Problem 20
Question
The functions in Problems \(17-20\) represent exponential growth or decay. What is the initial quantity? What is the growth rate? State if the growth rate is continuous. $$P=3.2 e^{0.03 t}$$
Step-by-Step Solution
Verified Answer
Initial quantity is 3.2, growth rate is 3%, and growth is continuous.
1Step 1: Identify Initial Quantity
The formula given is an exponential function of the form \( P = P_0 e^{rt} \), where \( P_0 \) is the initial quantity. In our case, the initial quantity \( P_0 \) is 3.2.
2Step 2: Identify Growth Rate
In the formula \( P = P_0 e^{rt} \), the value of \( r \) represents the growth rate. Here, \( r = 0.03 \) which means the growth rate is 3% per time unit.
3Step 3: Determine Growth Type
The function uses the constant \( e \), which is the base of the natural logarithm. This indicates that the growth is continuous because \( e^x \) describes continuous growth or decay.
Key Concepts
Understanding Initial QuantityExploring Growth RateWhat is Continuous Growth?
Understanding Initial Quantity
When dealing with exponential functions, the concept of initial quantity is crucial. It represents the starting value of whatever is being measured—often before any time has passed.
This value is depicted in the exponential equation of the form \( P = P_0 e^{rt} \), where \( P_0 \) stands for the initial quantity.
For example, in the given function \( P = 3.2 e^{0.03t} \), the initial quantity is \( 3.2 \). This means that at the very beginning of the observed period, the quantity of interest is \( 3.2 \). It's the baseline from which all growth (or decay) starts.
This value is depicted in the exponential equation of the form \( P = P_0 e^{rt} \), where \( P_0 \) stands for the initial quantity.
For example, in the given function \( P = 3.2 e^{0.03t} \), the initial quantity is \( 3.2 \). This means that at the very beginning of the observed period, the quantity of interest is \( 3.2 \). It's the baseline from which all growth (or decay) starts.
- Think of \( P_0 \) as the very first value we record.
- It guides us in projecting forward in time.
Exploring Growth Rate
The growth rate in an exponential function is the rate at which the initial quantity increases or decreases over time.
In the equation \( P = P_0 e^{rt} \), the term \( r \) serves as the growth rate.
In our function \( P = 3.2 e^{0.03t} \), the value of \( r \) is \( 0.03 \), which signifies that the quantity is growing at a rate of 3% per time unit.
It's important to note:
In the equation \( P = P_0 e^{rt} \), the term \( r \) serves as the growth rate.
In our function \( P = 3.2 e^{0.03t} \), the value of \( r \) is \( 0.03 \), which signifies that the quantity is growing at a rate of 3% per time unit.
It's important to note:
- The growth rate tells us how quickly the quantity is changing.
- A positive \( r \) implies growth, while a negative \( r \) indicates decay.
What is Continuous Growth?
Continuous growth is a type of growth characterized by the use of the mathematical constant \( e \), approximately equal to 2.718. This constant forms the base of natural logarithms.
Its presence in an exponential equation like \( P = P_0 e^{rt} \) indicates continuous growth.
With \( e \) as the base, our given function \( P = 3.2 e^{0.03t} \) displays a continuous growth pattern.
Its presence in an exponential equation like \( P = P_0 e^{rt} \) indicates continuous growth.
With \( e \) as the base, our given function \( P = 3.2 e^{0.03t} \) displays a continuous growth pattern.
- Continuous growth means the rate of growth is consistent at any point in time, without interruptions.
- It models natural processes accurately, such as population growth or compound interest.
Other exercises in this chapter
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