Problem 20
Question
Solve each equation. $$ 6^{x-2}=36 $$
Step-by-Step Solution
Verified Answer
The solution to the equation is \(x = 4\).
1Step 1: Recognize the Base
First, notice that the equation is given as \(6^{x-2} = 36\). To solve this for \(x\), recognize that both sides of the equation can be expressed with the same base. The number 36 can be written as \(6^2\).
2Step 2: Rewrite the Equation
Substitute \(36\) with its base expression: \(6^{x-2} = 6^2\). Now both sides have the same base.
3Step 3: Equate the Exponents
Since the bases are the same, you can set the exponents equal to each other: \(x-2 = 2\).
4Step 4: Solve for x
Now solve for \(x\) by adding 2 to both sides of the equation: \(x - 2 + 2 = 2 + 2\), which simplifies to \(x = 4\).
Key Concepts
Equation SolvingExponent RulesAlgebraic Manipulation
Equation Solving
Equation solving refers to the process of finding the unknown value that satisfies a given equation. In our example, this unknown value is represented by the variable \( x \). During equation solving, one seeks to isolate the variable on one side of the equation to determine its value.The first step involves observing the equation structure. Identifying similar terms or elements can greatly aid in simplifying the process. Here, the equation \( 6^{x-2} = 36 \) suggests that \( x \) is involved in a power with a base of 6.Remember, the goal is to manipulate the equation so that the variable \( x \) stands alone on one side of the equation. Doing so enables us to determine its exact value and solve the equation.
Exponent Rules
Exponent rules are fundamental when dealing with exponential equations like in the exercise above. These rules dictate how exponents are manipulated and combined, which can make solving the equation much simpler.In our given equation \( 6^{x-2} = 36 \), understanding that 36 is equivalent to \( 6^2 \) is crucial. This rule helps us write the equation with the same base on both sides:
- Product of Powers Rule: When multiplying like bases, add the exponents: \( a^m \cdot a^n = a^{m+n} \).
- Quotient of Powers Rule: When dividing like bases, subtract the exponents: \( \frac{a^m}{a^n} = a^{m-n} \).
- Power of a Power Rule: When raising a power to another power, multiply the exponents: \( (a^m)^n = a^{m \cdot n} \).
Algebraic Manipulation
Algebraic manipulation involves rearranging and transforming an equation to isolate the variable and simplify the expression. This skill is essential in solving for unknowns like in the equation \( 6^{x-2} = 6^2 \).Once we have both sides of the equation with the same base, algebraic manipulation focuses on the exponents: by equating \( x-2 = 2 \), we derive an equation that is simple to solve.Let's break down the steps of manipulation:
- Identify similar terms on both sides of the equation. In this case, they are the exponents in \( 6^{x-2} = 6^2 \).
- Apply basic arithmetic operations to isolate the variable. Here, add 2 to both sides of \( x-2 = 2 \) to find \( x \).
- Simplify the result: \( x = 4 \).
Other exercises in this chapter
Problem 20
In this Study Set, assume that all variables represent positive numbers and \(b \neq 1\). Evaluate each expression. See Example \(1 .\) $$ \log _{9} 9 $$
View solution Problem 20
Complete each solution. $$ \begin{aligned} \text { Solve: } \log _{2}(2 x-3) &=\log _{2}(x+4) \\ &=x+4 \\ x &= \end{aligned} $$
View solution Problem 20
For each function, determine its inverse, \(f^{-1}(x)\) a. \(f(x)=10^{x}\) b. \(f(x)=3^{x}\) c. \(f(x)=\log x\) d. \(f(x)=\log _{2} x\)
View solution Problem 20
Determine whether each function is one-to-one. $$ f(x)=|x| $$
View solution