Problem 20
Question
Solve each equation. For equations with real solutions, support your answers graphically. $$x^{2}=-32$$
Step-by-Step Solution
Verified Answer
The equation has no real solutions.
1Step 1: Understand the Equation
The equation given is \( x^2 = -32 \). Recognize that this equation involves finding a real number \( x \) whose square is \(-32\).
2Step 2: Analyze the Equation for Real Solutions
To analyze for real solutions, understand that squaring any real number results in a non-negative value. Since \( x^2 = -32 \) gives a negative, real numbers cannot satisfy this equation.
3Step 3: Conclude with No Real Solution
Based on the analysis, conclude that there are no real solutions for the equation \( x^2 = -32 \), because the square of any real number is always non-negative.
4Step 4: Graphical Representation
Although graphing won’t yield a real solution, examining a graph might help understand the problem. Graph \( y = x^2 \) and \( y = -32 \) on the same coordinate plane. You will see that the parabola \( y = x^2 \) does not intersect the line \( y = -32 \).
Key Concepts
Quadratic equationsGraphical representationImaginary numbers
Quadratic equations
Quadratic equations are quite common in mathematics. They have the general form \( ax^2 + bx + c = 0 \), where \( a \), \( b \), and \( c \) are constants and \( x \) is the variable we'll solve for. The equation provided in the exercise, \( x^2 = -32 \), is a simplified form where \( a = 1 \), \( b = 0 \), and \( c = -32 \). This means that the equation does not have a linear component (the \( bx \) part is missing).
Solving quadratic equations usually involves finding two possible values for \( x \), called the roots. For real roots, the solutions can be found either by factoring, completing the square, or using the quadratic formula, \( x = \frac{-b \pm \sqrt{b^2 - 4ac}}{2a} \). However, when the discriminant \( b^2 - 4ac \) is negative, as we have here with \( -4 \times 1 \times -32 \), it indicates the equation has no real solutions, leading us to consider imaginary numbers.
Solving quadratic equations usually involves finding two possible values for \( x \), called the roots. For real roots, the solutions can be found either by factoring, completing the square, or using the quadratic formula, \( x = \frac{-b \pm \sqrt{b^2 - 4ac}}{2a} \). However, when the discriminant \( b^2 - 4ac \) is negative, as we have here with \( -4 \times 1 \times -32 \), it indicates the equation has no real solutions, leading us to consider imaginary numbers.
Graphical representation
Graphical representation is a powerful tool in understanding equations. In the context of quadratic equations like \( x^2 = -32 \), it helps visualize the nature of solutions, even when they are not real. By plotting \( y = x^2 \) alongside the line \( y = -32 \), we use a graph to convey the concept visually.
When graphed, \( y = x^2 \) forms a parabola that opens upwards, starting from the point (0,0). This parabola never dips below the \( x \)-axis, which is why it does not intersect with the line \( y = -32 \) - represented graphically as a horizontal line far below. This visual evidence reinforces the conclusion that \( x^2 = -32 \) has no points of intersection with real numbers. Thus, these graphical tools can offer a tangible way to reason about mathematical concepts.
When graphed, \( y = x^2 \) forms a parabola that opens upwards, starting from the point (0,0). This parabola never dips below the \( x \)-axis, which is why it does not intersect with the line \( y = -32 \) - represented graphically as a horizontal line far below. This visual evidence reinforces the conclusion that \( x^2 = -32 \) has no points of intersection with real numbers. Thus, these graphical tools can offer a tangible way to reason about mathematical concepts.
Imaginary numbers
Imaginary numbers come into play when we deal with the square root of negative numbers, which are not defined in the realm of real numbers. The primary imaginary unit is \( i \), defined by the equation \( i^2 = -1 \).
In our exercise \( x^2 = -32 \), there are no real numbers \( x \) such that \( x^2 = -32 \). However, with imaginary numbers, we can solve it by recognizing that \( x = \sqrt{-32} \) can be expressed with \( i \). We simplify \( \sqrt{-32} \) as \( 4\sqrt{2}i \) because \( \sqrt{-1} = i \). Thus, the equation has solutions \( x = 4\sqrt{2}i \) and \( x = -4\sqrt{2}i \).
Imaginary numbers extend our number system to include solutions that are not visible on a standard number line but are crucial in fields like engineering and physics. They're particularly useful when dealing with wave functions or circuits in electrical engineering. By understanding and using these imaginary numbers, we can fully solve and interpret mathematical equations that initially seem unsolvable in the real number domain.
In our exercise \( x^2 = -32 \), there are no real numbers \( x \) such that \( x^2 = -32 \). However, with imaginary numbers, we can solve it by recognizing that \( x = \sqrt{-32} \) can be expressed with \( i \). We simplify \( \sqrt{-32} \) as \( 4\sqrt{2}i \) because \( \sqrt{-1} = i \). Thus, the equation has solutions \( x = 4\sqrt{2}i \) and \( x = -4\sqrt{2}i \).
Imaginary numbers extend our number system to include solutions that are not visible on a standard number line but are crucial in fields like engineering and physics. They're particularly useful when dealing with wave functions or circuits in electrical engineering. By understanding and using these imaginary numbers, we can fully solve and interpret mathematical equations that initially seem unsolvable in the real number domain.
Other exercises in this chapter
Problem 19
Solve each equation. For equations with real solutions, support your answers graphically. $$x^{2}=-18$$
View solution Problem 19
Determine whether each statement is true or false. If it is false, tell why. There is no real number that is a complex number.
View solution Problem 20
Solve each problem. A cylindrical aluminum can is being constructed to have a height \(h\) of 4 inches. If the can is to have a volume of 28 cubic inches, appro
View solution Problem 20
Determine whether each statement is true or false. If it is false, tell why. A complex number might not be a pure imaginary number.
View solution