Problem 20
Question
Solve each equation. $$ 5 x(5 x+7)=0 $$
Step-by-Step Solution
Verified Answer
The solutions are \( x = 0 \) and \( x = -\frac{7}{5} \).
1Step 1: Understand the Equation
The equation given is \( 5x(5x + 7) = 0 \). It is a factorization of the form \( a \times b = 0 \), where \( a = 5x \) and \( b = 5x + 7 \). To solve it, we apply the Zero Product Property.
2Step 2: Apply the Zero Product Property
The Zero Product Property states that if the product of two factors is zero, at least one of the factors must be zero. Thus, set each factor equal to zero: \( 5x = 0 \) and \( 5x + 7 = 0 \).
3Step 3: Solve the First Equation
Solve the first factor equation \( 5x = 0 \). Divide both sides by 5 to isolate \( x \):\[ x = \frac{0}{5} = 0 \].
4Step 4: Solve the Second Equation
Now, solve the second factor equation \( 5x + 7 = 0 \). Subtract 7 from both sides:\[ 5x = -7 \].Then divide both sides by 5 to solve for \( x \):\[ x = -\frac{7}{5} \].
5Step 5: State the Solutions
The solutions to the equation \( 5x(5x + 7) = 0 \) are \( x = 0 \) and \( x = -\frac{7}{5} \).
Key Concepts
Zero Product PropertyFactoringSolving Equations
Zero Product Property
When you face an equation that involves a product equaling zero, the Zero Product Property is your friend. This property tells us that if a product of two numbers is zero, then one or both numbers must be zero. For instance, if \(a \times b = 0\), then either \(a = 0\) or \(b = 0\), or both.
This principle is vital when solving quadratic equations because it allows us to break down complex equations into simpler parts. By isolating each factor and setting them individually to zero, we can find possible solutions for the variable.
Using this property effectively can simplify what initially seems like a complicated problem. It neatly splits the task of solving into manageable steps, making it a fundamental tool in algebra.
This principle is vital when solving quadratic equations because it allows us to break down complex equations into simpler parts. By isolating each factor and setting them individually to zero, we can find possible solutions for the variable.
Using this property effectively can simplify what initially seems like a complicated problem. It neatly splits the task of solving into manageable steps, making it a fundamental tool in algebra.
Factoring
Factoring is a classic technique used to solve quadratic equations. It involves expressing an equation as a product of its simpler components, called factors.
In the case of the equation \(5x(5x + 7) = 0\), this step is already given as it is already factorized as \((5x)\) and \((5x + 7)\).
Being able to factor equations allows you to use the Zero Product Property efficiently. If an equation is in a format where the product equals zero, you can directly apply the property. But first, you need each equation part's factors.
Remember, not all equations are ready to be factored at first glance. Some can be rearranged or simplified, turning them into a more favorable form for factoring, thus making solutions easier to find.
In the case of the equation \(5x(5x + 7) = 0\), this step is already given as it is already factorized as \((5x)\) and \((5x + 7)\).
Being able to factor equations allows you to use the Zero Product Property efficiently. If an equation is in a format where the product equals zero, you can directly apply the property. But first, you need each equation part's factors.
Remember, not all equations are ready to be factored at first glance. Some can be rearranged or simplified, turning them into a more favorable form for factoring, thus making solutions easier to find.
Solving Equations
Solving equations is about finding the value of the variable that makes the equation true. Once we've factored an equation, like in this exercise, it becomes much simpler.
Here’s how you solve our example step by step:
Here’s how you solve our example step by step:
- Identify the factors: You have \(5x\) and \(5x + 7\).
- Set each factor to zero: \(5x = 0\) and \(5x + 7 = 0\).
- Divide both sides by 5 to get \(x = 0\).
- Subtract 7 from both sides to get \(5x = -7\), then divide by 5 to solve for \(x\), resulting in \(x = -\frac{7}{5}\).
Other exercises in this chapter
Problem 20
The following is a list of random factoring problems. Factor each expression. If an expression is not factorable, write "prime." See Examples 1-5. $$ 6 r^{2}+3
View solution Problem 20
Geometry Problems Shuffleboard. The area of the numbered triangle on a shuffleboard court is \(27 \mathrm{ft}^{2}\). Its height is 3 feet more than the length o
View solution Problem 20
Determine whether each of the following is a perfect-square trinomial. $$ 9 y^{2}-30 y+25 $$
View solution Problem 20
Factor. $$ n^{3}+1 $$
View solution