ}) \)
Since cotangent is an odd function, \( \cot(-\theta) = -\cot(\theta) \). Thus, \( \cot(-225^{\circ}) = -\cot(225^{\circ}) \).
3Step 3: Calculate \( \cot(225^{\circ}) \)
225° is in the third quadrant where both sine and cosine are negative, so \( \cot(225^{\circ}) = \frac{\cos 225^{\circ}}{\sin 225^{\circ}} = \frac{-\sqrt{2}/2}{-\sqrt{2}/2} = 1 \).
4Step 4: Calculate Exact Value of \( \cot(-225^{\circ}) \)
Given that \( \cot(-225^{\circ}) = -\cot(225^{\circ}) \), and \( \cot(225^{\circ}) = 1 \), we have \( \cot(-225^{\circ}) = -1 \).
5Step 5: Apply Function Parity to Find \( \sec \left(-\frac{\pi}{4}\right) \)
Secant is an even function, meaning \( \sec(-\theta) = \sec(\theta) \). Therefore, \( \sec \left(-\frac{\pi}{4}\right) = \sec \left(\frac{\pi}{4}\right) \).
6Step 6: Calculate \( \sec \left(\frac{\pi}{4}\right) \)
The angle \( \frac{\pi}{4} \) corresponds to 45°, where the cosine of the angle is \( \cos(\frac{\pi}{4}) = \frac{\sqrt{2}}{2} \). Thus, \( \sec \left(\frac{\pi}{4}\right) = \frac{1}{\cos \left(\frac{\pi}{4}\right)} = \sqrt{2} \).
7Step 7: Calculate Exact Value of \( \sec \left(-\frac{\pi}{4}\right) \)
As \( \sec \left(-\frac{\pi}{4}\right) = \sec \left(\frac{\pi}{4}\right) \), and \( \sec \left(\frac{\pi}{4}\right) = \sqrt{2} \), we have \( \sec \left(-\frac{\pi}{4}\right) = \sqrt{2} \).
8Step 8: Apply Function Parity to Find \( \csc(-45^{\circ}) \)
Cosecant is an odd function, so \( \csc(-\theta) = -\csc(\theta) \). Therefore, \( \csc(-45^{\circ}) = -\csc(45^{\circ}) \).
9Step 9: Calculate \( \csc(45^{\circ}) \)
At 45°, \( \sin(45^{\circ}) = \frac{\sqrt{2}}{2} \). Thus, \( \csc(45^{\circ}) = \frac{1}{\sin(45^{\circ})} = \sqrt{2} \).
10Step 10: Calculate Exact Value of \( \csc(-45^{\circ}) \)
Given \( \csc(-45^{\circ}) = -\csc(45^{\circ}) \), and \( \csc(45^{\circ}) = \sqrt{2} \), we conclude \( \csc(-45^{\circ}) = -\sqrt{2} \).
Key Concepts
Even and Odd FunctionsTrigonometric FunctionsExact Values of Trigonometric Functions
Even and Odd Functions
Understanding the difference between even and odd functions is essential in trigonometry. These properties help us manipulate and find the exact values of functions quickly. An **even function** is symmetric about the y-axis. This means that for any function \( f \), if \( f(x) = f(-x) \), then it's even. Examples include cosine and secant. When you see these, remember they don't change with negation of the angle:
- \( \cos(-\theta) = \cos(\theta) \)
- \( \sec(-\theta) = \sec(\theta) \)
- \( \sin(-\theta) = -\sin(\theta) \)
- \( \cot(-\theta) = -\cot(\theta) \)
Trigonometric Functions
Trigonometric functions are fundamental in mathematics, describing relationships in triangles and cycles. The primary functions include sine (\( \sin \)), cosine (\( \cos \)), and tangent (\( \tan \)). Each has its own role in describing the dimensions of right-angled triangles.
- **Sine** describes the ratio of the opposite side to the hypotenuse in a right triangle.
- **Cosine** is the ratio of the adjacent side to the hypotenuse.
- **Tangent** represents the ratio of the opposite side to the adjacent side.
Exact Values of Trigonometric Functions
Finding the exact value of trigonometric functions often involves specific angles, such as 30°, 45°, and 60°, or their radian equivalents. These angles have known sine, cosine, and tangent values. Let's look into two steps:
- **Step 1: Use known Angles** - Knowing that \( \sin(45°) = \cos(45°) = \frac{\sqrt{2}}{2} \) can simplify finding cosecant, secant, and cotangent for these angles.
- **Step 2: Apply identities** - Each function's reciprocal, as in \( \sec(45°) = \frac{1}{\cos(45°)} \), gives us \( \sqrt{2} \). These specific values help in calculating other angular measures too.
Other exercises in this chapter
Problem 19
Exer. \(17-20\) : Express \(\theta\) in terms of degrees, minutes, and seconds, to the nearest second. $$\theta=5$$
View solution Problem 20
Given the indicated parts of triangle \(A B C\) with \(\gamma=90^{\circ},\) express the third part in terms of the first two. $$\alpha, b ; a$$
View solution Problem 20
Find the amplitude, the period, and the phase shift and sketch the graph of the equation. \(y=\sin \left(\frac{1}{2} x+\frac{\pi}{4}\right)\)
View solution Problem 20
Find the period and sketch the graph of the equation. Show the asymptotes. $$y=\cot \left(x+\frac{\pi}{4}\right)$$
View solution