Problem 20
Question
Prove that \((n+1)^{2}<2 n^{2}\) for all natural numbers \(n \geq 3.\)
Step-by-Step Solution
Verified Answer
The inequality holds for all natural numbers \(n \geq 3\).
1Step 1: Define the Expression
We start by expressing the inequality: \((n+1)^2 < 2n^2\). Expanding the left side gives us: \((n+1)^2 = n^2 + 2n + 1\).
2Step 2: Simplify the Inequality
Rewrite the inequality by substituting the expanded form of \((n+1)^2\) into the original inequality: \[ n^2 + 2n + 1 < 2n^2 \]
3Step 3: Rearrange the Inequality
Move all terms to one side to form an equation: \[ 0 < 2n^2 - n^2 - 2n - 1 \] Simplifying gives: \[ 0 < n^2 - 2n - 1 \]
4Step 4: Analyze the Quadratic Expression
The inequality is now in the form \(n^2 - 2n - 1 > 0\). To solve it, we can find its roots using the quadratic formula \(n = \frac{-b \pm \sqrt{b^2 - 4ac}}{2a}\), where \(a = 1\), \(b = -2\), and \(c = -1\).
5Step 5: Find the Roots of the Quadratic
Calculate the discriminant: \(b^2 - 4ac = (-2)^2 - 4 \cdot 1 \cdot (-1) = 4 + 4 = 8\). So, the roots are: \(n = \frac{2 \pm \sqrt{8}}{2} = \frac{2 \pm 2\sqrt{2}}{2} = 1 \pm \sqrt{2}\).
6Step 6: Determine Validity for Natural Numbers
Since \(1-\sqrt{2}\) is negative and doesn't apply to natural numbers, we consider \(n > 1 + \sqrt{2}\). Since \(\sqrt{2} \approx 1.41\), \(1 + \sqrt{2} \approx 2.41\), meaning \(n\) must be at least 3 for the inequality \(n^2 - 2n - 1 > 0\) to hold true.
Key Concepts
Natural NumbersQuadratic FormulaQuadratic RootsExpanding Expressions
Natural Numbers
Natural numbers are one of the most basic sets of numbers in mathematics. They refer to positive integers starting from 1, extending infinitely. They are typically the numbers we first learn to count with, such as 1, 2, 3, and so on. In mathematical notation, natural numbers are often represented as \( \mathbb{N} \).
- They do not include zero or negative numbers by traditional definition.
- Natural numbers are closed under addition and multiplication, meaning adding or multiplying any two natural numbers returns a natural number.
- They form the basis for more complex mathematical concepts and applications.
Quadratic Formula
The quadratic formula is a crucial mathematical tool used to find the roots of a quadratic equation, which are equations of the form \(ax^2 + bx + c = 0\).
- The formula is represented as \(x = \frac{-b \pm \sqrt{b^2 - 4ac}}{2a}\).
- It derives from the process of completing the square, offering a universal method to solve any quadratic equation.
- The discriminant, \(b^2 - 4ac\), determines the nature of the roots: if the discriminant is positive, there are two distinct real roots; if zero, exactly one real root; and if negative, there are no real roots.
Quadratic Roots
Quadratic roots are the solutions of a quadratic equation, obtained when the equation equals zero. They are specifically the values of \(x\) where \(ax^2 + bx + c = 0\) holds true.
- The roots may be real or complex, depending on the value of the discriminant \(b^2 - 4ac\).
- For real roots, these can be equal or distinct. In the situation of distinct roots, they occupy two points on the x-axis.
- The process of finding roots typically involves factoring, completing the square, or using the quadratic formula.
Expanding Expressions
Expanding expressions is a technique used to simplify or rewrite algebraic terms by distributing multiplication over addition or subtraction.
- It involves applying the distributive property \(a(b + c) = ab + ac\).
- Expansion helps to make complex algebraic expressions more manageable and can reveal patterns and simplifications that are not immediately obvious.
- It is essential in transforming polynomial equations such as \( (n+1)^2 = n^2 + 2n + 1 \).
Other exercises in this chapter
Problem 19
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