Problem 20
Question
Solve the equation by cross multiplying. Check your solutions. \(\frac{(x+1)^{2}}{(x-3)^{2}}=1\)
Step-by-Step Solution
Verified Answer
The solution to the equation \(\frac{(x+1)^{2}}{(x-3)^{2}}=1\) is \(x = 1\).
1Step 1: Cross-multiplication
Cross multiplication in a proportion is applied by multiplying the denominator of the first ratio by the numerator of the second ratio and equates it to the product of the numerator of the first ratio and the denominator of the second ratio. Apply this concept to the equation \(\frac{(x+1)^{2}}{(x-3)^{2}}=1\). Written in terms of cross multiplication, this becomes \((x+1)^{2}*1=(x-3)^{2}*1\). Simplified, this gives: \((x+1)^{2}=(x-3)^{2}\)
2Step 2: Simplify the equation
Expand the square terms on both sides of the equation. This leads to \(x^{2} + 2x + 1 = x^{2} - 6x + 9\). Then simplify the equation by subtracting \(x^{2}\) and \(2x\) from both sides of the equation. This reduces the equation to \(0 = -8x + 8\)
3Step 3: Solve for x
Solving for x involves isolating x on one side of the equation. This can be done by adding 8x and subtracting 8 from both sides, which transforms the equation into \(8x = 8\). Divide both sides of the equation by 8 to find the value of x, hence \(x = 1\).
4Step 4: Verify the solution
Check if the value of x found is correct by plugging it into the original equation \(\frac{(x+1)^{2}}{(x-3)^{2}}=1\). The left-hand side of the equation becomes \(\frac{(1+1)^{2}}{(1-3)^{2}}\) which simplifies to \(\frac{4}{4}\) or 1. Since this is equal to the right-hand side of the equation, the solution \(x = 1\) is valid and correct.
Key Concepts
Cross MultiplicationProportionsQuadratic Equations
Cross Multiplication
When you encounter a proportion, such as \(\frac{a}{b} = \frac{c}{d}\), cross multiplication is a nifty tool. It helps us determine if the ratios are equal and simplifies finding unknowns. Here's how it works:
- Multiply across the diagonals, so you compute \(a \cdot d = b \cdot c\).
- This essentially balances the equation using the cross products.
Proportions
Proportions express that two ratios or fractions are equivalent. They are written in the form \(\frac{a}{b} = \frac{c}{d}\). Understanding proportions is crucial because they appear in various mathematical contexts, from algebra to geometry. To handle proportions:
- Ensure both sides are ratios.
- You can set them equal and cross multiply to solve for unknowns.
Quadratic Equations
Quadratic equations are those that can be written in the form \(ax^2 + bx + c = 0\). They often have two solutions because they represent a parabola when graphed. Solving these equations involves several methods, including factoring, completing the square, and using the quadratic formula.Breaking down the solution process:
- Expand and simplify the expression, here \((x+1)^2 = (x-3)^2\) became \(x^2 + 2x + 1 = x^2 - 6x + 9\).
- Simplify by collecting like terms, which led to the linear equation \(-8x + 8 = 0\).
- Finally, solve for \(x\) by isolating the variable, resulting in \(x = 1\).
Other exercises in this chapter
Problem 20
SUBTRACTING RATIONAL EXPRESSIONS. Simplify the expression. $$ \frac{2 x}{x+2}-\frac{2 x+1}{x+2} $$
View solution Problem 20
The variables \(x\) and \(y\) vary inversely. Use the given values to write an equation that relates \(x\) and \(y .\) $$ x=16, y=1 $$
View solution Problem 20
Find the missing numerator. $$ \frac{x-9}{2 x+3}=\frac{?}{x(2 x+3)} $$
View solution Problem 20
Solve the proportion using the cross product property. Check your solution. $$ \frac{4}{2 w}=\frac{7}{3} $$
View solution