Problem 20
Question
Multiply. $$ (x+7)^{2} $$
Step-by-Step Solution
Verified Answer
\((x+7)^2 = x^2 + 14x + 49\).
1Step 1: Identify the Expression to Expand
The expression given is \((x+7)^2\). This is a perfect square trinomial, which can be expanded using the formula \((a+b)^2 = a^2 + 2ab + b^2\). Here, \(a = x\) and \(b = 7\).
2Step 2: Square the First Term
Using the formula \((a+b)^2 = a^2 + 2ab + b^2\), first compute \(a^2\). Since \(a = x\), we have \(a^2 = x^2\).
3Step 3: Compute Twice the Product of the Terms
Next, calculate the middle term, which is \(2ab\). Substituting \(a = x\) and \(b = 7\) into \(2ab\), we get: \(2 \times x \times 7 = 14x\).
4Step 4: Square the Second Term
Finally, compute \(b^2\). Since \(b = 7\), \(b^2 = 7^2 = 49\).
5Step 5: Combine All Terms
Combine the results from Steps 2, 3, and 4: \(x^2 + 14x + 49\). Thus, \((x+7)^2 = x^2 + 14x + 49\).
Key Concepts
Perfect Square TrinomialPolynomial ExpansionAlgebraic Expressions
Perfect Square Trinomial
A perfect square trinomial is a special type of polynomial that you get when you square a binomial expression. Let's break it down with the expression
The result is always a trinomial, having three terms.
It's called "perfect square" because when you expand it, the terms are predictable and fit the formula
- \((x + 7)^2\)
The result is always a trinomial, having three terms.
It's called "perfect square" because when you expand it, the terms are predictable and fit the formula
- \((a+b)^2 = a^2 + 2ab + b^2\)
- The first term \(a^2\) is the square of the first part of the binomial.
- The second term \(2ab\) is twice the product of the two parts.
- The third term \(b^2\) is the square of the last part.
Polynomial Expansion
When you're dealing with polynomial expansion, you're essentially distributing every term of one polynomial by every term of another polynomial.
This is exactly what happens when you expand a perfect square trinomial. Let's look at our exercise's example:
This is exactly what happens when you expand a perfect square trinomial. Let's look at our exercise's example:
- \((x + 7)^2\)
- First, multiply the first term \(x\) with itself: \(x \times x = x^2\)
- Then, multiply the first term \(x\) with the second: \(x \times 7 = 7x\)
- Now do the same but start with the second term: \(7 \times x = 7x\)
- Finally, multiply the second term by itself: \(7 \times 7 = 49\)
- \(x^2 + 7x + 7x + 49\)
- Simplify middle terms: \(x^2 + 14x + 49\)
Algebraic Expressions
Algebraic expressions are combinations of numbers, variables, and operators (such as plus and minus signs). They form the foundation of algebra. Digging into the given expression
Every polynomial, like a trinomial, is made up of these algebraic expressions.
Understanding the parts of the expression is important:
The goal is often to simplify or solve these expressions, leading to their polynomial forms.
- \((x+7)^2\)
Every polynomial, like a trinomial, is made up of these algebraic expressions.
Understanding the parts of the expression is important:
- **Variables** (in this case, \(x\)) represent unknown numbers that can change or move.
- **Constants** (here 7) are fixed numbers that do not change.
- **Operations** are math processes like addition, subtraction that combine or simplify expressions.
The goal is often to simplify or solve these expressions, leading to their polynomial forms.
Other exercises in this chapter
Problem 20
Subtract. $$ \left(-7 y^{2}+5\right)-\left(-8 y^{2}+12\right) $$
View solution Problem 20
Simplify each expression. Write each result using positive exponents only. $$ (-2)^{-6} $$
View solution Problem 20
Evaluate each expression with the given replacement values. $$ \frac{10}{3 y^{3}} \text { when } y=-3 $$
View solution Problem 20
Multiply. \(4 x\left(5 x^{2}-6 x-10\right)\)
View solution