Problem 20
Question
True or false: (a) Molecules containing polar bonds must be polar molecules and have dipole-dipole forces. (b) For the halogen gases, the dispersion forces decrease while the boiling points increase as you go down the column in the periodic table. (c) In terms of the total attractive forces for a given substance, the more polar bonds there are in a molecule, the stronger the dipole-dipole interaction. \((\mathbf{d})\) All other factors being the same, total attractive forces between linear molecules are greater than those between molecules whose shapes are nearly spherical. (e) The more electronegative the atom, the more polarizable it is.
Step-by-Step Solution
Verified Answer
a) False, b) False, c) False, d) True, e) False.
1Step 1: Polar Bonds and Polar Molecules
Examine whether molecules with polar bonds are necessarily polar molecules with dipole-dipole forces. Molecules can have polar bonds but be nonpolar if the molecular geometry causes the dipoles to cancel, such as in carbon dioxide. Therefore, a molecule with polar bonds is not necessarily a polar molecule or possess dipole-dipole forces.
**Answer:** False.
2Step 2: Dispersion Forces and Boiling Points of Halogens
Determine the relationship between dispersion forces and boiling points in halogen gases down the periodic table. As we go from fluorine to iodine, the size and mass of the molecules increase, increasing dispersion forces. Higher dispersion forces correlate with higher boiling points. The statement that dispersion forces decrease is incorrect.
**Answer:** False.
3Step 3: More Polar Bonds and Dipole-Dipole Interactions
Evaluate if more polar bonds lead to stronger dipole-dipole interactions. While more polar bonds could contribute more dipole moments, the overall molecular shape and arrangement are what determine the dipole-dipole interactions. Thus, this statement isn't necessarily true.
**Answer:** False.
4Step 4: Shape Impact on Attractive Forces
Assess how molecular shape affects total attractive forces. Linear molecules can pack closer together, increasing the contact area for intermolecular forces compared to spherical molecules. As such, linear molecules generally exhibit stronger total attractive forces assuming all else is equal.
**Answer:** True.
5Step 5: Electronegativity and Polarizability
Consider the link between electronegativity and polarizability. More electronegative atoms hold onto their electrons more tightly, making them less polarizable. Hence, more electronegative atoms are generally less polarizable.
**Answer:** False.
Key Concepts
Polar BondsDispersion ForcesInduced Dipole
Polar Bonds
Polar bonds occur when there is a difference in electronegativity between two atoms in a molecule. This difference causes an uneven distribution of electron density, leading to a partial positive charge on one atom and a partial negative charge on the other. We refer to the separation of charges as a dipole moment.
An important aspect to keep in mind is that having polar bonds doesn't automatically make a molecule polar.
Therefore, while polar bonds are essential for forming polar molecules, other factors like molecular geometry play a critical role.
An important aspect to keep in mind is that having polar bonds doesn't automatically make a molecule polar.
- Molecular symmetry can cause dipole moments to cancel each other out.
- For example, carbon dioxide (CO₂) has polar bonds but is nonpolar due to its linear shape.
Therefore, while polar bonds are essential for forming polar molecules, other factors like molecular geometry play a critical role.
Dispersion Forces
Dispersion forces, often called London dispersion forces, are weak intermolecular forces that arise from temporary dipoles in molecules. These forces are present in all molecular interactions but tend to be the sole intermolecular forces in nonpolar molecules.
Interestingly, as you move down the halogens in the periodic table from fluorine to iodine:
Interestingly, as you move down the halogens in the periodic table from fluorine to iodine:
- The size and molecular weight increase, enhancing the strength of the dispersion forces.
- This increase results in higher boiling points with heavier halogens as they offer more electrons that can shift to create temporary dipoles.
Induced Dipole
An induced dipole occurs when a nonpolar molecule temporarily becomes polar due to the influence of nearby charged particles or polar molecules. This happens when an external electric field distorts the electron cloud of the nonpolar molecule, creating a temporary dipole.
This concept is crucial in understanding dispersion forces and their interaction with polar and nonpolar substances. Induced dipoles are key players when:
This concept is crucial in understanding dispersion forces and their interaction with polar and nonpolar substances. Induced dipoles are key players when:
- Two nonpolar substances interact, creating temporary alignment and attraction.
- Nonpolar molecules are near polar ones, enhancing the strength of the overall interaction due to mutual attraction.
Other exercises in this chapter
Problem 18
Which type of intermolecular force accounts for each of these differences? (a) Acetone, \(\left(\mathrm{CH}_{3}\right)_{2} \mathrm{CO},\) boils at \(56^{\circ}
View solution Problem 19
(a) List the following molecules in order of increasing polarizability: \(\mathrm{GeCl}_{4}, \mathrm{CH}_{4}, \mathrm{SiCl}_{4}, \mathrm{SiH}_{4}\), and \(\math
View solution Problem 21
Which member in each pair has the greater dispersion forces? (a) \(\mathrm{CH}_{3} \mathrm{OH}\) or \(\mathrm{CH}_{3} \mathrm{CH}_{2} \mathrm{OH},(\mathbf{b}) \
View solution Problem 22
Which member in each pair has the stronger intermolecular dispersion forces? (a) \(\mathrm{H}_{2} \mathrm{O}\) or \(\mathrm{CH}_{3} \mathrm{OH},\) (b) \(\mathrm
View solution