Problem 20
Question
Solve each equation by hand. Do not use a calculator. $$\sqrt[4]{2 x+3}=\sqrt{x+1}$$
Step-by-Step Solution
Verified Answer
The solution is \( x = \sqrt{2} \).
1Step 1: Eliminate the Radicals
To remove the radicals from the equation, raise both sides to the 4th power. This gets rid of the 4th root on the left-hand side. Therefore, the equation becomes: \( (\sqrt[4]{2x+3})^4 = (\sqrt{x+1})^4 \) which simplifies to: \( 2x+3 = (x+1)^2 \).
2Step 2: Expand the Equation
Expand the right-hand side of the equation. \( (x+1)^2 = x^2 + 2x + 1 \). The equation now is:\( 2x + 3 = x^2 + 2x + 1 \).
3Step 3: Rearrange the Equation
Subtract \(2x + 3\) from both sides to set the equation to zero:\( 0 = x^2 + 2x + 1 - 2x - 3 \). Simplify to get:\( 0 = x^2 - 2 \).
4Step 4: Solve for x
Now, solve for \(x\). Add 2 to both sides: \( x^2 = 2 \). Take the square root of both sides:\( x = \pm \sqrt{2} \).
5Step 5: Check the Solutions
Verify each potential solution by substituting back into the original equation. 1. For \( x = \sqrt{2} \): - \( \sqrt[4]{2\sqrt{2}+3} = \sqrt{\sqrt{2}+1} \) - Simplifying both sides gives the same value, which means \( x = \sqrt{2} \) is a valid solution.2. For \( x = -\sqrt{2} \): - Substituting does not yield a valid equation as it results in a negative term under a square root on the right. - Therefore, \( x = -\sqrt{2} \) is not a valid solution.
Key Concepts
Polynomial Expansion
Polynomial Expansion
Polynomial expansion is an algebraic process used to express a product of polynomials as a sum of terms. In the context of solving radical equations, this is essential for simplifying expressions. Let's dive into how it's applied. When given the expression
- \((x+1)^2\)
- For any binomial \((a+b)^2\), the expansion is \(a^2 + 2ab + b^2\).
- \(x^2 + 2x + 1\).
- A fourth root, such as \(\sqrt[4]{2x+3}\), needs to be simplified by raising it to the power necessary to cancel the root.
- This transformation eliminates the root to further simplify or solve the equation.
- \((\sqrt[4]{2x+3})^4\) becomes \(2x+3\).
- In this exercise, after solving for \(x\) and finding that \(x = \pm \sqrt{2}\), students must check each solution.
- Substitute \(x = \sqrt{2}\) back into the original equation:
- On substitution, if both sides of the equation are equal, the solution is valid.
- For \(x = -\sqrt{2}\), substitution leads to inconsistencies such as a negative quantity under a square root, making it invalid.
- \((x+1)^2\)
- For any binomial \(a+b)^2\), the expansion is \(a^2 + 2ab + b^2\).
- \(x^2 + 2x + 1\).
- A fourth root, such as \(\sqrt[4]{2x+3}\), needs to be simplified by raising it to the power necessary to cancel the root.
- This transformation eliminates the root to further simplify or solve the equation.
- \((\sqrt[4]{2x+3})^4\) becomes \(2x+3\).
- In this exercise, after solving for \(x\) and finding that \(x = \pm \sqrt{2}\), students must check each solution.
- Substitute \(x = \sqrt{2}\) back into the original equation:
- On substitution, if both sides of the equation are equal, the solution is valid.
- For \(x = -\sqrt{2}\), substitution leads to inconsistencies such as a negative quantity under a square root, making it invalid.
Other exercises in this chapter
Problem 20
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Evaluate each expression. $$\left(4^{-1 / 2}\right)^{-4}$$
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Explain how the graph of \(f\) can be obtained from the graph of \(y=\frac{1}{x}\) or \(y=\frac{1}{x^{2}} .\) Draw a sketch of the graph of \(f\) by hand. Then
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