Problem 20
Question
One of the two events must occur. If the chance of one is \(2 / 3\) of the other, then odds in favour of the other are (a) \(2: 3\) (b) \(1: 3\) (c) \(3: 1\) (d) \(3: 2\)
Step-by-Step Solution
Verified Answer
The odds in favour of the other event are (d) \(3:2\).
1Step 1: Define the Events
Let's assume two events, Event A and Event B, with their respective probabilities of occurring being \( P(A) \) and \( P(B) \). Since one of the two events must occur, that implies \( P(A) + P(B) = 1 \), because the total probability of all outcomes is always 1.
2Step 2: Establish the Relationship Between Probabilities
We are given that the chance of one event is \( \frac{2}{3} \) of the other. Assume \( P(A) = \frac{2}{3}P(B) \). This gives us a relationship between the probabilities of A and B.
3Step 3: Express All Probabilities in Terms of One Variable
From \( P(A) = \frac{2}{3}P(B) \), substitute \( P(A) = \frac{2}{3}P(B) \) into the equation \( P(A) + P(B) = 1 \):\[ \frac{2}{3}P(B) + P(B) = 1 \]Combine like terms:\[ \frac{5}{3}P(B) = 1 \]
4Step 4: Solve for Probability of Event B
Solve the equation \( \frac{5}{3}P(B) = 1 \):\[ P(B) = \frac{3}{5} \]
5Step 5: Find the Probability of Event A
Now that we have the probability of Event B, find the probability of Event A:\[ P(A) = 1 - P(B) = 1 - \frac{3}{5} = \frac{2}{5} \]
6Step 6: Calculate Odds in Favour of Event B
Odds in favor of Event B are given by \( \frac{P(B)}{P(A)} \), which measures the ratio of the probability of B to the probability of A:\[ \text{Odds in favor of B} = \frac{P(B)}{P(A)} = \frac{\frac{3}{5}}{\frac{2}{5}} = \frac{3}{2} \]
7Step 7: Interpret Odds in Simplest Form
The odds \( \frac{3}{2} \) can be expressed in terms of a ratio, which is \(3:2\).
Key Concepts
Understanding OddsExploring Probability of EventsUnderstanding Conditional Probability
Understanding Odds
Odds are a way to express the likelihood that a certain event will occur as compared to its non-occurrence. They are different from probability, though closely related. Odds are typically expressed in the form of a ratio, such as "3:2," which reads as "three to two." This means that, for every three occurrences of the event in question, there are two non-occurrences.
The concept of odds is widely used in fields like gambling, sports betting, and statistics. Here's how to understand odds in a clearer context:
The concept of odds is widely used in fields like gambling, sports betting, and statistics. Here's how to understand odds in a clearer context:
- If the odds are in favor (e.g., 3:2), it means the event is more likely to happen than not.
- If the odds are against (e.g., 2:3), the event is less likely to happen.
- Odds can be transformed into probabilities using the formula: \( P(E) = \frac{a}{a+b} \), where \(a:b\) are the odds in favor.
Exploring Probability of Events
Probability is the measure of the likelihood that an event will occur. It is calculated by dividing the number of favorable outcomes by the total number of possible outcomes. Probability values range from 0 to 1, where "0" indicates impossibility and "1" indicates certainty.
Whenever you are assessing the probability of an event, encounter some basic principles:
Whenever you are assessing the probability of an event, encounter some basic principles:
- Probability of a certain event: \( P(E) = 1 \).
- Probability of an impossible event: \( P(E) = 0 \).
- The sum of probabilities for all possible outcomes must equal 1.
Understanding Conditional Probability
Conditional probability refers to the likelihood of an event occurring given that another event has already occurred. It is a fundamental concept in probability theory that helps in understanding relationships between events.
Consider this general formula for conditional probability:\[ P(A|B) = \frac{P(A \cap B)}{P(B)} \]This formula reads out as "the probability of event A occurring given that event B has occurred".
Consider this general formula for conditional probability:\[ P(A|B) = \frac{P(A \cap B)}{P(B)} \]This formula reads out as "the probability of event A occurring given that event B has occurred".
- The symbol \(P(A|B)\) is the conditional probability.
- \(P(A \cap B)\) represents the probability that both events A and B occur.
- \(P(B)\) is the prior probability of event B.
Other exercises in this chapter
Problem 18
The probability of getting a number greater than 2 in throwing a die is (a) \(1 / 3\) (b) \(2 / 3\) (c) \(1 / 2\) (d) \(1 / 6\)
View solution Problem 19
Two dice are thrown together. The probability that sum of the two numbers will be a multiple of 4 is (a) \(1 / 9\) (b) \(1 / 3\) (c) \(1 / 4\) (d) \(5 / 9\)
View solution Problem 21
Two dice are thrown. The probability that the sum of numbers appearing is more than 10 is (a) \(1 / 18\) (b) \(1 / 12\) (c) \(1 / 6\) (d) None of these
View solution Problem 22
A coin is tossed twice. The probability of getting head both the times is (a) \(1 / 2\) (b) \(1 / 4\) (c) \(3 / 4\) (d) 1
View solution