Problem 20
Question
Show that a demand equation \(q=k / p^{r},\) where \(r\) is a positive constant, gives constant elasticity \(E=r\)
Step-by-Step Solution
Verified Answer
The demand equation gives constant elasticity \( E = r \).
1Step 1: Understanding the Demand Equation
The demand equation given is \( q = \frac{k}{p^r} \), where \( q \) is the demand, \( k \) is a constant, \( p \) is the price, and \( r \) is a positive constant.
2Step 2: Recall the Elasticity Formula
The elasticity of demand formula is \( E = \frac{dq/dp}{q/p} \). This measures the percentage change in quantity demanded resulting from a one percent change in price.
3Step 3: Differentiate the Demand Equation
Differentiate \( q = \frac{k}{p^r} \) with respect to \( p \). Use the power rule for differentiation: \( dq/dp = -rk \cdot p^{-(r+1)} \).
4Step 4: Find \( q/p \) in the Elasticity Formula
In the formula \( q/p \), simply use the given \( q = \frac{k}{p^r} \) as: \( \frac{q}{p} = \frac{k}{p^{r+1}} \).
5Step 5: Substitute into the Elasticity Formula
Substitute \( dq/dp = -rk \cdot p^{-(r+1)} \) and \( q/p = \frac{k}{p^{r+1}} \) into \( E = \frac{dq/dp}{q/p} \). This gives:\[E = \frac{-rk \cdot p^{-(r+1)}}{k/p^{r+1}}\].Simplify the expression by canceling \( k \) and rearranging the exponents.
6Step 6: Simplify to Find the Elasticity
The expression simplifies to:\[E = \frac{-rk \cdot p^{-(r+1)}}{k \cdot p^{-(r+1)}} = -r\].Note the negative sign indicates the direction of change (as price increases, demand decreases), thus elasticity \( E = r \).
7Step 7: Conclude the Elasticity is Constant
Since the elasticity \( E = r \) is independent of \( p \) and other variables, the elasticity is constant and equal to \( r \).
Key Concepts
Differentiation in CalculusDemand EquationElasticity of Demand Formula
Differentiation in Calculus
Differentiation is a key concept in calculus that focuses on how functions change over time. When we talk about differentiation, we're often concerned with finding the derivative of a function. The derivative essentially measures how a function changes as its input changes.
An important aspect of differentiation is the power rule, which is a straightforward formula for finding the derivative of polynomial functions. For example, if you have a function of the form \( f(x) = x^n \), the derivative of this function using the power rule is \( f'(x) = nx^{n-1} \).
In the context of our original exercise, differentiation is used to analyze the change in demand relative to the change in price. By applying the power rule to the demand equation, we can find out how sensitive demand is to price changes. This derivative is crucial to determining the elasticity of demand, which in turn tells us how much quantity demanded changes when the price changes by a certain percentage.
An important aspect of differentiation is the power rule, which is a straightforward formula for finding the derivative of polynomial functions. For example, if you have a function of the form \( f(x) = x^n \), the derivative of this function using the power rule is \( f'(x) = nx^{n-1} \).
In the context of our original exercise, differentiation is used to analyze the change in demand relative to the change in price. By applying the power rule to the demand equation, we can find out how sensitive demand is to price changes. This derivative is crucial to determining the elasticity of demand, which in turn tells us how much quantity demanded changes when the price changes by a certain percentage.
Demand Equation
A demand equation is an equation that represents the relationship between quantity demanded and price within a market. It reflects how much of a product consumers want to buy at different price levels. In mathematics, this relationship can be expressed as a formula like \( q = \frac{k}{p^r} \), where:
Understanding this equation helps economists and businesses determine pricing strategies that maximize revenue while considering consumers' responsiveness to price changes.
- \( q \) represents the quantity demanded.
- \( p \) is the price of the good or service.
- \( k \) is a constant that represents other non-price factors affecting demand.
- \( r \) is a positive constant showing the influence of price on demand.
Understanding this equation helps economists and businesses determine pricing strategies that maximize revenue while considering consumers' responsiveness to price changes.
Elasticity of Demand Formula
The elasticity of demand is a crucial economic concept that measures how quantity demanded reacts to changes in price. The formula for price elasticity of demand is expressed as:
\[ E = \frac{dq/dp}{q/p} \]
Where:
In the specific case of our original exercise, the demand elasticity is shown to be a constant \( r \). The negative sign indicates the inverse relationship; as price increases, the quantity demanded decreases. Simplifying the elasticity formula in the exercise confirms this by showing how the influence of price through the \( r \) exponent results in constant elasticity, encapsulated simply as \( E = r \).
\[ E = \frac{dq/dp}{q/p} \]
Where:
- \( \frac{dq}{dp} \) is the derivative of demand with respect to price, indicating the rate of change in demand for an infinitesimal change in price.
- \( q/p \) is the ratio of quantity to price, essentially showing how much demand corresponds to a certain price level.
In the specific case of our original exercise, the demand elasticity is shown to be a constant \( r \). The negative sign indicates the inverse relationship; as price increases, the quantity demanded decreases. Simplifying the elasticity formula in the exercise confirms this by showing how the influence of price through the \( r \) exponent results in constant elasticity, encapsulated simply as \( E = r \).
Other exercises in this chapter
Problem 20
An ice cream company finds that at a price of \(\$ 4.00,\) demand is 4000 units. For every \(\$ 0.25\) decrease in price, demand increases by 200 units. Find th
View solution Problem 20
Cell membranes contain ion channels. The fraction, \(f\) of channels that are open is a function of the membrane potential \(V\) (the voltage inside the cell mi
View solution Problem 20
Find the value of \(x\) that maximizes \(y=12+18 x-5 x^{2}\) and the corresponding value of \(y,\) by. (a) Estimating the values from a graph of \(y\) (b) Findi
View solution Problem 20
Use the first derivative to find all critical points and use the second derivative to find all inflection points. Use a graph to identify each critical point as
View solution