Problem 20
Question
Suppose that \(A\) is an \(m \times k\) matrix and \(B\) is a \(k \times n\) matrix. Show that $$ (A B)^{\prime}=B^{\prime} A^{\prime} $$
Step-by-Step Solution
Verified Answer
We proved \((AB)' = B'A'\) using the transpose property of matrix products.
1Step 1: Understand the Transpose of a Product
We need to prove the relationship \((A B)' = B' A'\). Recall that the transpose of a product follows the rule that \((XY)' = Y'X'\) when the matrices are compatible for multiplication. Here, \(A\) is an \(m \times k\) matrix and \(B\) is a \(k \times n\) matrix, making \(AB\) an \(m \times n\) matrix.
2Step 2: Apply the Transpose Property to Matrices A and B
According to the property of transpose, for the matrix product \(AB\), the transpose of the product is obtained by reversing the order of multiplication and transposing the individual matrices. Therefore, we write: \((AB)' = B'A'\).
3Step 3: Conclude the Solution
By carefully applying the transpose property of matrix products, we have shown that \((AB)' = B'A'\), proving the original statement. This demonstration confirms the mathematical property of transposes in matrix algebra.
Key Concepts
Matrix TransposeMatrix MultiplicationMatrices
Matrix Transpose
In matrix algebra, the concept of a transpose is fundamental. It involves transforming a matrix by flipping it over its diagonal. This process interchanges the row and column indices of the matrix. For a given matrix \( C \), denoted as \( C^T \), every element \( c_{ij} \) is repositioned as \( c_{ji} \). In simple terms:
An essential rule to remember is that for transpose operations in matrix products, the order of multiplication reverses. So, \((XY)^T = Y^TX^T\) holds, and this rule is particularly useful in solving and simplifying algebraic expressions involving matrices.
- Rows become columns
- Columns become rows
An essential rule to remember is that for transpose operations in matrix products, the order of multiplication reverses. So, \((XY)^T = Y^TX^T\) holds, and this rule is particularly useful in solving and simplifying algebraic expressions involving matrices.
Matrix Multiplication
Matrix multiplication is a bit different from multiplying regular numbers. It involves combining two matrices to produce another matrix. However, not every pair of matrices can be multiplied. For two matrices \(A\) and \(B\) to be multiplied, the number of columns in \(A\) must match the number of rows in \(B\).
When multiplying matrices:
When multiplying matrices:
- The resultant element at position \(i, j\) in the new matrix results from the dot product between the \(i^{th}\) row of the first matrix and the \(j^{th}\) column of the second matrix.
- The dimensions of the resulting matrix are determined by taking the rows from the first matrix and columns from the second, i.e., for an \(m \times k\) matrix \(A\) and a \(k \times n\) matrix \(B\), the product \(AB\) will be an \(m \times n\) matrix.
Matrices
Matrices are a powerful tool in mathematics, particularly useful for representing linear transformations, solving systems of equations, and much more. A matrix is essentially a rectangular array of numbers, symbols, or expressions arranged in rows and columns. Each item in a matrix is called an element.
There are several types of matrices, including:
There are several types of matrices, including:
- Square Matrix: The same number of rows and columns, such as a 3x3 matrix.
- Row Matrix: A matrix with only one row, e.g., 1x3.
- Column Matrix: A matrix with only one column, e.g., 3x1.
- Zero Matrix: A matrix where all elements are zero.
- Identity Matrix: A square matrix with ones on the diagonal and zeros elsewhere.
Other exercises in this chapter
Problem 20
Use the dot product to compute the length of \([1,1,3]\) '.
View solution Problem 20
Find \(\mathbf{x}+\mathbf{y}\) for each pair of vectors \(\mathbf{x}\) and \(\mathbf{v}\). Represent \(\mathrm{x}, \mathbf{y}\), and \(\mathrm{x}+\mathrm{y}\) i
View solution Problem 20
In Problems 19-24, solve each system of linear equations. $$ \begin{aligned} 5 x-y+2 z &=6 \\ x+2 y-z &=-1 \\ 3 x+2 y-2 z &=1 \end{aligned} $$
View solution Problem 21
Use the dot product to compute the length of \([1,2,3,4]\) '.
View solution